Dear Jim, wow! It worked! Thanks a lot.
I did as you suggested and it worked well with the real data. Although it gave me this error: Error in if (!is.na(x$Y[i])) { : argument is of length zero. For some reason the X1 produced less observations than it is in the data. But it's not a big deal - I identified those cases and simply deleted from the data (it was countries that only appeared twice in the data (e.g. USSR Yugoslavia etc). Best, Faradj > 29 maj 2018 kl. 02:15 skrev Jim Lemon <drjimle...@gmail.com>: > > Hi Faradj, > What a problem! I think I have worked it out, but only because the > result is the one you said you wanted. > > # the sample data frame is named fkdf > Y2Xby3<-function(x) { > nrows<-dim(x)[1] > X<-rep(0,nrows) > for(i in 1:(nrows-2)) { > if(!is.na(x$Y[i])) { > if(x$Y[i] == 1 && any(is.na(x$Y[(i+1):(i+2)]))) X[i]<-1 > if(i > 1) { > if(X[i-1] == 1) X[i]<-0 > } > } > else { > if(!is.na(x$Y[i+1])) { > if(x$Y[i+1] == 1 && is.na(x$Y[i+2]) && X[i] == 0) > X[i+1]<-1 > } > } > } > return(X) > } > countries<-as.character(unique(fkdf$country)) > X1<-NULL > for(country in countries) > X1<-c(X1,Y2Xby3(fkdf[fkdf$country == country,])) > X1 > [1] 1 0 0 1 0 0 1 0 1 0 1 0 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 > [38] 1 0 1 0 1 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 1 0 > [75] 1 0 0 0 1 0 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 >> fkdf$X > [1] 1 0 0 1 0 0 1 0 1 0 1 0 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 0 1 0 0 > [38] 1 0 1 0 1 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 1 0 > [75] 1 0 0 0 1 0 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 > > Jim > > On Mon, May 28, 2018 at 8:43 PM, Faradj Koliev <farad...@gmail.com> wrote: >> Hi everyone, >> >> I am trying to generate a conditional dummy variable ”X" with the following >> rules >> >> set X=1 if Y is =1, two years prior to the NA. [0,0,NA]. >> >> For example, if the pattern for Y is 0,0,NA then the X variable is =0 for >> all the two years prior to the NA. If the pattern for Y is 0,1,NA or 1,0,NA >> then the X =1 . To be clear, if 1,1,NA then the X=1 that first specific >> year, it should only count once (X=1), not twice. >> >> The code that I have now is not complete and I would appreciate some advice >> here. This is the code: >> dat2 <- dat1 %>% >> group_by(country) %>% >> group_by(grp = cumsum(is.na(lag(Y))), add = TRUE) %>% >> mutate(first_year_at_1 = match(1, Y) * any(is.na(Y)) * any(tail(Y, 3) == >> 1L), >> X = {x <- integer(length(Y)) ; x[first_year_at_1] <- 1L ; x}) %>% >> ungroup() >> >> It doesn’t really generate what I described above. Any help here would be >> much appreciated. >> >> Below you can see my sample data with the desired outcome ”X” dummy in it. >> >> Thank you! >> >>> dput(data) >> structure(list(year = c(1991L, 1992L, 1993L, 1994L, 1995L, 1996L, >> 1997L, 1998L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, >> 2006L, 2007L, 2008L, 2009L, 2010L, 2011L, 1990L, 1991L, 1992L, >> 1993L, 1994L, 1995L, 1996L, 1997L, 1998L, 1999L, 2000L, 2001L, >> 2002L, 2003L, 2004L, 2005L, 2006L, 2007L, 2008L, 2009L, 2010L, >> 2011L, 1990L, 1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L, >> 1998L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L, >> 2007L, 2008L, 2009L, 2010L, 2011L, 1990L, 1991L, 1992L, 1993L, >> 1994L, 1995L, 1996L, 1997L, 1998L, 1999L, 2000L, 2001L, 2002L, >> 2003L, 2004L, 2005L, 2006L, 2007L, 2008L, 2009L, 2010L, 2011L, >> 1990L, 1991L, 1992L, 1993L, 1994L, 1995L, 1996L, 1997L, 1998L, >> 1999L, 1999L, 2000L, 2001L, 2002L, 2003L, 2004L, 2005L, 2006L, >> 2007L, 2008L, 2009L, 2010L, 2011L), country = structure(c(1L, >> 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, >> 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, >> 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 4L, 4L, 4L, 4L, 4L, 4L, >> 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, >> 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, >> 3L, 3L, 3L, 3L, 3L, 3L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, >> 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L), .Label = c("Canada", >> "Cuba", "Dominican Republic", "Haiti", "Jamaica"), class = "factor"), >> Y = c(1L, NA, 1L, 1L, 1L, NA, 1L, NA, 1L, NA, 1L, NA, 1L, >> 1L, NA, 1L, NA, 1L, NA, 1L, NA, NA, 1L, 1L, NA, NA, 1L, NA, >> 1L, NA, 1L, NA, 1L, 1L, 1L, 1L, NA, 1L, NA, 1L, NA, 1L, NA, >> NA, 1L, NA, 1L, 0L, 0L, 0L, 1L, NA, 0L, 1L, 0L, 0L, 0L, 0L, >> 0L, 1L, NA, 0L, 1L, 1L, NA, 0L, 1L, NA, 1L, NA, 1L, NA, 1L, >> NA, 1L, NA, 1L, 1L, 1L, 1L, NA, 1L, NA, 1L, NA, 1L, NA, 1L, >> 0L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 1L, 1L, NA, 0L, 1L, 1L, 1L, >> NA, 1L, NA, 0L, 1L, 1L, NA), X = c(1L, 0L, 0L, 1L, 0L, 0L, >> 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, >> 0L, 1L, 0L, 0L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, >> 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, >> 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 0L, >> 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, >> 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, >> 1L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 0L, 0L, 1L, 0L, 0L)), .Names = >> c("year", >> "country", "Y", "X"), class = "data.frame", row.names = c(NA, >> -110L)) >> >> >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.