jainankitk commented on code in PR #14439:
URL: https://github.com/apache/lucene/pull/14439#discussion_r2054906523


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lucene/sandbox/src/java/org/apache/lucene/sandbox/facet/plain/histograms/PointTreeBulkCollector.java:
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@@ -0,0 +1,227 @@
+/*
+ * Licensed to the Apache Software Foundation (ASF) under one or more
+ * contributor license agreements.  See the NOTICE file distributed with
+ * this work for additional information regarding copyright ownership.
+ * The ASF licenses this file to You under the Apache License, Version 2.0
+ * (the "License"); you may not use this file except in compliance with
+ * the License.  You may obtain a copy of the License at
+ *
+ *     http://www.apache.org/licenses/LICENSE-2.0
+ *
+ * Unless required by applicable law or agreed to in writing, software
+ * distributed under the License is distributed on an "AS IS" BASIS,
+ * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+ * See the License for the specific language governing permissions and
+ * limitations under the License.
+ */
+package org.apache.lucene.sandbox.facet.plain.histograms;
+
+import static org.apache.lucene.search.DocIdSetIterator.NO_MORE_DOCS;
+
+import java.io.IOException;
+import java.util.function.Function;
+import org.apache.lucene.index.PointValues;
+import org.apache.lucene.internal.hppc.LongIntHashMap;
+import org.apache.lucene.search.DocIdSetIterator;
+import org.apache.lucene.util.NumericUtils;
+
+class PointTreeBulkCollector {
+  private static Function<byte[], Long> bytesToLong(int numBytes) {
+    if (numBytes == Long.BYTES) {
+      // Used by LongPoint, DoublePoint
+      return a -> NumericUtils.sortableBytesToLong(a, 0);
+    } else if (numBytes == Integer.BYTES) {
+      // Used by IntPoint, FloatPoint, LatLonPoint, LatLonShape
+      return a -> (long) NumericUtils.sortableBytesToInt(a, 0);
+    }
+
+    return null;
+  }
+
+  static boolean canCollectEfficiently(final PointValues pointValues, final 
long bucketWidth)
+      throws IOException {
+    // TODO: Do we really need pointValues.getDocCount() == pointValues.size() 
for this optimization
+    if (pointValues == null
+        || pointValues.getNumDimensions() != 1
+        || pointValues.getDocCount() != pointValues.size()) {
+      return false;
+    }
+
+    final Function<byte[], Long> byteToLong = 
bytesToLong(pointValues.getBytesPerDimension());
+    if (byteToLong == null) {
+      return false;
+    }
+
+    long leafMinBucket =
+        Math.floorDiv(byteToLong.apply(pointValues.getMinPackedValue()), 
bucketWidth);
+    long leafMaxBucket =
+        Math.floorDiv(byteToLong.apply(pointValues.getMaxPackedValue()), 
bucketWidth);
+
+    // We want that # leaf nodes is more than # buckets so that we can 
completely skip over
+    // some of the leaf nodes. Higher this ratio, more efficient it is than 
naive approach!
+    if ((pointValues.size() / 512) < (leafMaxBucket - leafMinBucket)) {

Review Comment:
   > I imagine that 512 is the size of leaves with the default codec. It's a 
bit annoying to rely on a codec parameter. I'm tempted to replace it with a 
simpler heuristic like the collector does, something like leafMaxBucket - 
leafMinBucket <= 1024.
   
   While I share your annoyance of relying on codec parameter, `leafMaxBucket - 
leafMinBucket <= 1024` works for prior case as it uses dense array that is just 
function of this. But here, if we collect billion documents,  even ` 
leafMaxBucket - leafMinBucket  <= 10^5` is fairly reasonable. Maybe we can use 
something more generic and reasonable like 1000 instead of sticking exactly to 
the codec parameter?



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