Greetings R-help community,
I am relatively new to R, which may be why I am having trouble
understanding this problem. I want to know the differences between
vector and array. could someone tell me something about this question.
Thanks in advance,
__
R
Marc Schwartz wrote:
On Aug 3, 2009, at 12:06 AM, Thomas Mang wrote:
Hi,
Suppose a binomial GLM with both continuous as well as categorical
predictors (sometimes referred to as GLM-ANCOVA, if I remember
correctly). For the categorical predictors = indicator variables, is
then there a sugges
Hi
I have a data frame like this:
V1V2 V3 V4
Min. :0.01146 Min. :0.0006714 Min. :0.004912 Min. : 0
1st Qu.:0.03938 1st Qu.:0.0072805 1st Qu.:0.052719 1st Qu.:1150
Median :0.04224 Median :0.0077581 Median :0.056388
Here's what I came up with:
> gsub("(\\w)[^ ]+[\\b ]", "\\1", astr)
[1] "Timtowtdit"
You might be interested in Regular Expressions Cookbook from O'Reilly
(publisher not author) or http://www.regular-expressions.info/
I usually bumble along knowing there are better ways to do whatever I am doing
Dear R members,
I would like to know if there is a stepwise function that gives LRT value
instaed of AIC?
thanks in advance,
Luciana Pozzi
CENPAT-CONICET
Argentina
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https:
time <- seq(0,72,12)
betagal.abs <- c(0.05,0.18,0.25,0.31,0.32,0.34,0.35)
cell.density <- c(0,1000,2000,3000,4000,5000,6000)
#add extra space to right margin of plot within frame par(mar=c(5, 4, 4, 4) +
0.1)
# Plot first set of data and draw its axis
plot(time, betagal.abs, pch=16, axes=F, yli
I've completed an experiment and want to summarize the results.
There are two things I like to create.
1) A simple count of things from the data.frame with predictions
1a) Number of predictions with probability greater than x
1b) Number of predictions with probability greater than x that
HI
am plotting different density plots in one graph each with a different
color.
And i want to add labels to plot mentioning which color belongs to which
data series.
p2 <- qplot(corArms, data = data1, geom = "density", adjust=0.4, main="Arms
Correlation All") +
layer(data=data2, geom="densi
Hi, the problem has been solved by using "lmer" rather than the "lme"
function. It seems the "lme" function dislike my large data size. "lmer"
function deals with large data size much better. Thanks for the replies
above.
Harry
On Tue, Aug 4, 2009 at 7:11 PM, David Winsemius wrote:
>
> On Aug
Very nice. Two questions:
1> Do you have any idea of the timing difference, if any, between this and
the vector-subscripting method?
2> How do you generalize this to select multiple rows eg with indexes given
by a vector 'v'?
Søren Højsgaard wrote:
>
> You can do
>> A <- HairEyeColor
>> do.ca
On Aug 4, 2009, at 9:06 PM, Hongwei Dong wrote:
> Thanks, David, you are right. If I use continuous data such as 1,
> 2, ...6 to represent those 6 housing types, the model works with the
> lme function in R. The problem is, the relationship between the 6
> housing types are not continuous,
Ram,
Did my email from earlier today not help?
http://article.gmane.org/gmane.comp.lang.r.general/158431
-steve
On Aug 4, 2009, at 6:22 PM, ram basnet wrote:
Dear R users,
I am new user for elastic net. I am trying to use elasticnet
library.
I have marker data with 359 markers and 168
sa
Dear, R help
How can I generate random numbers of the multivariate power exponential
distribution.
Regards,
Jeremias Leão.
[[elided Yahoo spam]]
[[alternative HTML version deleted]]
_
Let me rephrase. You have some counts. You have some other measurement or
measurements. Presumably you are trying to predict (fit) expected count in
terms of the measurements. Can you identify which variable is the count and
how your model describes the expected count?
Glen
glen_b wrote:
>
>
Hang on, now I'm very confused. What is the information you have collected?
Is it x and y? k and x? which one is the count?
