-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
I have pointed out already: This is a LyX question - please ask on their
mailing list
(http://www.lyx.org/MailingLists#toc2 and
http://dir.gmane.org/gmane.editors.lyx.general)
There are many users who use LyX / sweave or knitr / R under Ubuntu!
Rai
Hi Sebastian
I think I found the package by accident when I did a search of the
Cran package page for"latex" but did not use it as it could not do a
very particular problem.
If there was no other alternative use the add.to.row argument of xtable
A while ago I needed to add some info from the
It is actually much easier to do it under Ubuntu; see a video here:
http://yihui.name/knitr/demo/lyx/ If you want to use Sweave instead of
knitr, there is also a module for it.
The official documentation is here:
- https://github.com/downloads/yihui/lyx/sweave.pdf
- https://github.com/downloads/y
By "Connect" I meant to say that I was able to write code chunks in LYX and
compile them within LYX( using R) to produce results along with other
stuffs.
There are many tutorials available for doing this under Windows but I could
not solve the problem for linux (UBUNTU).
-Atanu
--
View thi
I am not sure you have expressed what you wanjt to do correctly. See inline:
On Wed, Oct 10, 2012 at 9:10 PM, andrewH wrote:
> I have a couple of hundred American Community Survey Summary Files files
> containing rectangular arrays of data, mainly though not exclusively
> numeric. Each file is r
I have a couple of hundred American Community Survey Summary Files files
containing rectangular arrays of data, mainly though not exclusively
numeric. Each file is referred to as a sequence (henceforth "seq"). From
these files I am trying to extract particular subsets (tables) consisting of
a set
Dear Anthony,
You have been so so helpful! The par() example code has worked well.
Thanks,
Pradip
From: Anthony Damico [ajdam...@gmail.com]
Sent: Wednesday, October 10, 2012 5:25 PM
To: Muhuri, Pradip (SAMH/CBHSQ)
Cc: R help
Subject: Re: [R] svyplot
ht
HI,
If you have a lot of variables and in no order, then it would be better to
order the data by column names.
For e.g.
set.seed(432)
dat2<-data.frame(apple_pre=sample(10:20,5,replace=TRUE),orange_post=sample(18:28,5,replace=TRUE),banana_pre=sample(25:35,5,replace=TRUE),apple_post=sample(20:30,5,
I forgot that you were looking for whole numbers:
> Zfact <- data.frame(factor=LETTERS[1:3], low=c(.5, 4.5, 9.5),
high=c(4.499, 9.499, 12.499))
> Zfact
factor low high
1 A 0.5 4.499
2 B 4.5 9.499
3 C 9.5 12.499
> set.seed(42)
> a$Zval <- round(runif(nrow(a), Zfact$low[as
This should work:
> a <- data.frame(X=rnorm(25, 20, 4), Y=rnorm(25, 15, 3),
Z=sample(c(LETTERS[1:3]), 25, replace=TRUE))
> head(a)
X Y Z
1 17.77449 14.425221 B
2 19.95400 13.408439 A
3 13.40162 12.219984 A
4 15.89822 19.214026 B
5 18.55717 14.568691 B
6 19.86619 11.60
HI,
A typo in my solution:
row.names(res2)<-unlist(unique(lapply(strsplit(colnames(dat2),"_"),`[`,1)))
A.K.
- Original Message -
From: "Nundy, Shantanu"
To: "r-help@r-project.org"
Cc:
Se
HI,
May be this helps you.
set.seed(1)
dat2<-data.frame(apple_pre=sample(10:20,5,replace=TRUE),banana_pre=sample(25:35,5,replace=TRUE),apple_post=sample(20:30,5,replace=TRUE),banana_post=sample(40:50,5,replace=TRUE))
list2<-list(dat2[regmatches(colnames(dat2),regexpr("apple.*",colnames(dat2)))],dat
Luis Huckstadt ucsc.edu> writes:
> I'm running into some computer issues when trying to run a binomial model
> for spatially correlated data using glmmPQL and was wondering if anyone
> could help me out.
> My whole dataset consists of about 300,000 points for which I have a suite
> of environment
Rui Barradas sapo.pt> writes:
> It's in the source code for `?`, file src/library/utils/R/question.R,
> lines 32 to 35.
>
See:
https://github.com/wch/r-source/commit/34b3998c928fbf50e24ab0e33c7d72ab8c944330
__
R-help@r-project.org mailing list
htt
On Oct 10, 2012, at 6:45 PM, jim holtman wrote:
> This is a classic example from my tag line:
>
> Tell me what you want to do, not how you want to do it.
>
> For example you provided no information as to what the objects were.
