(a), function(i) { b <- v[a$country_code[i]];
> a$year[i] - ifelse(is.na(b),d,b)})
>
> Best,
> Eric
>
>
>
>
>
> On Thu, Oct 3, 2019 at 5:19 PM Faradj Koliev wrote:
> Hi,
>
> I was thinking that it could simply show the negative counts. For ex: if
rev Eric Berger :
>
> Hi Faradj,
> What should the treatment variable be in those cases? If you want to set it
> to a constant y (such as y=0), you can add something like
>
> y <- 0
> a$treatment[ is.na(a$treatment) ] <- y
>
> HTH,
> Eric
>
>
> On Thu
a$treatment <- sapply( 1:nrow(a), function(i) { a$year[i] -
> v[a$country_code[i]]})
>
> HTH,
> Eric
>
>
> On Thu, Oct 3, 2019 at 3:36 PM Faradj Koliev wrote:
> Dear Michael Dewey,
>
> Thanks for reaching out about this. I trying again, now with plain text, a
= c(NA,
-722L))
> 3 okt. 2019 kl. 14:24 skrev Michael Dewey :
>
> Dear Faradj
>
> I am afraid your post is unreadable since this is a plain text list and you
> sent in HTML.
>
> Michael
>
> On 03/10/2019 12:17, Faradj Koliev wrote:
>> Dear R-users,
>>
Dear R-users,
I need an urgent help with the following: I have a country-year data covering
the period 1982 - 2013. I want to assess how the variable X (a certain policy)
affects the Y variable. The X variable is =1 when a country introduces that
policy in a specific year, otherwise =0.
What
%>%
mutate(
idx = +( (lag(X1) == 0 & X1 == 1) | row_number() == 1 & X1 == 1),
X1_pre4 = check_pre(idx, 4),
X1_pre5 = check_pre(idx, 5),
idx = NULL
)
> On 27 Jul 2019, at 10:45, Faradj Koliev wrote:
>
> Peter Dalgaard,
>
> Thanks for this.
>
reement. Then X1_pre4 should be as.integer(tt <=4
> & tt > 0)
>
> -pd
>
>> On 27 Jul 2019, at 09:13 , Faradj Koliev wrote:
>>
>> Re-post, now in *plain text*.
>>
>>
>>
>> Dear R-users,
>>
>> I’ve a rather comp
king things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Fri, Jul 26, 2019 at 12:25 PM Faradj Koliev wrote:
> Dear R-users,
>
> I’ve a rather complicated task to do and need all the help I can get.
>
> I have data i
Dear R-users,
I’ve a rather complicated task to do and need all the help I can get.
I have data indicating whether a country has signed an agreement or not (1=yes
and 0=otherwise). I want to simply create variable that would capture the years
before the agreement is signed. The aim is to see
da,2,2
> >2002,Canada,2,2
> >2003,Canada,1,2
> >2004,Canada,2,0.5
> >2005,Canada,1,0.5
> >2006,Canada,0,0.5
> >2007,Canada,1,0.5
> >2008,Canada,0,0.5
> >2009,Canada,1,0.5
> >2010,Canada,1,0.5
> >2011,Canada,0,1",
> >h
Dear R-users,
I have a country-year data for 180 countries from 1970 to 2010. I’m interested
in capturing positive and negative changes in some of the variables. Some of
these variables are continuous (0,25, 0,33, 1, 1,5 etc) others are ordered
(0,1, 2).
To do this, I use this code data$X1_c
1 0
> [75] 1 0 0 0 1 0 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0
>> fkdf$X
> [1] 1 0 0 1 0 0 1 0 1 0 1 0 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0
> [38] 1 0 1 0 1 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 1 0
> [75] 1 0 0 0 1 0 0
Hi everyone,
I am trying to generate a conditional dummy variable ”X" with the following
rules
set X=1 if Y is =1, two years prior to the NA. [0,0,NA].
For example, if the pattern for Y is 0,0,NA then the X variable is =0 for all
the two years prior to the NA. If the pattern for Y is 0,1
t;> E.g.,
>>>> options(digits=16)
>>>> base::log1p(1e-14)
>>> [1] 9.95e-15
>>>> base::log1p(1e-14) - base::log(1+1e-14)
>>> [1] 7.992778373591124e-18
>>>> as.numeric(log(Rmpfr::mpfr(1,precBits=1000) + Rmpfr::mpfr(1e
Hi all,
How do I perform log(x+1) in R?
log1p_trans() from the package ”scales" doesn’t seem to work for me.