John Sanders-2 wrote:
>
> The function I'm trying to fit has the form:
>
> P(k)
> ~ k^(-y) exp (– k ⁄ kx)
>
> And deals with count data. I'm a newbie, so any more spe
In addition, it seems the lme function in R are very troubled with the dummy
variables used at the first (random) level.
Harry
On Tue, Aug 4, 2009 at 6:06 PM, Hongwei Dong wrote:
> Thanks, David, you are right. If I use continuous data such as 1, 2, ...6
> to represent those 6 housing types, th
Thanks, David, you are right. If I use continuous data such as 1, 2, ...6 to
represent those 6 housing types, the model works with the lme function in R.
The problem is, the relationship between the 6 housing types are not
continuous, which we assume when we use 1,2,..6 to represent them.
Harry
O
On Aug 4, 2009, at 8:47 PM, David Winsemius wrote:
On Aug 4, 2009, at 7:48 PM, Hongwei Dong wrote:
Yeah, I have a very large sample size, about 60,000 observations.
Multicollinearity should not be a problem here. The weird thing is
that SPSS
can converge very quickly and gives out reasona
On Aug 4, 2009, at 7:48 PM, Hongwei Dong wrote:
Yeah, I have a very large sample size, about 60,000 observations.
Multicollinearity should not be a problem here. The weird thing is
that SPSS
can converge very quickly and gives out reasonable results.
The only problem I can think of is that,
Dear R-listers,
I am now asking for step by step tutorial to beginning of R programming by
Emacs+ESS on MS Windows. Though it was appreciated highly, there is much
troubles we must conquered before we set up R programming by Emacs+ESS,
especially for users of MS Windows and who without extensive
Ravi,
Here is a third way to do this, but it doesn't make use of regular expressions
per se:
> avec <- unlist(strsplit(astr, "")) # First convert astr to a vector
> avec[c(1, 1 + grep(" ", avec))]
[1] "T" "i" "m" "t" "o" "w" "t" "d" "i"
This latter expression subscripts avec by concatenating t
> Nice, but I need a few columns for the data. Don't know how to do this with
> the method you suggest.
For each iteration, you make a vector of your 'data', in the example
it is a vector of length 3.
Each of the elements in this vector will become a column in the dataframe.
If that is not what
Hi,
Nice, but I need a few columns for the data. Don't know how to do this
with the method you suggest.
-N
On 8/4/09 4:57 PM, Remko Duursma wrote:
Hi Noah,
there are a few ways to do this. Easiest is to keep adding an element
to a list, and then make it into a dataframe at the end, like th
Hi Noah,
there are a few ways to do this. Easiest is to keep adding an element
to a list, and then make it into a dataframe at the end, like this:
resultlis <- list()
for(i in 1:10){
# your calculations here
datavec <- runif(3)
resultlis[[i]] <- datavec
}
resultdfr <- as.data.frame(do.call("rb
Yeah, I have a very large sample size, about 60,000 observations.
Multicollinearity should not be a problem here. The weird thing is that SPSS
can converge very quickly and gives out reasonable results.
The only problem I can think of is that, my first level (random) variables
are dummy variables:
Hi,
Time for another of my "newbie" questions.
Is it possible to build up a data.frame "row by row" as I go
I'm going to be running a bunch of experiments (many in a loop) to test
different things. I'm using AUC as my main performance measure.
My thought was to add a row to a data.frame for
LOL,
I'll happily support that. Can we possibly take my name off of it? :)
-N
On 8/4/09 4:31 PM, Rolf Turner wrote:
On 5/08/2009, at 11:10 AM, Greg Snow wrote:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Noah Silverma
On 5/08/2009, at 11:10 AM, Greg Snow wrote:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Noah Silverman
Sent: Monday, August 03, 2009 12:26 AM
To: r help
Subject: [R] Scale set of 0 values returns NAN??
[snip]
Using R is
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Noah Silverman
> Sent: Monday, August 03, 2009 12:26 AM
> To: r help
> Subject: [R] Scale set of 0 values returns NAN??