> I hope that 'stratID' is at least of length one greater than 'x'
Hi David,
this looks very promising, but I am afraid I can't see clearly how this would
work.
If possible, would you mind a short explanation? perhaps using the attached
exampled?
Thank you for your advice,
Sebastian
On Oct 10, 2012, at 9:16 PM, David Winsemius wrote:
>
> On Oct 10, 2012
nserdar hotmail.com> writes:
>
>
> I need a "Hessian" matrix in "nlmnib" package to discuss whether parameters
> are significant or not.
>
> Please let me know how to obtain hessian matrix and how to evaluate the
> significancy of parameters.
>
You can get a finite-difference approximatio
This is a classic example from my tag line:
Tell me what you want to do, not how you want to do it.
For example you provided no information as to what the objects were.
I hope that 'stratID' is at least of length one greater than 'x' based
on your loops. Also on the last iteration you are tryin
Hello,
Could you post a data example? Using, with data.frame named 'dat'
dput( head(dat, 30) ) # paste the output of this in a post
I have written code that creates pairs pre/post columns but it can't
really be tested.
Hope this helps,
Rui Barradas
Em 11-10-2012 00:09, Nundy, Shantanu escr
You need to include how many random numbers you want to create; you
are asking for only 1, that is why they are are the same. You
probably want something like:
a$Z<-ifelse(a$Z=="L"
,sample(1:4, nrow(a), TRUE)
,ifelse(a$Z=="M"
,sample(5:9, nrow(a), TRUE)
,ifelse(a$Z=="U"
Please don't double post.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playin
On Oct 10, 2012, at 4:45 PM, Sebastian Barfort wrote:
> I am also interested in the standard errors, but beneath not next to the
> point estimates which is standard in the xtable package.
Last year Mark Difford offered code to do that.
From: Mark Difford
Subject:Re:
sample(Range,1) generates 1 random number. Change that
(in all 3 places) to sample(Range, length(a$Z), replace=TRUE)
to get length(a$Z) random numbers in the same range.
There are other ways to do this with less typing.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Me
I have a data set (a) with three columns (X,Y,Z). The first 2 columns are
numeric. The third (Z) is a factor with three levels A,B,C. I want to turn
each A into a different random number between 1 and 4, each B into a
different random number between 5 and 8, etc.
I tried this:
a$Z<-ifelse(a$Z=="L
I have a data set (a) with 3 columns (X,Y,Z). The first 2 columns are
numerical. The third column (Z) is a factor with three levels ("A","B","C").
What I want to do is turn each of the "A's" into different random numbers
between 1 and 4, "B's" into a random number between 5 and 8, etc.
I tried thi
I am also interested in the standard errors, but beneath not next to the point
estimates which is standard in the xtable package.
If you by any chance remember the name of the package or how to do it that
would be much appreciated!
Cheers,
Sebastian
On Oct 10, 2012, at 7:10 PM, Duncan Mackay
Hi A.K,
thanks for the suggestion. Unfortunately, it's not really what I'm looking for.
I'm looking for a package or some function that can create the point estimate
in the first row with the standard error in parenthesis in the second which is
not what you normally get from the xtable package.
Hi everyone-
I have a dataset with multiple "pre" and "post" variables I want to compare.
The variables are named "apple_pre" or "pre_banana" with the corresponding post
variables named "apple_post" or "post_banana". The variables are in no
particular order.
apple_pre orange_pre orange_post pr
Dear R Help,
I have two nested negative log-likelihood functions that I am optimizing
with the spg function [BB package]. I would like to perform model
selection on these two objective functions using AIC (and possibly
anova() too). However, the spg() function returns a list and I need a
fi
Hi John,I installed & but somehow it did not work on my computer, while I tried
another computer - it works.
Thanks for all your communications.Best,Zhengyu
Date: Tue, 9 Oct 2012 05:16:59 -0800
From: jrkrid...@inbox.com
Subject: RE: [R] smoothScatter plot
To: zhyjiang2...@hotmail.com
Glad i
Hi
If you just want the coefficients.
xtable(summary(fe)$coef)
% latex table generated in R 2.15.1 by xtable 1.7-0 package
% Thu Oct 11 09:04:59 2012
\begin{table}[ht]
\begin{center}
\begin{tabular}{r}
\hline
& Estimate & Std. Error & t-value & Pr($>$$|$t$|$) \\
\hline
x & 0.12 & 0.07
see inline below.
On Tue, Oct 9, 2012 at 10:35 AM, Rantony wrote:
> Hi,
>
> i wanted to send a mail from R (using Eclips).
> Currently i installed the following packages
> base64_1.1
> sendmailR_1.1-1
> mail_1.0.tar.gz
> Rmail_1.1.tar.gz
>
> But while installing package some error was occuring.