Best,
Faradj
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do re
Dear all,
I need a little help with plotting predicted probabilities (values). Consider
the following example
**
data(”mtcars”)
mfit = lm(mpg ~ vs + disp + cyl, data=mtcars)
newcar=data.frame(vs=c(0,1), disp=230, cyl=6.188)
Pmodel<–predict(mfit, newcar)
**
I want to plot the effect of ”vs
;
>> See in line
>>
>>> -Original Message-
>>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Faradj
>>> Koliev
>>> Sent: Thursday, August 25, 2016 12:32 PM
>>> To: r-help@r-project.org
>>> Subject: [R] Hickma
Hi everyone,
How do I run Heckman models in R with two binary dependent variables?
sampleSelection package in R works with standard heckman models ( binary DV for
the selection equation and continuous DV for the outcome equation). In my case
dependent variables are both binary (actually order
Hi everyone,
I have three ordered regression models where the ordered dependent variable
ranges from 0 to 2. What I want to do is create marginal effects tables (not a
plot) at each level (0, 1, and 2) for all three models. So, three tables with
each showing the marginal effects at level 0, 1,
tat. Pr(Chi)
1 2121 1763.999
2 2120 1732.787 1 vs 2 1 31.21204 2.313266e-08
And both seems to reject the null hypothesis. Thanks again!
Best,
Faradj
> 27 jul 2016 kl. 13:35 skrev Fox, John :
>
> Dear Faradj Koliev,
>
>
Dear all,
A quick question: Let’s say I have a full and a restricted model that looks
something like this:
Full<- polr(Y ~ X1+X2+X3+X4, data=data, Hess = TRUE, method="logistic”) #
ordered logistic regression
Restricted<- polr(Y ~ X1+X2+X3, data=data, Hess = TRUE, method="logistic”) #
or
Dear David Winsemius,
Thank you!
The sample make no sense, I know. The real data is too big. So, I only want to
understand how to plot marginal effects, to visualize them in a proper way.
Best,
> 22 juli 2016 kl. 08:35 skrev David Winsemius :
>
>>
>> On Jul 21, 2016,
Dear all,
I have two logistic regression models:
• model <- glm(Y ~ X1+X2+X3+X4, data = data, family = "binomial")
• modelInteraction <- glm(Y ~ X1+X2+X3+X4+X1*X4, data = data, family =
"binomial")
To calculate the marginal effects (MEM approach) for these models, I used the
`mfx` p
Dear all,
I hope you’re enjoying your summer!
I've been asked to "aggregate" my time lags from simple 1 year time lag to 1-3
year time lag. This could be done --I've been told --by simply taking the sum
or mean of time lag 1,2, and 3.
I need your help here. How can I generate this "aggrega
ng now?
> 1 jul 2016 kl. 14:57 skrev Achim Zeileis :
>
> On Fri, 1 Jul 2016, Faradj Koliev wrote:
>
>> Dear all,
>>
>> I use ?polr? command (library: MASS) to estimate an ordered logistic
>> regression.
>>
>> My model: summary( model<-
Dear all,
I use ”polr” command (library: MASS) to estimate an ordered logistic regression.
My model: summary( model<- polr(y ~ x1+x2+x3+x4+x1*x2 ,data=mydata, Hess =
TRUE))
But how do I get robust clustered standard errors?
I’’ve tried coeftest(resA, vcov=vcovHC(resA, cluster=lipton$ID)
Dear all,
Let’s say that I have a dataset that looks something like this:
Subject YearA
A 19901
A 19911
A 19921
A 19931
A 19940
A 19950
B 19901
B 19910
B 19921
B 19
Dear all,
I’ll need your help with obtaining robust clustered errors. I use polr command
in MASS package m<–porl(y~x1+x2,data=mydata, method=probit). In the rms
package, this is as simple as: clusterSE<–robcov(m, mydata$id). Is it possible
to do something similar for polr object as well? Thank
Dear all,
I have two questions that are almost completely related to how to do things in
R.
I am running an ordinal probit regression analysis in R. The dependent variable
has three levels (0=no action; 1=warning; 2=sanction).
I use the lrm command in the rms package:
print( res1<- lrm(Y ~ x
Dear all,
I am looking for some online courses – paid or free – in survival analysis with
R. Perhaps you can recommend some interesting online courses?
Best,
Faradj Koliev
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https
Hey,
I am having some problems with importing a csv file into R and then saving it
for analyzing.
I got a csv file ( skater.csv) which i could read by typing:
read.csv(file="/Users/kama/Desktop/skatter.csv", header=TRUE, sep=";")
However, when i enter:skatter.csv<-read.csv("skatter.c
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