[snip]
> Using R is forcing me
> to take a much deeper l
Thanks David,
My apologies for the HTML e-mail. Its the default of my desktop client.
-N
On 8/4/09 4:03 PM, David Winsemius wrote:
On Aug 4, 2009, at 6:52 PM, Noah Silverman wrote:
Hmmm.. I'll try that.
I recall reading somewhere that the "group" variable had to be
indicated in a specia
On Aug 4, 2009, at 6:52 PM, Noah Silverman wrote:
Hmmm.. I'll try that.
I recall reading somewhere that the "group" variable had to be
indicated in a special way.
I use lrm and cph all the time ... thank you, Frank Harrell and I
can assure you that a factor variable or one that h
Hmmm.. I'll try that.
I recall reading somewhere that the "group" variable had to be indicated
in a special way.
-N
On 8/4/09 3:49 PM, David Winsemius wrote:
>
> On Aug 4, 2009, at 6:45 PM, Noah Silverman wrote:
>
>> I guess I didn't explain it well enough.
>>
>> I have a number of training ex
Hi there,
It may not be so ellegant, but you can try:
PrsnData<-data.frame(cbind(PrsnSerialno,PrsnAge,IsHead))
PrsnData.subset<-subset(PrsnData, PrsnSerialno %in% HhSerialno)
PrsnData.subset
PrsnData.subset.maxage<-aggregate(PrsnData.subset["PrsnAge"],
list(PrsnData.subset$PrsnSerialno), max)
Pr
On Aug 4, 2009, at 6:45 PM, Noah Silverman wrote:
> I guess I didn't explain it well enough.
>
> I have a number of training examples. They have 4 fields.
> label, v1, v2, group
>
> The label is binary ("yes", "no")
>
> My understanding (Quite possible wrong.) was that there was a way
> to tr
I guess I didn't explain it well enough.
I have a number of training examples. They have 4 fields.
label, v1, v2, group
The label is binary ("yes", "no")
My understanding (Quite possible wrong.) was that there was a way to
train the LR to estimate probabilities "per group"
In pseudo-code it
On Aug 4, 2009, at 6:38 PM, Noah Silverman wrote:
> Thanks David,
>
> But HOW do I indicate the "grouping" variable in the formula?
Hard to tell. You have told us absolutely nothing about the problem.
Discrete variables cause no problems in formulas. Perhaps one of :
?factor
?cut
?quantile
>
Thanks David,
But HOW do I indicate the "grouping" variable in the formula?
Thanks!
-N
On 8/4/09 3:37 PM, David Winsemius wrote:
>
> On Aug 4, 2009, at 6:33 PM, Noah Silverman wrote:
>
>> Hi,
>>
>> Trying to setup a logistic regression model. (Something new to me. I
>> usually use SVM.)
>>
>>
On Aug 4, 2009, at 6:33 PM, Noah Silverman wrote:
Hi,
Trying to setup a logistic regression model. (Something new to me. I
usually use SVM.)
The person explaining the concept explained to me that I can include a
"group" variable so that the probabilities predicted by the model will
be "per g
Hi,
Trying to setup a logistic regression model. (Something new to me. I
usually use SVM.)
The person explaining the concept explained to me that I can include a
"group" variable so that the probabilities predicted by the model will
be "per group"
Does this make sense to anyone? If so, how
Dear R users,
I am new user for elastic net. I am trying to use elasticnet
library.
I have marker data with 359 markers and 168
samples, and response is metabolites. I am trying to do regression between
a metabolite and markers.
But i am getting the following error:
>
en<-enet(marker
On Aug 4, 2009, at 11:16 AM, Rnewbie wrote:
dear all,
I got a problem with pattern matching using grep. I extracted a list
of
characters from a data frame, and I tried to match this list of
characters
to a column from another data frame. In return, I got only one
match, but
there shoul
The magic I was looking for is to pass "as.is=TRUE" to "sqlQuery" of
RODBC.
The reference to "read.table" is a little oblique, but with that, all
works fine.
An education!
