On Dec 12, 2009, at 8:19 PM, casperyc wrote:
for an example,
counts <- c(18,17,15,20,10,20,25,13,12)
outcome <- gl(3,1,9); treatment <- gl(3,3)
glm.D93 <- glm(counts ~ outcome + treatment, family=poisson())
confint(glm.D93)
confint.default(glm.D93) # based on asymptotic normality
to verify
On Dec 12, 2009, at 8:31 PM, Moohwan Kim wrote:
Dear R family
When I run the command below, the error message came up. It seems like
the problem is about computer capacity.
It would be appreciated if anyone could give me a solution.
You would want to just store such an object but also to man
Dear Jorge, Thanks.
But.
(My R console width is set by default at 91, which is fine.
Output for R>1:120 wraps correctly already. )
The problem is that when I am typing a command, it does not wrap like it
does in this email while typing. As I am reach the right border, a
horizontal scroll
Is there an easy way to switch between R GUI and R terminal? I'm currently
using R GUI 2.10.0 on Windows Vista and would like to see something like the
R terminal found in Linux. But I may also want to switch back to GUI. I
don't remember seeing the terminal option at the R download site, or during
Hi Viju,
Here is a suggestion:
R> options(width = 80)
R> 1:120
HTH,
Jorge
On Sat, Dec 12, 2009 at 10:34 PM, Viju Moses <> wrote:
> I'm facing this problem on R GUI version 2.10.0 on Windows Vista. I have
> not
> changed Windows settings or R GUI settings much except to change from MDI
> to
>
I'm facing this problem on R GUI version 2.10.0 on Windows Vista. I have not
changed Windows settings or R GUI settings much except to change from MDI to
SDI.
Someone else reported this problem a few months ago:
https://stat.ethz.ch/pipermail/r-help/2009-April/195714.html
but it wasn't followed
Hi all, i am still using the Hmisc package and I like the filled bands part,
is there a way though to have different groups have different color of
bands, maybe a lighter version of the color of the line that is used?
---
Joe King, M.A.
Ph.D. Student
Dear R family
When I run the command below, the error message came up. It seems like
the problem is about computer capacity.
It would be appreciated if anyone could give me a solution.
###
> N <- 415884
> tau <- diag(1, N)[c(N, 1:(N - 1)),]
Error in array(0, c(n, p)) : 'dim' specifies too
for an example,
counts <- c(18,17,15,20,10,20,25,13,12)
outcome <- gl(3,1,9); treatment <- gl(3,3)
glm.D93 <- glm(counts ~ outcome + treatment, family=poisson())
confint(glm.D93)
confint.default(glm.D93) # based on asymptotic normality
to verify the confidence interval (confint.default(glm.D93
Hi,
I am trying to fit a non-linear model for a parasite dataset. Initially, I
tried log-transforming the data and conducting a 2-way ANCOVA, and found
that the equal variance of populations and normality assumptions were
violated. Gaba et al. (2005) suggests that the Weibull Distribution is be
Dear list,
I am trying to make a contingency table with xtabs but I am getting
a 0 where I expect a 'NA'. Here is a simple example:
options(stringsAsFactors = FALSE)
rn <- LETTERS[1:4]
df1 <- data.frame(r07 = rep(rn, each=4),
r08 = rep(rn, 4), value = 1:16)
xtabs(value ~ r07 +
Farrel Buchinsky wrote:
> It Works! Thanks a lot! Its great.
Thanks for letting me know. Glad that fixed things for you.
>
> What were your "few minor, but important, changes" - in a nutshell. I will
> not understand unless you describe it as high level issues.
Basically, recognizing the type
On Dec 12, 2009, at 6:15 PM, Patrizio Frederic wrote:
hi Michael,
the following code should work
b <- a[match('first',names(a)): match('last',names(a))]
b[is.na(b)]<-0
This might not throw an error:
b <- apply(a[match('first',names(a)): match('last',names(a))], 1:2,
fun
On Sat, 12 Dec 2009, Jorge Ivan Velez wrote:
Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
...which is what I would usually do.
But for heavy duty applications, the IRanges package and function may be
worth study
On Dec 12, 2009, at 5:36 PM, parkbomee wrote:
Hi,
Is it possible to assign to an array with different dimensions?
That is to say, supposing a three dimensional array,
the third dimension of the array has matrices of different sizes?
Use a list. Or populate with NA's
array
, , 1
[1
Yes, thanks. It's exactly what I want.
