s are treated as 'numeric' variables. Though the ols
estimates are obviously very different.
Thank you in advance for your views on the problem.
Best Regards,
julian
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Dear Micheal
So I would be much better off just reporting the PCA as is and conclude what i
can from plot
cheers
Julian
Julian R. Marchesi
Deputy Director and Professor of Clinical Microbiome Research at the Centre
for Digestive and Gut Health, Imperial College London, London W2 1NY Tel
many thanks david for such a swift response, really appreciate your help
cheers
Julian
Julian R. Marchesi
Deputy Director and Professor of Clinical Microbiome Research at the Centre
for Digestive and Gut Health, Imperial College London, London W2 1NY Tel: +44
(0)20 331 26197
and
Professor
Rplot_PCA.pdf
Description: Rplot_PCA.pdf
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and provide commented
I am now trying to use random effects in GAMs developed by Professor Simon
Wood. Prof Wood uses s(...,bs="re") to account for the random effects.
Random intercepts models or random slopes models are two different types of
mixed linear models or general random effects model (Cameron and Trivedi,
20
uggestions?
#
gam(crash~s(main.traffic.volume, ID, bs=“re")+s(minor.traffic.volume, ID,
bs="re"), family=nb(),data=mydata3sg)
#
Many thanks!
On Fri, Feb 12, 2016 at 1:57 PM, Julian
happens if I call R from Matlab, not when I start R by itself or use
the terminal to start R.
I already installed R new, but it did not help.
Can anyone enlighten my on this matter?
Thanks a lot!
Julian
Dr. Julian Keil
AG Multisensorische Integration
Psychiatrische Univer
occur (and a Error:
"java.lang.OutOfMemoryError: GC overhead limit exceeded" when trying to
set a larger size).
Does anybody else have or had this problem?
All the best
Julian
adapted Example from help (?dbHasCompleted ), Works ###
require("RSQLite"
Postgres_drv)
#Error in .valueClassTest(standardGeneric("dbUnloadDriver"), "logical", :
# invalid value from generic function 'dbUnloadDriver', class "NULL",
expected "logical"
--
All the best
Julian
[[alternativ
NULL
# save as.mids
as.mids(imp_long,.imp=1, .id=2) # doesnt work
as.mids(imp_long) # doesnt work
Best,
Julian
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PLEASE do read the postin
I am having the same problem
trainImp <- rfImpute(train[,!colnames(train)=="score"],train$score)
yields
Error in randomForest.default(xf, y, ntree = ntree, ..., do.trace = ntree,
:
NA not permitted in predictors
any ideas?
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the issue seemed to crop up after I installed RStudio.
Best wishes,
Julian Wells
Begin forwarded message:
> From: r-help-requ...@r-project.org
> Subject: R-help Digest, Vol 122, Issue 5
> Date: 5 April 2013 11:00:08 GMT+01:00
> To: r-help@r-project.org
> Reply-To: r-help@r-proje
27;Permission denied'
I'm running
R 2.15.3 GUI 1.53 Leopard build 64-bit
on a MacBook Pro
Processor 2.3 GHz Intel Core i7
Software Mac OS X Lion 10.7.5 (11G63)
Julian Wells
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Hi,
This worked:
fit <- hclust(d, method="ward")
library(ape)
p <- (as.phylo(fit))
write.tree(p, file="MyNewick.tre")
Cheers,
J
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Sent from the R help mailing list arch
uot;)
d <- dist(data, method = "euclidean")
library(ape)
fit <- as.phylo(hclust(d, method="ward")
library(ctc)
write.table(as.phylo(hc2Newick(fit),
file="C:/path/output.txt",row.names=FALSE,col.names=FALSE))
Would anyone have an idea about how to make this work?
I'm trying to use a self-written function with the summaryBy function (doBy
package).
I have lots of data from Monte Carlo experiments comparing different
estimators across different (combinations of) parameter values, similar to
the following form:
colnames(mydata) <- c("X", "b0", "b1", # parame
Hi,
I'm new to R and using it for Cox survival analysis. Thanks to this great forum
I learned how to compute the HR with its confidence interval.
My question would be: Is there any way to get the p-value for a hazard ratio in
addition to the confidence interval?
