Try this:
k=c(1,1,1,2,2,1,1,1)
> k[(k!=1)]
[1] 2 2
> k[(k!=2)]
[1] 1 1 1 1 1 1
> k[(k!=3)]
[1] 1 1 1 2 2 1 1 1
Julian
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
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