:-)
Thanks much,
Jan
On Tue, 04 Aug 2009 09:05:05 +0200, "Peter Dalgaard"
said:
> Jan Theodore Galkowski wrote:
> >
I would use sshfs or an alternatively remote file system access. Ssh
to your Linux box and then mount the mac os x filesystem via sshfs, or
afs for example. Alternatively, can't you copy the data to the Linux
box using sftp first?
--
Dr. Mark Wardle
Specialist registrar, Neurology
(Sent fro
R-help,
I get the following error message when trying to connect to an Oracle
database
through R (2.8.1) under Linux (Ubuntu 9.04).
> channel<-odbcConnect("magnus",uid="luisr",pwd="juanayzakarias")
Warning messages:
1: In odbcDriverConnect(st, ...) :
[RODBC] ERROR: state IM002, code 0, message
R-help,
I get the following error message when trying to connect to an Oracle database
through R (2.8.1) under Linux (Ubuntu 9.04).
> channel<-odbcConnect("magnus",uid="luisr",pwd="juanayzakarias")
Warning messages:
1: In odbcDriverConnect(st, ...) :
[RODBC] ERROR: state IM002, code 0, message
dear all,
I got a problem with pattern matching using grep. I extracted a list of
characters from a data frame, and I tried to match this list of characters
to a column from another data frame. In return, I got only one match, but
there should be far more matches. Any ideas what has gone wrong?
Hi Sir
How to get Wakeby distribution curve on L-moment ratio diagram?
Regards
--
AMINA SHAHZADI
Department of Statistics
GC University Lahore, Pakistan.
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https://stat.e
Please consider the following inputs:
PrsnSerialno<-c(735,1147,2019,4131,4131,4217,4629,4822,4822,5979,5979,6128,6128,7004,7004,
7004,7004,7004,7438,7438,9402,9402,9402,10115,10115,11605,12693,12693,12693)
PrsnAge<-c(59,48,42,24,24,89,60,43,47,57,56,76,76,66,70,14,7,3,62,62,30,10,7,20,21,50,53,44
Hi,
On Aug 3, 2009, at 10:37 PM, Weiwei Shi wrote:
Hi
I am wondering if R or some others provide free-to-use graph mining
tools,
like mining some frequent structure in a x-y plot data?
It sounds like you're looking for a library does frequent subgraph
mining across a graph dataset. I'm
Is there a place that shows how to create two plots that are stacked on top of
each other where they share a common x-axis scale, but have differnt y-axis
scale?
Say have the following data: airquality
Stack plot(airquality$Day, airquality$Wind) on top of plot(airquality$Day,
airquality$Temp).
Hi Steve,
I had the same problem when writing the hierobarp function in plotrix.
Have a look at the source code (v2.6-4 in my copy lines 128-133) as the
solution seems to work well.
Jim
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailm
That is exactly what I needed! I dunno why I did not think about it
earlier duuhhh!!!
thanks very much!!!
sapply(modelos, AIC) did the job!
more specifically, (I wanted a dataframe to make comparaisons easy)
k=as.data.frame(sapply(modelos,AIC))
df_results=cbind(k,modelo=rownames(k))
So,
Thanks. This seems to mirror the output *both* to the console *and* to the
sink file. The error messages, on the other hand, show up only in the
console.
On Tue, Aug 4, 2009 at 3:24 PM, Allan Engelhardt wrote:
> sink(..., type=c("output","message"), split=TRUE) at the beginning of your
> session
correction -- that would work for a single row, if you want the result to be
an array with one fewer dimensions. But in general you get an array of the
same dimension you started with (where the first dimension may be length 1).
So:
dim(slice) <- c(length(v), dim(arr)[-1])
Although you *do* hav
You can do
> A <- HairEyeColor
> do.call("[", c(list(A),list(1,T,T)))
Sex
Eye Male Female
Brown 32 36
Blue11 9
Hazel 10 5
Green3 2
Regards
Søren
Fra: r-help-boun...@r-project.org [r-help-boun...@r-project.
