thanks, got it
import os, subprocess, re
directory = 'abs/path'
for track, filename in enumerate(os.listdir(directory), 1):
pathname = os.path.join(directory, filename)
subprocess.call(['ffmpeg', '-i', pathname, filename+str(track)+'.mp3'])
On Thu, Jul 31, 2014 at 7:02 PM, C Smith <illusiontechniq...@gmail.com> wrote:
> Huh, that is quite an annoyance about changing the order though. Any
> ideas about that? I will look into it further in the meantime...
>
> On Thu, Jul 31, 2014 at 6:57 PM, C Smith <illusiontechniq...@gmail.com> wrote:
>> Works now, thanks!
>>
>> On Thu, Jul 31, 2014 at 6:57 PM, C Smith <illusiontechniq...@gmail.com>
>> wrote:
>>> woops, I see it pathname != filename
>>>
>>> On Thu, Jul 31, 2014 at 6:55 PM, C Smith <illusiontechniq...@gmail.com>
>>> wrote:
>>>>>for track, filename in enumerate(os.listdir(directory), 1):
>>>> It seems kinda counter-intuitive to have track then filename as
>>>> variables, but enumerate looks like it gets passed the filename then
>>>> track number. Is that correct and just the way enumerate works, a
>>>> typo, or am I missing something else here?
>>>>
>>>> It is an ffmpeg error I am getting.
>>>> ffmpeg just gives its usual build information and the error is (for
>>>> each song title in the directory):
>>>> songTitleIsHere.flac: no such file or directory
>>>>
>>>> So it looks like it is close to working because it finds the correct
>>>> file names, but doesn't recognize it for some reason.
>>>> Here is how I put in your code
>>>> import os, subprocess
>>>> directory = '/absolute/path/goes/here'
>>>> for track, filename in enumerate(os.listdir(directory), 1):
>>>> pathname = os.path.join(directory, filename)
>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>>
>>>> So it goes to the right place, because every song title is listed out,
>>>> ffmpeg or the shell just don't recognize them correctly.
>>>>
>>>> On Thu, Jul 31, 2014 at 6:35 PM, Steven D'Aprano <st...@pearwood.info>
>>>> wrote:
>>>>> You may have already have solved your problem, unfortunately my
>>>>> emails are coming in slowly and out of order, but I have a suggestion:
>>>>>
>>>>> On Thu, Jul 31, 2014 at 03:53:48PM -0400, C Smith wrote:
>>>>>> I am on OSX, which needs to escape spaces in filenames with a backslash.
>>>>>
>>>>> Same as any other Unix, or Linux, or, indeed, Windows.
>>>>>
>>>>>> There are multiple files within one directory that all have the same
>>>>>> structure, one or more characters with zero or more spaces in the
>>>>>> filename, like this:
>>>>>> 3 Song Title XYZ.flac.
>>>>>> I want to use Python to call ffmpeg to convert each file to an .mp3.
>>>>>> So far this is what I was trying to use:
>>>>>> import os, subprocess
>>>>>> track = 1
>>>>>> for filename in os.listdir('myDir'):
>>>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>>>> track += 1
>>>>>
>>>>> I believe that your problem is *not* the spaces, but that you're passing
>>>>> just the filename and not the directory. subprocess will escape the
>>>>> spaces for you. Also, let Python count the track number for you. Try
>>>>> this:
>>>>>
>>>>>
>>>>> directory = '/path/to/the/directory'
>>>>> for track, filename in enumerate(os.listdir(directory), 1):
>>>>> pathname = os.path.join(directory, filename)
>>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>>>
>>>>>
>>>>> I expect something like that will work. You should be able to pass
>>>>> either an absolute path (beginning with /) or a relative path starting
>>>>> from the current working directory.
>>>>>
>>>>> If this doesn't work, please show the full error that you receive. If it
>>>>> is a Python traceback, copy and paste the whole thing, if it's an ffmpeg
>>>>> error, give as much information as you can.
>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Steven
>>>>> _______________________________________________
>>>>> Tutor maillist - Tutor@python.org
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