Annie
On Sat, Dec 12, 2009 at 12:46 PM, Peter Dalgaard
wrote:
> annie Zhang wrote:
>
>> Hi, ALL,
>>
>> Is there any function in R that does the exact test for the matched pair
>> proportions (one sided), which I assume is binomial(b+c, .5).
>>
>
> binom.te
hi Michael,
the following code should work
b <- a[match('first',names(a)): match('last',names(a))]
b[is.na(b)]<-0
a[match('first',names(a)): match('last',names(a))] <- b
cheers,
Patrizio
2009/12/13 Michael Scharkow :
> Dear all,
>
> I'm stuck in a seemingly trivial task that I need to perform f
Dear all,
I'm stuck in a seemingly trivial task that I need to perform for many
datasets. Basically, I want to replace NA with 0 in a specified range of
columns in a dataframe. I know the first and last column to be recoded
only by its name.
I can select the columns starting like this
a[match
Hi,
Is it possible to assign to an array with different dimensions?
That is to say, supposing a three dimensional array,
the third dimension of the array has matrices of different sizes?
> array
, , 1
[1] [2] [3]
[1] 111
, , 2
[1] [2] [3]
[1] 111
[2] 11
Hi Philip,
I must confess that I not understood what is the problem.
Could you clarify it a little bit more?
Cheers
miltinho
brazil=toronto
On Sat, Dec 12, 2009 at 12:39 AM, philip robinson wrote:
>
> I am trying to graphically represent a large set of data who's result is
> not
> strictly un
Also what about
c(seq(1,4,1),seq(10,15,1),seq(20,27,1))
Joe King
j...@joepking.com
"Never throughout history has a man who lived a life of ease left a name
worth remembering." --Theodore Roosevelt
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
See ?mapply and ?do.call for more information.
HTH,
Jorge
On Sat, Dec 12, 2009 at 2:27 PM, Kevin Ummel <> wrote:
> How can I create the following without the 'for' loop?
How can I create the following without the 'for' loop?
start=c(1,10,20)
end=c(4,15,27)
out=c()
for (i in 1:length(start)) {
out=c(out,start[i]:end[i])
}
out
[1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
I know there must be an easier (and, hopefully, faster) way.
Dear R Users,
Do you know whether is there any way of calling STATA from within R
(possibly in a similar way that is possible to call WinBUGS from within R
using the function "Bugs")??
Thanks,
Manuel
--
View this message in context:
http://n4.nabble.com/Call-STATA-code-from-within-R-tp961885p9
*Respected Sir,
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
***I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
On Dec 12, 2009, at 3:38 PM, L.A. wrote:
Thanks for all the help, They all worked, But I'm stuck again.
I've tried searching, but I not sure how to word my search as
nothing came
up.
Here is my new hurdle, my data has 7 abservations and my results
have 2
answers:
Here is my data
saveObject() and loadObject() are using save() and load() in base.
The default is to compress the data when saving, which take some time.
Using saveObject(..., compress=FALSE) is probably faster, but takes
up more disk space. ...and make sure you don't work towards a file
system over a network,
RV> I would be very grateful if you could help me with:
RV> Given the regularized gamma function Reg=int_0^r
RV> (x^(k-1)e^(-x))dx/int_0^Inf (x^(k-1)e^(-x))dx ; 0 (which is eventually the ratio of the Incomplete gamma
RV> function by the gamma function),
and which is exactly what
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of L.A.
> Sent: Saturday, December 12, 2009 12:39 PM
> To: r-help@r-project.org
> Subject: Re: [R] by function ??
>
>
>
> Thanks for all the help, They all worked, But I'm stuck a
Hi,
I had a question regarding the rpart command in R. I used seven continuous
predictor variables in the model and the variable called "TB122" was chosen
for the first split. But in looking at the output, there are 4 variables
that improve the predicted membership equally (TB122, TB139, TB144,
Dear all,
here my problem my be somone can help to solve this.
I have tow timeseries from different stock market with different length
(diff ca. 4000 )
Now I would to add the missing times of the one of this series with proper
time (they are minute data) and set the value to 0 since I need to hav
annie Zhang wrote:
Hi, ALL,
Is there any function in R that does the exact test for the matched pair
proportions (one sided), which I assume is binomial(b+c, .5).
binom.test should fit nicely, I think.