Thanks,
Thierry
--
Thier
eed to copy the
dim information to y too.
attributes(y)<-attributes(x)
Is this a correct way to do it in R? Is there any single step function
which can do the something? Thanks
Regards,
TszKin Julian
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https:
? How can i create a progress
bar in parallelized foreach? Thanks
cl<-makeCluster(core)
registerDoSNOW(cl)
pb<-txtProgressBar(min = 0, max = n, style = 3)
foreach( i = 1:n ,.combine=c) %dopar%{
setTxtProgressBar(pb, i)
Sys.sleep(0.1)
}
close(pb)
stopCluster(cl)
Regards,
TszKin
facet_grid(code2 ~ code1)
p + geom_vline(aes(xintercept = n.mean), mean.data,col="red")
# END R CODE ##
I can´t figure out why the second example does not work when having
the "scales=free" argument, and why I get the extra face
Hi all,
Is there any way for me to to string in the argument of qplot or ggplot? for
example
qplot(x='carat',y='price',data=diamonds,geom=c('point','smooth'))
instead of
qplot(x=carat,y=price,data=diamonds,geom=c('point','smooth'))
On Sun, Apr 24, 2011 at 07:02:48PM -0400, Ravi Varadhan wrote:
> Julian,
>
> You have not specified your problem fully. What is the nature of f? Is f a
> scalar function or is it a vector function (2-dim)?
It's something like this (only a bit worse):
given x, work out alpha
her
> it is a y1 or a y2 observation. You can also specify a within-pair
> correlation.
Will take a look, thanks!
Julian
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PLEASE do read the posting gu
estimated, and I'll
assume the errors to be normal for sake of simplicity.
If there were only one response per input, I would use the nls()
function, but what can I do in this case?
Many thanks,
Julian
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)
library(mgcv)
g3 = mgcv::gam( y ~ s(x) )
plot(g3)
detach(package:mgcv,unload=TRUE)
library(gam)
g4= gam::gam( y ~ s(x,5) )
plot(g4,se=TRUE)
Julian Shaw
Notice:
This e-mail message is intended only for the named recipient(s) above. It may
contain
luster(cl)
# However if i put require(lmtest) inside the foreach loop, it works again!
cl<-makeCluster(2)
registerDoSNOW(cl)
foreach(i=1:2) %dopar% {
require(lmtest)
coeftest(lm(length ~ age, data=Mandible, subset=(age <= 28)))
}
stopCluster(cl)
ed
to, and it is not for everyone. But, it is totally customizable, and
combined with org mode and org babel it becomes a tool as no other.
I´ve tried about every editor, including Tinn-R, Notepad++, and
Eclipse with StatEt, but after switching to Emacs/ESS there is no
turning back.
Julian
-
hoc test on the categorical predictor in the models where it is
significant.
Any suggestions?
Thanks,
Julian
--
Julian Mariano Burgos
Hafrannsóknastofnunin/Marine Research Institute
Skúlagata 4, 121 Reykjavík, Iceland
Sími/Telephone : +354-5752037
Bréfsími/Telefax: +354-5752001
Netfang/Email
ource(.trPaths[5], echo=TRUE, max.deparse.length=150)
It doesn't do that after I configure
(R>configure>permanent(rprofile.site)) but after i closed R/Tinn-R I
have to configure R again. Is that necessary?
Thank you,
Julian
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R-help@r-pro
As I understand it, predict.lm(l ,newdata=nd ,interval="confidence") yields
confidence bands for the predicted mean of new observations and lm.predict(l
,newdata=nd ,interval="prediction") yields confidence bands for new
observations themselves, given an lm object l.
However with regard to {m
Hi all,
Is there any tutorial for learning C/R interface ? Thanks
Regards,
Julian
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PLEASE do read the posting guide http
ength(x) - length(y) ]]
> y
[[1]]
[1] 2
[[2]]
[1] 3
[[3]]
[1] 4
[[4]]
[1] 5
Regards,
Julian
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x,y, MoreArgs = MoreArgs, SIMPLIFY = SIMPLIFY,
USE.NAMES = USE.NAMES)
}
Regards,
Julian
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r some reason R
prints the attributes of the object when you do the inverse but not when you
do the square root (I´m curious about why...If anyone has an answer please
pitch in).
If you only want to get a number, do this:
> x=as.numeric(dist(temp))
> class(x)
[1] "numeric"
> 1/
Does anyone know of any tools to do multichannel(multivariate) singular
spectrum analysis (M-SSA) in R? Seems like this would be a useful thing to
have.
