Hi Kevin,
Here is a suggestion using mapply():
start <- c(1,10,20)
end <- c(4,15,27)
do.call(c, mapply( seq, start, end))
See ?mapply and ?do.call for more information.
HTH,
Jorge
On Sat, Dec 12, 2009 at 2:27 PM, Kevin Ummel <> wrote:
> How can I create the following without the 'for' loop?
>
> start=c(1,10,20)
>
> end=c(4,15,27)
>
> out=c()
>
> for (i in 1:length(start)) {
> out=c(out,start[i]:end[i])
> }
> out
> [1] 1 2 3 4 10 11 12 13 14 15 20 21 22 23 24 25 26 27
>
> I know there must be an easier (and, hopefully, faster) way.
>
> Many thanks in advance,
> Kevin Ummel
>
> Central European University
> Department of Environmental Science and Policy
>
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