How can I create the following without the 'for' loop?
start=c(1,10,20)
end=c(4,15,27)
out=c()
for (i in 1:length(start)) {
out=c(out,start[i]:end[i])
}
out
[1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
I know there must be an easier (and, hopefully, faster) way.
Many thanks in advance,
Kevin Ummel
Central European University
Department of Environmental Science and Policy
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