-Hilbert
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ocale:
[1] LC_COLLATE=Icelandic_Iceland.1252 LC_CTYPE=Icelandic_Iceland.1252
[3] LC_MONETARY=Icelandic_Iceland.1252 LC_NUMERIC=C
[5] LC_TIME=Icelandic_Iceland.1252
attached base packages:
[1] grDevices datasets splines graphics stats tcltk utils
[8] methods base
other attache
me4=strptime("2009 06 01 00 57 00",format="%Y %m %d %H %M")
> >
> > diff(c(time3,time4))
> Time difference of 10 mins
> >
>
> I have version 2.10.1
>
> On Thu, May 20, 2010 at 12:36 PM, Julian Burgos wrote:
> > Dear list,
> >
> >
06 01 00 57 00",format="%Y %m %d %H %M")
>
> diff(c(time3,time4))
Time difference of NA secs
...which is not what I´m looking for. The difference should also be 10
minutes.
I burned a few neurons (and searched the documentation) and I cannot figure
why this happens. Any ide
higher at
intermediate values.
It seems that the best way to go is to model this using the "quasi" family
with a logit link and a mu(1-mu) variance. Or I am missing something
obvious? I will be thankful for any input.
All the best,
Julian
--
Julian Mariano Burgos
Hafrannsóknastofnu
(0.54)
7.4 (0.45) 1.4 (0.63)4.6 (0.37)
What would be the best way to fit a multiple regression taking into account
the variance of the individual values of the independent and dependent
variables? Any references to methods or R packages will be greatly welcomed.
Julian
--
Julian
microsoft.
All that is free. I suggest you to read tutorials on how to build packages
from sources in Windows. This website might be a good start point
http://www.biostat.wisc.edu/~kbroman/Rintro/Rwinpack.html.
Hope this helps,
Julian Ramirez
Research Assistant
International Centre for Tropical
-tests flag
Many thanks for any help you might be able to provide,
Julian Ramirez
Research Assistant
International Centre for Tropical Agriculture, CIAT
Colombia
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You have to download it from CRAN and install it. From the GUI, do
Packages->Install package(s).
Pretty basic stuff...you should check the documentation before posting.
Julian
>
>
> R version 2.9.2 (2009-08-24) - for windows
>
>> library(SOM)
> Error in library(SO
rovide commented, minimal, self-contained, reproducible code.
--
Julian Mariano Burgos
Hafrannsóknastofnunin/Marine Research Institute
Skúlagata 4, 121 Reykjavík, Iceland
Sími/Telephone : +354-5752037
Bréfsími/Telefax: +354-5752001
Netfang/Email: jul...@hafro.is, jmbur...@u.washington.edu
___
end (for example, "number" instead
of "n").
b) How to avoid having a legend for the polygon?
Many thanks,
Julian
--
Julian Mariano Burgos
Hafrannsóknastofnunin/Marine Research Institute
Skúlagata 4, 121 Reykjavík, Iceland
Sími/Telephone : +354-5752037
Bréfsími/Telefax: +354-
"PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code."
Otherwise...the only other possible suggestion is to use a smaller file.
Julian
Neotropical bat risk assessments wrote:
Hi all,
I am
Hi Torsten,
If you are fitting a line, why are you using "loess"? Why not simply
use "lm" to fit a regression line that goes through the origin? (i.e.
with no intercept).
Julian
jimm-pa...@gmx.de wrote:
Hi all,
I'm fitting a line to my dataset. Later I want to pr
Hi
Is there any package in R that allow me to do IV probit, just like the
ivprobit command in stata.
or do i have to carry out the newey's two-step estimator myself?
Regards,
Julian
[[alternative HTML version deleted]]
__
R-h
You could do something like this:
> Name.x=c('nx1','nx2',NA,NA)
> Name.y=c('ny1','NA','ny3',NA)
> Name=Name.x
> Name[is.na(Name.x)]=Name.y[is.na(Name.x)]
> Name
[1] "nx1" "nx2" "ny3" NA
Julian
You can use the points() and lines() functions to add points and lines
to an existing plot.
Julian
Michel PETITJEAN wrote:
I am a new user of R.
Please does somebody knows how to plot 3 datasets
(x1,a1),...,(xn,an), (x1,b1),...,(xn,bn), and (x1,c1),...,(xn,cn)
on a single x,y plot, each of
How about something like
my.data=my.data[,4:1]
Julian
milicic.marko wrote:
Hi,
I have the data.frame with 4 columns. I simply want to invert dataset
so that last row becomes first...
I tried with rev(my_data-frame) but I got my columns inverted... not
my rows
Thanks
primera fila, hice un vector con el
nombre y nueve espacios en blanco (para completar las diez filas que
tiene mi tabla).
