woops, I see it pathname != filename
On Thu, Jul 31, 2014 at 6:55 PM, C Smith <illusiontechniq...@gmail.com> wrote:
>>for track, filename in enumerate(os.listdir(directory), 1):
> It seems kinda counter-intuitive to have track then filename as
> variables, but enumerate looks like it gets passed the filename then
> track number. Is that correct and just the way enumerate works, a
> typo, or am I missing something else here?
>
> It is an ffmpeg error I am getting.
> ffmpeg just gives its usual build information and the error is (for
> each song title in the directory):
> songTitleIsHere.flac: no such file or directory
>
> So it looks like it is close to working because it finds the correct
> file names, but doesn't recognize it for some reason.
> Here is how I put in your code
> import os, subprocess
> directory = '/absolute/path/goes/here'
> for track, filename in enumerate(os.listdir(directory), 1):
> pathname = os.path.join(directory, filename)
> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>
> So it goes to the right place, because every song title is listed out,
> ffmpeg or the shell just don't recognize them correctly.
>
> On Thu, Jul 31, 2014 at 6:35 PM, Steven D'Aprano <st...@pearwood.info> wrote:
>> You may have already have solved your problem, unfortunately my
>> emails are coming in slowly and out of order, but I have a suggestion:
>>
>> On Thu, Jul 31, 2014 at 03:53:48PM -0400, C Smith wrote:
>>> I am on OSX, which needs to escape spaces in filenames with a backslash.
>>
>> Same as any other Unix, or Linux, or, indeed, Windows.
>>
>>> There are multiple files within one directory that all have the same
>>> structure, one or more characters with zero or more spaces in the
>>> filename, like this:
>>> 3 Song Title XYZ.flac.
>>> I want to use Python to call ffmpeg to convert each file to an .mp3.
>>> So far this is what I was trying to use:
>>> import os, subprocess
>>> track = 1
>>> for filename in os.listdir('myDir'):
>>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>> track += 1
>>
>> I believe that your problem is *not* the spaces, but that you're passing
>> just the filename and not the directory. subprocess will escape the
>> spaces for you. Also, let Python count the track number for you. Try
>> this:
>>
>>
>> directory = '/path/to/the/directory'
>> for track, filename in enumerate(os.listdir(directory), 1):
>> pathname = os.path.join(directory, filename)
>> subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>
>>
>> I expect something like that will work. You should be able to pass
>> either an absolute path (beginning with /) or a relative path starting
>> from the current working directory.
>>
>> If this doesn't work, please show the full error that you receive. If it
>> is a Python traceback, copy and paste the whole thing, if it's an ffmpeg
>> error, give as much information as you can.
>>
>>
>>
>> --
>> Steven
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