Huh, that is quite an annoyance about changing the order though. Any
ideas about that? I will look into it further in the meantime...
On Thu, Jul 31, 2014 at 6:57 PM, C Smith <illusiontechniq...@gmail.com> wrote:
> Works now, thanks!
>
> On Thu, Jul 31, 2014 at 6:57 PM, C Smith <illusiontechniq...@gmail.com> wrote:
>> woops, I see it pathname != filename
>>
>> On Thu, Jul 31, 2014 at 6:55 PM, C Smith <illusiontechniq...@gmail.com>
>> wrote:
>>>>for track, filename in enumerate(os.listdir(directory), 1):
>>> It seems kinda counter-intuitive to have track then filename as
>>> variables, but enumerate looks like it gets passed the filename then
>>> track number. Is that correct and just the way enumerate works, a
>>> typo, or am I missing something else here?
>>>
>>> It is an ffmpeg error I am getting.
>>> ffmpeg just gives its usual build information and the error is (for
>>> each song title in the directory):
>>> songTitleIsHere.flac: no such file or directory
>>>
>>> So it looks like it is close to working because it finds the correct
>>> file names, but doesn't recognize it for some reason.
>>> Here is how I put in your code
>>> import os, subprocess
>>> directory = '/absolute/path/goes/here'
>>> for track, filename in enumerate(os.listdir(directory), 1):
>>> pathname = os.path.join(directory, filename)
>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>
>>> So it goes to the right place, because every song title is listed out,
>>> ffmpeg or the shell just don't recognize them correctly.
>>>
>>> On Thu, Jul 31, 2014 at 6:35 PM, Steven D'Aprano <st...@pearwood.info>
>>> wrote:
>>>> You may have already have solved your problem, unfortunately my
>>>> emails are coming in slowly and out of order, but I have a suggestion:
>>>>
>>>> On Thu, Jul 31, 2014 at 03:53:48PM -0400, C Smith wrote:
>>>>> I am on OSX, which needs to escape spaces in filenames with a backslash.
>>>>
>>>> Same as any other Unix, or Linux, or, indeed, Windows.
>>>>
>>>>> There are multiple files within one directory that all have the same
>>>>> structure, one or more characters with zero or more spaces in the
>>>>> filename, like this:
>>>>> 3 Song Title XYZ.flac.
>>>>> I want to use Python to call ffmpeg to convert each file to an .mp3.
>>>>> So far this is what I was trying to use:
>>>>> import os, subprocess
>>>>> track = 1
>>>>> for filename in os.listdir('myDir'):
>>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>>> track += 1
>>>>
>>>> I believe that your problem is *not* the spaces, but that you're passing
>>>> just the filename and not the directory. subprocess will escape the
>>>> spaces for you. Also, let Python count the track number for you. Try
>>>> this:
>>>>
>>>>
>>>> directory = '/path/to/the/directory'
>>>> for track, filename in enumerate(os.listdir(directory), 1):
>>>> pathname = os.path.join(directory, filename)
>>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>>>
>>>>
>>>> I expect something like that will work. You should be able to pass
>>>> either an absolute path (beginning with /) or a relative path starting
>>>> from the current working directory.
>>>>
>>>> If this doesn't work, please show the full error that you receive. If it
>>>> is a Python traceback, copy and paste the whole thing, if it's an ffmpeg
>>>> error, give as much information as you can.
>>>>
>>>>
>>>>
>>>> --
>>>> Steven
>>>> _______________________________________________
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