Although you *do* have to re-assign the dimensions, otherwise the result is
just a flat vector, ie
slice <- A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
dim(slice) <- dim(A)[-1]
Steve Jaffe wrote:
>
> A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
>
--
View this message i
On Tue, Aug 4, 2009 at 11:37 AM, Vitalie S. wrote:
> Dear UseRs,
>
> I declared a `$` method for a S4 class. Can I have ab automatic completion
> for this operator in R? Lists and environment objects provide this feature
> by default, but my object is an extension of "function" class which does not
Yes, I was thinking more in terms of mental operations than physical.
I think the following works, but it doesn't seem entirely transparent :-)
Given array A, and a vector of row indices v (ie 1 <= v <= dim(A)[1]), the
slice of rows v is
A[ outer(v, dim(A)[1]*( 1:prod(dim(A)[-1])-1 ), '+') ]
Will take a look when back from holidays in 2 weeks.
Uwe
David Winsemius wrote:
Not sure you can call it a bug when the help page says for angles in
range (180, 360) that some support functions may "not work properly".
On Aug 3, 2009, at 2:12 PM, Vivek Ayer wrote:
Hey guys,
Not sure if
Hi,
On Aug 4, 2009, at 3:23 PM, Steve Jaffe wrote:
Suppose I have an n-diml array A and I want to extract the first
"row" -- ie
all elements A[1, ...]
Interactively if I know 'n' I can write A[1,] with (n-1) commas.
How do I do the same more generally, eg in a script?
(I can think of
sink(..., type=c("output","message"), split=TRUE) at the beginning of
your session should do it?
Jacob Wegelin wrote:
Consider all the text that one sees on the console during an R session.
Is there a way, within R, to make all this text--both the "output" and
the "messages"--automatically g
Suppose I have an n-diml array A and I want to extract the first "row" -- ie
all elements A[1, ...]
Interactively if I know 'n' I can write A[1,] with (n-1) commas.
How do I do the same more generally, eg in a script?
(I can think of doing this by converting A to a vector then extracting t
Hi all,
On October 19, I'll be offering a one data ggplot2 course in
conjunction with the ISMI Manufacturing Week. The course is open to
all and you can attend in person (Austin TX) or over the web. More
information available from http://lookingatdata.com/ismi-2009/
Regards,
Hadley
--
http://
I hadn't thought of that. I'll run some tests...
-N
On 8/4/09 11:49 AM, Tobias Sing wrote:
>> Is the "probability of the true label" the best prediction to feed to
>> the ROCR package, or is it better to use the "decision.value"
>>
> Since AFAIK they are related by a monotonous transforma
> Is the "probability of the true label" the best prediction to feed to
> the ROCR package, or is it better to use the "decision.value"
Since AFAIK they are related by a monotonous transformation, both
approaches should lead to the same ROC curve, shouldn't they? (not
tested)
On Tue, Aug 4, 2009
Dear UseRs,
I declared a `$` method for a S4 class. Can I have ab automatic completion
for this operator in R? Lists and environment objects provide this feature
by default, but my object is an extension of "function" class which does
not have subseting defined. How to be?
Thanks for any
Hello,
since a couple of days I'm trying hard to elicit a certain thing
out of the Sweave function of R. Unfortunately I'm quite unsuccessful.
It's only about a small, ridiculous minus sign, which does not appear
in the final pdf of a latex file, if I try to incorporate the Computer-
Modern fonts
On Aug 4, 2009, at 2:04 PM, Jim Bouldin wrote:
I admit that I've not done a thorough search on this topic, but from
the
several instructional manuals and/or tutorials I've looked at, I
don't see
any mention of relational database capabilities in R? Have I missed
something, and if so, c
Good point. I'm not sure how I missed that.
This does lead to an additional question:
Is the "probability of the true label" the best prediction to feed to
the ROCR package, or is it better to use the "decision.value"
Anybody have any experience on this one?
Thanks!
-N
On 8/4/09 3:28 AM, Ch
Dear R Users
I'm writing my first simulation in R.
I've put across my problems with a smaller example in the attachment along
with the questions.
