Works now, thanks!
On Thu, Jul 31, 2014 at 6:57 PM, C Smith <illusiontechniq...@gmail.com> wrote:
> woops, I see it pathname != filename
>
> On Thu, Jul 31, 2014 at 6:55 PM, C Smith <illusiontechniq...@gmail.com> wrote:
>>>for track, filename in enumerate(os.listdir(directory), 1):
>> It seems kinda counter-intuitive to have track then filename as
>> variables, but enumerate looks like it gets passed the filename then
>> track number. Is that correct and just the way enumerate works, a
>> typo, or am I missing something else here?
>>
>> It is an ffmpeg error I am getting.
>> ffmpeg just gives its usual build information and the error is (for
>> each song title in the directory):
>> songTitleIsHere.flac: no such file or directory
>>
>> So it looks like it is close to working because it finds the correct
>> file names, but doesn't recognize it for some reason.
>> Here is how I put in your code
>> import os, subprocess
>> directory = '/absolute/path/goes/here'
>> for track, filename in enumerate(os.listdir(directory), 1):
>> pathname = os.path.join(directory, filename)
>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>
>> So it goes to the right place, because every song title is listed out,
>> ffmpeg or the shell just don't recognize them correctly.
>>
>> On Thu, Jul 31, 2014 at 6:35 PM, Steven D'Aprano <st...@pearwood.info> wrote:
>>> You may have already have solved your problem, unfortunately my
>>> emails are coming in slowly and out of order, but I have a suggestion:
>>>
>>> On Thu, Jul 31, 2014 at 03:53:48PM -0400, C Smith wrote:
>>>> I am on OSX, which needs to escape spaces in filenames with a backslash.
>>>
>>> Same as any other Unix, or Linux, or, indeed, Windows.
>>>
>>>> There are multiple files within one directory that all have the same
>>>> structure, one or more characters with zero or more spaces in the
>>>> filename, like this:
>>>> 3 Song Title XYZ.flac.
>>>> I want to use Python to call ffmpeg to convert each file to an .mp3.
>>>> So far this is what I was trying to use:
>>>> import os, subprocess
>>>> track = 1
>>>> for filename in os.listdir('myDir'):
>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>> track += 1
>>>
>>> I believe that your problem is *not* the spaces, but that you're passing
>>> just the filename and not the directory. subprocess will escape the
>>> spaces for you. Also, let Python count the track number for you. Try
>>> this:
>>>
>>>
>>> directory = '/path/to/the/directory'
>>> for track, filename in enumerate(os.listdir(directory), 1):
>>> pathname = os.path.join(directory, filename)
>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>
>>>
>>> I expect something like that will work. You should be able to pass
>>> either an absolute path (beginning with /) or a relative path starting
>>> from the current working directory.
>>>
>>> If this doesn't work, please show the full error that you receive. If it
>>> is a Python traceback, copy and paste the whole thing, if it's an ffmpeg
>>> error, give as much information as you can.
>>>
>>>
>>>
>>> --
>>> Steven
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>>> Tutor maillist - Tutor@python.org
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