Al grabar la tabla usando write.csv, el comportamiento "default" es
guardar los nombres de las columnas y filas.
Saludos,
Julian
Luz Milena Zea Fernandez wrote:
by doing
my.clusters$membership
Hope this helps,
Julian
cnagy wrote:
I'm trying to test a method of identifying individuals (birds) based on
measured data (their calls).
I have test data from known individual birds, and I am using the Mclust
package to see if the program can corr
Do simply
which(a<100 & a>=200)
Julian
sj wrote:
Hello, I am trying to identify values that fall within a certain range. I
thought that I might be able to use the which function to do this but I have
been unable to figure out a way to do it. Perhaps a little code will
illustrate
Hi Paul,
The easiest thing to to is to open the file using a text editor (Notepad
will do) and examine the first few lines. You can add add a column name
if needed.
Julian
Paul Adams wrote:
Hello to everyone,
I have gotten my file to print to screen but when I use read.table I am getting
Hola Borja,
Creo que vas a tener muy pocas respuestas a menos que escribas a la
lista en inglés. Lamentablemente yo conozco poco de Java y no puedo
responder tu pregunta.
Saludos,
Julian
Borja Soto Varela wrote:
Hola, es la primera vez que mando un correo a cualquiera de las listas de
Hi Steve,
You can use write.table:
write.table(x, file="/Users/Desktop/Data.txt",
sep="",row.names=F,col.names=F)
Cheers,
Julian
Stropharia wrote:
Dear R users,
I've had no joy finding a solution to this online or in any of my R books.
Many thanks in advance
You could do something like this:
mydata=c(1,2,1,1,6,7,-1,-1,5,-1)
color= as.numeric(mydata== -1) +1
plot(mydata,col=color)
This will give you a plot where the -1's are in red (color = 2) and the
other numbers in black (color=1).
Julian
uv wrote:
Hi. I am plotting graphs for v
see
?findIntervals
francogrex wrote:
Hi, this is probably quite simple but I can't seem to do it correctly. I have
a data frame of counts of infections in different ages; something like:
count=c(1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 7, 8, 8, 9, 9,
10, 11, 15, 17, 17, 17, 17, 19, 19, 19,
rint (x)
Var1 Var2
1 11
2 21
3 31
4 41
5 51
6 12
7 22
8 32
9 42
1052
1113
1223
1333
144 3
1553
Hope this helps,
Julian
Philip Twumasi-Ankrah wrote:
I am new to more radical pro
Depends on the RAM in your machine. And in your definition of 'handle'.
You may be able to load a very large dataset into R, but won't be able
to use some functions that require additional memory.
A vague answer to a vague question... :)
Julian
Mingjun Huang wrote:
Hello,
Try this:
k=c(1,1,1,2,2,1,1,1)
> k[(k!=1)]
[1] 2 2
> k[(k!=2)]
[1] 1 1 1 1 1 1
> k[(k!=3)]
[1] 1 1 1 2 2 1 1 1
Julian
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-w
Hi Stephen,
Your link doesn't work. In any case, check out the wavCWT function in
the wmtsa package.
Julian
stephen sefick wrote:
http://ion.researchsystems.com/cgi-bin/ion-p
I would like a continuous wavelet transform. I have downloaded wavethresh,
Rwave, and waveslim. I would li
Try
get(paste("wf$",fl[[1]],sep=""))
See ?get
Julian
Dirkheld wrote:
Hi,
I have a dataframe wf existing of a header with different labels and beneath
the values of those labels :
wf:
label1 label2 ...
0,450,21
0,100,45
I have a list
fl &
See
?match
ss wrote:
Dear list,
If I have two vector, t1 and t2, of different lengths. Is there an easy way
to count
the number of the overlapped in two vectors and show the result in the
graph?
Thanks much,
Alex
[[alternative HTML version deleted]]
rop=prop/length(x)
return(prop)}
This function first identifies which numbers in your original vector are
part of a sequence of consecutive numbers.
Julian
Julian Burgos wrote:
Hey Anthony,
There must be many ways to do this. This is one of them:
#First, define a function to calculate
ortions of consecutive
numbers
Julian
Anthony28 wrote:
I need to use R to model a large number of experiments (say, 1000). Each
experiment involves the random selection of 5 numbers (without replacement)
from a pool of numbers ranging between 1 and 30.
What I need to know is what *proportion
x within each group.
