Hi Noah, there are a few ways to do this. Easiest is to keep adding an element to a list, and then make it into a dataframe at the end, like this:
resultlis <- list() for(i in 1:10){ # your calculations here datavec <- runif(3) resultlis[[i]] <- datavec } resultdfr <- as.data.frame(do.call("rbind", resultlis)) greetings, Remko ------------------------------------------------- Remko Duursma Post-Doctoral Fellow Centre for Plants and the Environment University of Western Sydney Hawkesbury Campus Richmond NSW 2753 Dept of Biological Science Macquarie University North Ryde NSW 2109 Australia Mobile: +61 (0)422 096908 www.remkoduursma.com On Wed, Aug 5, 2009 at 9:41 AM, Noah Silverman<n...@smartmediacorp.com> wrote: > Hi, > > Time for another of my "newbie" questions. > > Is it possible to build up a data.frame "row by row" as I go > > I'm going to be running a bunch of experiments (many in a loop) to test > different things. I'm using AUC as my main performance measure. > > My thought was to add a row to a data.frame for each iteration and then have > a nice summary report at the end. > > I found how to import, export, and create from vectors. I haven't been able > to find how just make an empty one and add rows as I go. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.