On Sat, 12 Dec 2009, Jorge Ivan Velez wrote:
Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
...which is what I would usually do.
But for heavy duty applications, the IRanges package and function may be
worth studying:
require(IRanges) # from bioConductor.org
as.vector( IRanges( start, end ) )
[1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
An introduction to the package is at
http://bioconductor.org/packages/2.5/bioc/vignettes/IRanges/inst/doc/IRangesOverview.pdf
HTH,
Chuck
See ?mapply and ?do.call for more information.
HTH,
Jorge
On Sat, Dec 12, 2009 at 2:27 PM, Kevin Ummel <> wrote:
How can I create the following without the 'for' loop?
start=c(1,10,20)
end=c(4,15,27)
out=c()
for (i in 1:length(start)) {
out=c(out,start[i]:end[i])
}
out
[1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
I know there must be an easier (and, hopefully, faster) way.
Many thanks in advance,
Kevin Ummel
Central European University
Department of Environmental Science and Policy
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Charles C. Berry (858) 534-2098
Dept of Family/Preventive Medicine
E mailto:cbe...@tajo.ucsd.edu UC San Diego
http://famprevmed.ucsd.edu/faculty/cberry/ La Jolla, San Diego 92093-0901
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