> means=tapply(x,group,mean)
> vars=tapply(x,group,var)
> means
1 2 3
-0.14711206 0.28314274 -0.07861427
> vars
1 2 3
1.4584971 0.3611996 0.6300624
Julian
kathie wrote:
> Dear R users,
>
> I have
Hi
You can try using the ctc package to export your dendrogram objects and use
Cluster to open them.
This package is part of biocondutor.
>>source("http://bioconductor.org/biocLite.R";)
>>biocLite('ctc')
regards
Julian Lee
- Original Message -
From: Ji
In this case you can simply do
cumsum(a[x,]+a[y,])
Julian
yoo wrote:
> Hi all, i have the following..
>
> a <- data.frame(data = seq(1,10))
>
> i have indices:
> x <- c(1, 5, 3, 9)
> y <- c(2, 7, 4, 10)
>
> I want the cumsum of a[1:2], a[5:7], a[3:4]
Hello Kayj,
There are very good tutorials at the R website. See here:
http://cran.r-project.org/other-docs.html
Julian
kayj wrote:
> Hi All,
>
> I am a new user in R and I would like to buy a book that teaches me how to
> use R. In addition, I may nees to do some advanced
See ?assign.
ppaarrkk wrote:
> I have an array called filesBox. I want to take each element of the first
> column and assign a dataset to it.
>
> For example :
>
> filesBox[4,1] returns
>
> [1] "fileR"
>
> Then I want to assign "fileR" which exists as a text file to the R object
> "fileR" lik
elp says that the exact method is computationally demanding, but even
after days the computing it won't finish. Also, if I include a frailty-term,
the exact method gives me results in no time. Is my setup incorrect?
Many thanks in advance!
-
Julian Wucherpfennig
PhD Student Politica
See rnorm(). If you are sampling from a continuous normal distribution,
it makes no sense to define a sample with replacement, because the
probability of sampling twice the same number is zero.
Julian
sigalit mangut-leiba wrote:
> Hello,
> How do I sample observations with replacement
Tinn-R also has this option. I suspect most editors will also do.
Julian
-Halcyon- wrote:
> RWinEdt has line indication. You might want to try that.
>
>
> Uwe Ligges-3 wrote:
>> This depends on the editor you use for writing R code rather than on R.
>>
>> U
Hi Mika03,
It would be useful to know what function you used to create your plot.
Assuming you used boxplot, do this:
?boxplot
?boxplot.stats
Julian
mika03 wrote:
>
> http://www.nabble.com/file/p14668788/paragraphs.png
>
> Hi,
>
> R is is world full of wonders... I cr
Hi Livia,
There are several ways to do this. Try:
a=50/12
floor(a) will give you the entire portion, and
a-floor(a) will give you the remainder.
Julian
livia wrote:
> Hello everyone,
>
> I have got a question about a simple calculation. If I would like to
> calculate 50/12 an
Hi Jack,
Any intro stats book should have them. See for example chapter 11 in
Sokal and Rohlf (2nd ed., 1981).
Julian
Jack Luo wrote:
> Dear list,
>
> Could someone show me where can I find the detailed formula on how to
> calculate the two way anova with unbalanced design? Say, i
I should say that the name of this chart varies even among
Spanish-speaking countries. In Argentina is "diagrama de torta" which
is something like "cake-chart".
Julian
ahimsa campos-arceiz wrote:
> Two non-eatable examples from Spain and Japan:
>
> in Span
large) and review line 528, instead of reviewing the
spreadsheet in Excel. You should be able to spot the problem right away.
Julian
Wayne Aldo Gavioli wrote:
> Hello all,
>
>
> I seem to be having a problem importing a data set from Excel into R. I'm
> using
> the &q
imply
data.matrix=as.matrix(data)
Julian
Andre Jung wrote:
> I just got stuck with a quite simple question. I've just read in an
> ASCII table from a plain text file with read.table(). It's a 1200x1200
> table. R has assigned variables for each column: V1,V2,V3,V4,...
> Fo
The basic functions you need are
image()
contour()
although I like better the plot.surface() function in the 'fields' package.
Julian
threshold wrote:
> Hi All, simple question:
> do you know how to graph the following object/matrix in a 'surface manner':
>
>
it of clarification I
may help you some more.
Julian
TLowe wrote:
> Hey Folks,
>
> Could somebody help me rewrite the following code?
>
> I am looping through all records across 5 fields to calculate the cumulative
> percentage of each record (relative to each individual field).
previous plot)}
Julian
Roger Levy wrote:
> I'm interested in writing a function that constructs a new plot on the
> current graphics device if no plot exists there yet, but adds lines to
> the existing plot if a plot is already there. How can I do this? It
> seems to me that the
nction.