On Thu, Oct 11, 2012 at 11:18 AM, R. Michael Weylandt
wrote:
> Thanks Prof Lumley,
>
> I'm still not sure how this gets to the call stack of 5 or 6 the OP
> reported or the difference between GUI & Terminal. Any thoughts there?
I don't see how the terminal version is getting 5 and 6 rather than
Hi,
here is one way using ddply (from the plyr package):
dat <- read.table(text="tdate stock_symbolexpiration strike
9/11/2012 C 9/16/201211
9/11/2012 C 9/16/201212
9/11/2012 C 9/16/201
Hi everybody,
I am trying to fit a GAM model without intercept using library mgcv.
However, the result has nothing to do with the observed data. In fact
the predicted points are far from the predicted points obtained from the
model with intercept. For example:
#First I generate some simulated
Hi,
You can also try with aggregate() or ddply()
dat2<-aggregate(dat,list(dat$stock_symbol,dat$tdate),FUN=function(x) head(x,1))
dat2[,3:6]
# tdate stock_symbol expiration strike
#1 9/11/2012 C 9/16/2012 11
#2 9/12/2012 C 9/16/2012 14
library(plyr)
ddply(da
On Wed, Oct 10, 2012 at 3:35 PM, Baoqiang Cao wrote:
> Hi,
>
> I have a question about using lm on matrix, have to admit it is very
> trivial but I just couldn't find the answer after searched the mailing
> list and other online tutorial. It would be great if you could help.
>
> I have a matrix "t
On Mon, Oct 8, 2012 at 8:29 PM, Jhope wrote:
> Hi Michael,
>
> I am very willing to subscribe to where you think is appropriate but I
> thought I was subscribed.
>
> I have a password that I can log into Nabble with and I receive update
> emails from the R-help forum constantly in to my inbox [R]
On Tue, Oct 9, 2012 at 10:54 PM, marsyxp wrote:
> I am using Donlp2 package to solve a non-linear problem, but there's an error
> I always meet:
>
> Error in matrix(unlist(value, recursive = FALSE, use.names = FALSE), nrow =
> nr, :
> attempt to set an attribute on NULL
>
> I have been sufferin
On Wed, Oct 10, 2012 at 10:04 PM, Thomas Lumley wrote:
> On Thu, Oct 11, 2012 at 9:05 AM, R. Michael Weylandt
> wrote:
>> Can someone more capable than I help Martin out with this? I'm feeling
>> out of my league (that or I've missed something obvious)
>>
>> Shot in the dark: you aren't running t
As for interactive plots, there is also aplpack (sliders for changing the
width of histograms, and density plots; iPlots; and iWebPlots.
--
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77843-4352
> -
On Oct 10, 2012, at 11:09 AM, ramoss wrote:
> Hello,
>
> I am trying to re-code all my programs from SAS into R.
>
> In SAS I use the following code:
>
> proc sort data=upper;
> by tdate stock_symbol expire strike;
> run;
> data upper1;
> set upper;
> by tdate stock_symbol expire strike;
https://stat.ethz.ch/pipermail/r-help/2012-October/324944.html
On Wed, Oct 10, 2012 at 5:05 PM, Muhuri, Pradip (SAMHSA/CBHSQ) <
pradip.muh...@samhsa.hhs.gov> wrote:
> Hello,
>
> Using the svyplot () function, I have plotted four graphs that are saved
> in four different .png files.
>
> I am look
On Oct 10, 2012, at 1:31 PM, Jay Rice wrote:
> New to R and having issues with loops. I am aware that I should use
> vectorization whenever possible and use the apply functions, however,
> sometimes a loop seems necessary.
>
> I have a data set of 2 million rows and have tried run a couple of lo
Hi Jay,
A few comments.
1) As you know, vectorize when possible. Even if you must have a
loop, perhaps you can avoid nested loops or at least speed each
iteration.
2) Write your loop in a function and then byte compile it using the
cmpfun() function from the compiler package. This can help
dram
Hello,
Using the svyplot () function, I have plotted four graphs that are saved in
four different .png files.
I am looking for examples how to redraw the same four graphs within grid
viewports so that they stay together on a page. The goal is to create one .png
file that will include all four
On Thu, Oct 11, 2012 at 9:05 AM, R. Michael Weylandt
wrote:
> Can someone more capable than I help Martin out with this? I'm feeling
> out of my league (that or I've missed something obvious)
>
> Shot in the dark: you aren't running this in some sort of debug mode, are you?
>
> RMW
>
> On Sun, Oct
Hi Stephan,
Now I have your same problem on Granger causality test, have you got some
news about it? The anova.rq is the right one to do it?