Please help.
Best regards
Meenu
mydat<-read.table(textConnection("Level spread change State
4.57 1.6 BlF NA
4.45 2.04 BrS NA
3.07 2.49 BlS NA
3.26 -0
Hi,
Did your search include this :
R> RSiteSearch( "database" )
Romain
On 08/04/2009 08:04 PM, Jim Bouldin wrote:
I admit that I've not done a thorough search on this topic, but from the
several instructional manuals and/or tutorials I've looked at, I don't see
any mention of relational data
I admit that I've not done a thorough search on this topic, but from the
several instructional manuals and/or tutorials I've looked at, I don't see
any mention of relational database capabilities in R? Have I missed
something, and if so, can someone point me in the right direction to get
started
Thanks Barry and Steve,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
Probably works with ftp: too. How remote is it?
In fact it is a bit more complicated.
I am working on a Mac machine,
And here is a second way:
> strapply(astr, "(\\w)\\w+", c, simplify = c)
[1] "T" "i" "m" "t" "o" "w" "t" "d" "i" "i" "t" "f" "f" "T"
On Tue, Aug 4, 2009 at 1:42 PM, Gabor
Grothendieck wrote:
> Try this:
>
>> library(gsubfn)
>> strapply(astr, "\\w+", ~ substr(x, 1, 1), simplify = c)
> [1] "T" "
Try this:
> library(gsubfn)
> strapply(astr, "\\w+", ~ substr(x, 1, 1), simplify = c)
[1] "T" "i" "m" "t" "o" "w" "t" "d" "i" "i" "t" "f" "f" "T"
On Tue, Aug 4, 2009 at 1:28 PM, ravi wrote:
>
> Hi,
> I am getting stuck over an apparently simple problem in the use of regular
> expressions :
> T
On 4 Aug 2009, at 18:27, David Winsemius wrote:
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word "less" with the
word English "fewer". Many native speak
On 4 Aug 2009, at 18:27, David Winsemius wrote:
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word "less" with the
word English "fewer". Many native speak
Hi,
I am getting stuck over an apparently simple problem in the use of regular
expressions :
To collect together the first letters of the words from the Perl motto, “There
is more than one way to do it” in the following form – TIMTOWTDI.
I tried the following code :
# A regex problem with
Your first posting made me think that you were complaining that the
fitted values were less than the raw values. Your second posting makes
me think that you may be conflating the English word "less" with the
word English "fewer". Many native speakers make the same error, but in
this contex
I write about R every weekday at the Revolutions blog:
http://blog.revolution-computing.com
In case you missed them, here are some articles from last month of
particular interest to R users.
http://bit.ly/2HPlOe announced a directory of R user groups available
on the Revolutions blog.
http://bit
Hi,
I've done a more complete response in my blog. http://tr.im/vshK
Romain
On 08/04/2009 06:10 PM, Romain Francois wrote:
Hi,
So the file you want to read is on the client machine, and you want to
transfer it to the server and read it into R ?
What I guess you need is :
- open a FileInput
Hi,
On Aug 4, 2009, at 1:03 PM, ram basnet wrote:
Dear R users,
I am new user for elastic net. I am trying to use elasticnet library.
I have marker data with 359 markers and 168 samples, and response is
metabolites. I am trying to do regression between a metabolite and
markers.
But i am
Deducer 0.1 has been released to CRAN
Deducer is designed to be a free, easy to use, alternative to proprietary
software such as SPSS, JMP, and Minitab. It has a menu system to do common
data manipulation and data analysis tasks, and an excel-like spreadsheet in
which to view and edit data frames.
Dear R users,
I am new user for elastic net. I am trying to use elasticnet library.
I have marker data with 359 markers and 168 samples, and response is
metabolites. I am trying to do regression between a metabolite and markers.
But i am getting the following error:
> en<-enet(marker,as.numer
Actually, I tried doing
data2 = unique(data)
mod = lm(y ~ x1 + ... + xn, data2)
fitted(mod)
and I still get les fitted values than observations.