I hope that helps,
Julian
[EMAIL PROTECTED] wrote:
> Hello R cracks
>
> The image() function requires strictly increasing x and y values and z as a
> matrix.
>
> Actually, I don't have equally spaced variables, but anyway want to plot an
> colored image() (wit
clearly what
you are trying to achieve, we can help you to simplify your code.
Julian
Julian Burgos wrote:
> Hi Amy,
> Many (perhaps most) of the people on the list do not receive emails with
> html...so we can't see colored text. Also it would be helpfully to have
> a bit of you
lease explain what are the 'xlabel' and the 'ylabel' that you
mentioned. I don't see those variables in your code.
Julian
Amit Patel wrote:
> Hi
> I am very new to R and statistical programming in general. I am trying to
> reorder data from a .csv file. I have
(as.matrix(x))
x=matrix(x,ncol=11,byrow=T)
Julian
marcg wrote:
> This was my intention, but I'm not able to read it in as a vector (because i
> don't know the function, neither I can convert the read in table to a vector
> and then to matrix or directly.
>
> What did I miss o
analytical work,
it is probably a good idea to learn about the different methods, its
assumptions and limitations.
Julian
mysimbaa wrote:
> http://www.nabble.com/file/p13880048/Fluctuation.jpeg
>
> Hi R users,
>
> I have collected data which I plot(x,y).The problem it has oscillat
Like always, there is much to be learned from the R-help list! Another
message had a much simpler approach.
plot(xy.coords(reizstaerke, kennlinie1, log="x"), log="x")
Julian
Julian Burgos wrote:
> Hey John,
>
> You can do simply
>
> plot(reizstaerke, k
=F,xlim=log10(c(1,1000)))
box()
axis(1,at=log10(c(1,10,100,1000)),label=c(1,10,100,1000))
axis(2)
Julian
John Wiedenhoeft wrote:
> Hi there,
>
> I guess this must be a standard issue, but I'm starting to go crazy with it.
> I
> simply want a plot with the x axis being log
e at the bottom of every message send through this list. The
posting guide is not hard to find, and (in my opinion) it isn't long or
difficult to understand (in particular for anyone taking college level
statistics).
Julian
Loren Engrav wrote:
> I am a newbie to R and Bio emails and
>
&g
columns, and
you'll get everything except the rows/columns referenced.
Julian
Barb, Jennifer (NIH/CIT) [E] wrote:
> Can anyone tell me how to delete a row in a matrix? I have searched
> around and couldn't find a straightforward way to do this.
>
> Thanks, any help will be
should not expect for people on the list to
do your homework for you. That is a big no-no.
Cheers,
Julian
Epselon wrote:
> I have three problems I am trying to simulate, that I am having difficulty
> getting around with.
>
> Problem 1.
> I want to determine the 85 percentile (
If you don't know the class of
the object, you can do this:
class(Disease.FL)
Julian
affy snp wrote:
> Dear list,
>
> Hello! I have a question about how to print a label in the plot.
> I am using the following code:
>
> width=5);plot(Disease.FL, index=i, type="Single&qu
posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Julian M. Burgos
Fisheries Acoustics Research Lab
School of Aquatic and Fishery Science
University of Washington
1122 NE Boat Street
Seattle, WA 98105
Phone: 206-221-6864
__
self-contained,
reproducible code' so we can find the problem.
As a general comment, you can do any number of plots on a device (a
window or a pdf file). The limit is only given by the number and size
of the plots and the size of the device.
Julian
affy snp wrote:
> Dear list,
>
summary(log_v)
Julian
sigalit mangut-leiba wrote:
> Hello,
> In addition to my question a few days ago,
> Now I have a matrix of the coefficients,
> how can I see all the P.Values (Pr(>|z|)) of the covariates from the 1000
> iterations?
> I tried names(log_v) and couldn
ogarithm is not
defined for negative numbers.
Julian
Wensui Liu wrote:
> dont think so, unless i miss something here.
> please do check the range of normal random number and the domain of
> log function.
>
> On 11/14/07, Tobias Schlottmann <[EMAIL PROTECTED]> wrote:
>
One way to do this is
range(which(B[,2]==1))
Julian
affy snp wrote:
> Hello list,
>
> I read in a txt file using
>
>
> by specifying the row.names=NULL so that the rows are numbered.
> Below is an example after how the table looks like using
>
>
>
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