On Dec 12, 2009, at 3:38 PM, L.A. wrote:
Thanks for all the help, They all worked, But I'm stuck again.
I've tried searching, but I not sure how to word my search as
nothing came
up.
Here is my new hurdle, my data has 7 abservations and my results
have 2
answers:
Here is my data
LEAID ratio
3 6307 0.7200000
1 6307 0.7623810
2 6307 0.8600000
4 6307 0.9200000
5 8300 0.5678462
7 8300 0.7700000
6 8300 0.8300000
median<-summaryBy(ratio ~ LEAID, data = Dataset, FUN = median)
print(median)
LEAID ratio.median
1 6307 0.8111905
2 8300 0.7700000
Now what I want is a way to compute
abs(ratio- median)by LEAID for each observation to produce something
like
this
?ave # creates a vector of length = length of original data.frame
abs( ave(dtst$ratio, dtst$LEAID, FUN=median)-dtst$ratio)
[1] 0.0911905 0.0488095 0.0488095 0.1088095 0.2021538 0.0000000
0.0600000
LEAID ratio abs
3 6307 0.7200000 .0912
1 6307 0.7623810 .0488
2 6307 0.8600000 .0488
4 6307 0.9200000 .1088
5 8300 0.5678462 .2022
7 8300 0.7700000 .0000
6 8300 0.8300000 .0600
Thanks,
L.A.
Ista Zahn wrote:
Hi,
I think you want
by(TestData[ , "RATIO"], LEAID, median)
-Ista
On Tue, Dec 8, 2009 at 8:36 PM, L.A. <ro...@millect.com> wrote:
I'm just learning and this is probably very simple, but I'm stuck.
I'm trying to understand the by().
This works.
by(TestData, LEAID, summary)
But, This doesn't.
by(TestData, LEAID, median(RATIO))
ERROR: could not find function "FUN"
HELP!
Thanks,
LA
--
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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