Thanks,
Annie
[[alternative HTML version deleted]]
*
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
*I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
The observation
Thanks for all the help, They all worked, But I'm stuck again.
I've tried searching, but I not sure how to word my search as nothing came
up.
Here is my new hurdle, my data has 7 abservations and my results have 2
answers:
Here is my data
LEAID ratio
3 6307 0.720
1 6307
*Respected Sir,
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
*I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
Th
*
I have a simple question regarding plots of time series in R.
I have to plot "conc" against "time" **for each individual and display in
the same panel for the in-built dataset "Indometh" in R.
*
***I have six time series, say subject1.ts, subject2.ts, .,
subject6.ts.
The observation
Hi, ALL,
Is there any function in R that does the exact test for the matched pair
proportions (one sided), which I assume is binomial(b+c, .5).
Thanks,
Annie
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://st
David Winsemius 12-Dec-09 17:12:
> > txt <- gsub("( [A-Za-z]+),","\\1;",readLines("file.csv"))
> > read.csv(textConnection(txt), header=TRUE)
>var1 var2 var3
> 1 onetwo three
> 2 one this is a comment;with commas. three
Wonderful, tha
On Dec 12, 2009, at 12:01 PM, Marianne Promberger wrote:
Thanks for both replies.
Let me start by giving a better minimal example, although indeed the
regex replacement is not my problem.
system("echo \"var1,var2,var3\none,two,three\none,this is a
comment,with commas.,three\" > file.csv")
Thanks for both replies.
Let me start by giving a better minimal example, although indeed the
regex replacement is not my problem.
system("echo \"var1,var2,var3\none,two,three\none,this is a comment,with
commas.,three\" > file.csv")
> On 12/12/09 11:02, David Winsemius wrote:
> >
> > You ne
On 12/12/09 11:02, David Winsemius wrote:
>
> On Dec 12, 2009, at 7:54 AM, Marianne Promberger wrote:
>
> > Dear list,
> >
> > I have a file that is comma delimited but contains some erroneous
> > non-delimiter commas. I would like to replace these commas with
> > semicolons and then read the cor
On Dec 12, 2009, at 7:54 AM, Marianne Promberger wrote:
Dear list,
I have a file that is comma delimited but contains some erroneous
non-delimiter commas. I would like to replace these commas with
semicolons and then read the correct file into R as a data frame.
I want to do this from within
I am using SWord from statconn: http://rcom.univie.ac.at/download.html
It allows you to put r-commands into Word (similar to odfWeave). Output
is directed to Word including figures and tables. It is still a
beta-version but works fine.
Frank Bloos
>>> Wenjie Lee 12.12.2009 00:28 >>>
Hi R Exper
On Dec 12, 2009, at 9:31 AM, Rodrigo Tsai wrote:
Dear R developers,
is that right?
-27^(1/3)
[1] -3
library(fortunes)
> fortune("^")
Thomas Lumley: The precedence of ^ is higher than that of unary minus.
It may be surprising, [...]
Hervé Pagès: No, it's not surprising. At least to me...
Dear R developers,
is that right?
> -27^(1/3)
[1] -3
> c(-27,27)^(1/3)
[1] NaN 3
i'm using sign( c(-27,27) ) * abs( c(-27,27)) ^(1/3) ,
thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/m
Dear list,
I have a file that is comma delimited but contains some erroneous
non-delimiter commas. I would like to replace these commas with
semicolons and then read the correct file into R as a data frame.
I want to do this from within R, without changing the original data
file.
My current idea
> Datum: Fri, 11 Dec 2009 21:52:30 -0500
>
> On Dec 11, 2009, at 11:08 AM, Tom Knockinger wrote:
>
> > Hi,
> > i am new to the R-project but until now i have found solutions for
> > every problem in toturials, R Wikis and this mailing list, but now i
> > have some problems which I can't solve
On Fri, 11 Dec 2009, Xiongqing Zhang wrote:
Hello all, I am Xiongqing Zhang, come from Beijing of China. I know you from
the web site: http://finzi.psych.upenn.edu/Rhelp08/2008-February/154627.html.
I am not very clear about the R-project software.
Look at
http://www.R-project.org/
especia
Thank you very much!
Eleni
On Fri, Dec 11, 2009 at 7:19 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi Eleni,
>
> On Dec 11, 2009, at 12:04 PM, Eleni Christodoulou wrote:
>
> > Dear R users,
> >
> > I am trying to apply SVM regression for a set of microarray data. I am
> usin
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