Federico
On 4 Aug 2009, at 12:18, Federico Calboli wrote:
Hi All,
I have some data where the dependent variable is a score, low (1:3) or
high (8:
Hi,
So the file you want to read is on the client machine, and you want to
transfer it to the server and read it into R ?
What I guess you need is :
- open a FileInputStream, many many tutorials on the web will tell you
how this works.
- open a RFileOutputStream
- call the read(byte[] b) met
On Tue, Aug 4, 2009 at 3:37 PM, Olga Lyashevska wrote:
> Dear all,
>
> I am trying to import data with read.csv and my file is on remote machine.
> I believe that I need to open a connection, not sure about syntax though.
If it's on an HTTP server then you don't need to faff with
connections, jus
On Tue, Aug 4, 2009 at 4:20 PM, Hyo Karen Lee wrote:
> I am currently working on some research which involves huge amounts
> of data(it is about 15GB).
One point nobody has seemed to make yet is that the above statement
is meaningless...
Do you have a CSV file that is 15GB big? The important n
> Does anyone know if there is a function like survdiff which can also handle
> left-truncated and right-censored data? When I use it on left-truncated and
> right-censored data I get an error message saying Right censored data only.
coxph(Surv(time1, time2, status) ~ factor(group), data=mydata)
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Hyo Karen Lee
> Sent: Tuesday, August 04, 2009 8:21 AM
> To: r-help@r-project.org
> Subject: [R] One critical question in R
>
> Hi,
> I have one critical question in using R.
> I
On Tue, 4 Aug 2009, Tom La Bone wrote:
My concern is that the two tests give different DW statistics for the
weighted fit and very different p-values for the same DW statistic for the
unweighted fit. Is there a "right" answer here?
dwtest() is not handling WLS at the moment. I'll have a look w
Hi,
On Aug 4, 2009, at 11:20 AM, Hyo Karen Lee wrote:
Hi,
I have one critical question in using R.
I am currently working on some research which involves huge amounts
of data(it is about 15GB).
I am trying to use R in this research rather than using SAS or STATA.
(The company where I am working
Dear all,
I am attempting to convert 10 NetCDF files into a single NetCDF file, due to
the data input requirements of a model I hope to use. I am using the ncdf
package, version 1.6. The data are global-scale water values, on a monthly
basis for 10 years (ie. 120 months of data in total; at pr
Hi,
I have one critical question in using R.
I am currently working on some research which involves huge amounts
of data(it is about 15GB).
I am trying to use R in this research rather than using SAS or STATA.
(The company where I am working right now, is trying to switch SAS/STATA to
R)
As far as
Hi,
On Aug 4, 2009, at 10:37 AM, Olga Lyashevska wrote:
Dear all,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
I would appreciate any suggestions,
Look at the different ways you can
Dear all,
I am trying to import data with read.csv and my file is on remote
machine.
I believe that I need to open a connection, not sure about syntax
though.
I would appreciate any suggestions,
Thanks!
Olga
__
R-help@r-project.org mailing list
Thanks to Hadley (shortest and sweetest), Eric and Gabor.
I was _so_ close.
Now I think I've learned some things about the reshape function and package!
(Also transform and interaction.)
Thanks to you all,
-- David
-Original Message-
From: hadley wickham [mailto:h.wick...@gmail.com]
Sent
My concern is that the two tests give different DW statistics for the
weighted fit and very different p-values for the same DW statistic for the
unweighted fit. Is there a "right" answer here?
--
View this message in context:
http://www.nabble.com/Comparison-of-Output-from-%22dwtest%22-and-
I have a piece of code as the one at the bottom, unfortunately since it
involves time series from a db it's not easy to give to mailing list a working
script.
It becomes very slow after few hundred iterations over variable sp (must
process several thousands).
The Rprof() indicates that the probl
Hello,
I have a package that builds fine using R CMD build pkg --no-vignette,
but I get the following error when running R CMD build pkg:
** building package indices ...
Error in setwd(OutVignetteDir) : cannot change working directory
ERROR: installing package indices failed
I don't know why it
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