Regards,
Massimo
--
View this message in context:
http://r.789695.n4.nabble.com/quantreg-Wald-Test-tp4638198p4645773.html
Sent from the R help mailing lis
#optim package
estimate<-optim(init.par,Linn,hessian=TRUE, method=c("L-BFGS-B"),control =
list(trace=1,abstol=0.001),lower=c(0,0,0,0,-Inf,-Inf,-Inf,-Inf,-Inf,-Inf,-Inf,-Inf,-Inf),upper=c(1,1,1,1,Inf,Inf,Inf,Inf,Inf,Inf,Inf,Inf,Inf))
#nlminb package
estimate<-nlminb(init.par,Linn,gr=NULL,hessian=T
I need a "Hessian" matrix in "nlmnib" package to discuss whether parameters
are significant or not.
Please let me know how to obtain hessian matrix and how to evaluate the
significancy of parameters.
Regards
Serdar
--
View this message in context:
http://r.789695.n4.nabble.com/nlmnib-Packag
New to R and having issues with loops. I am aware that I should use
vectorization whenever possible and use the apply functions, however,
sometimes a loop seems necessary.
I have a data set of 2 million rows and have tried run a couple of loops of
varying complexity to test efficiency. If I do a v
Hello,
I am trying to re-code all my programs from SAS into R.
In SAS I use the following code:
proc sort data=upper;
by tdate stock_symbol expire strike;
run;
data upper1;
set upper;
by tdate stock_symbol expire strike;
if first.expire then output;
rename strike=astrike;
run;
on the
Hello,
I am learning to use the metafor package to conduct meta-regression analyses
for a systematic review on multidisciplinary care interventions in chronic
kidney disease. For the forest plots, I can't figure out how to plot
unadjusted and adjusted models on the same plot. From top to bott
Can someone more capable than I help Martin out with this? I'm feeling
out of my league (that or I've missed something obvious)
Shot in the dark: you aren't running this in some sort of debug mode, are you?
RMW
On Sun, Oct 7, 2012 at 5:10 PM, Martin Ivanov wrote:
> Thank You very much for Your
On Wed, Oct 10, 2012 at 4:47 PM, sagarnikam123 wrote:
> i want to show histogram in innovative way (good if interactive) in html
> report..is threre any tutorials/hint
> also there is any package to show correalation plot
The histogram is well defined, so I'm not really sure how much
innovation y
Your original method would be the following function
f <- function (x, y)
{
xy <- cbind(x, y)
outside <- function(z) {
!any(x > z[1] & y > z[2])
}
j <- apply(xy, 1, outside)
which(j)
}
and the following one quickly computes the same thing as the above
as long as there
There are packages for big data analysis, which is best depends on
what you want to do. The High Performance Computing task view on CRAN
has a section on packages that deal with big data which gives some
more detail and may help you choose which package(s) to use.
On Wed, Oct 10, 2012 at 12:36 AM
Did not see a simple way to make it faster. However, this is a piece of
code which can be made to run much faster in C. See below.
I don't know if you are familiar with running c-code from R. If not, the
official documentation is in the R Extensions manual. However, this is
not the most easy
Sorry, not one of my days. Forgot to Cc the list.
Rui barradas
Em 10-10-2012 20:28, Sarah Goslee escreveu:
Sent just to me?
On Wed, Oct 10, 2012 at 3:26 PM, Rui Barradas wrote:
You're right, apologies to the op and the list. I was thinking of the more
complicated
as.numeric(levels(abc)[abc[1
I think David was saying the humor was unsuccessful (i.e., Christian
didn't get the joke), not that the code was.
Cheers,
RMW
On Wed, Oct 10, 2012 at 7:16 PM, Rui Barradas wrote:
> Unsuccessfull? Why unsuccessfull? Have you noticed the call to rpois? It
> beats runif by potential infinity.
>
> R
HI,
May be you can use library(texreg):
library(plm)
#generating some data
x <- rnorm(270)
y <- rnorm(270)
t <- rep(1:3,30)
i <- rep(1:90, each=3)
data <- data.frame(i,t,x,y)
fe <- plm(y~x,data=data,model="within")
summary(fe)
library(texreg)
fe1<-extract.plm(fe) #extract the plm object
libra
Rui, that doesn't answer the question as I understood it:
Your suggestion returns the numeric value of the second value of the levels:
> as.numeric(levels(abc)[2])
[1] 3
But I read the question as wanting the numeric value of the second
element of abc:
> as.numeric(as.character(abc[2]))
[1] 2
O
Hello,
Try instead
?levels
abc <- factor(c(2,2,3,4,7,7))
as.numeric(levels(abc)[1])
Hope this helps,
Rui Barradas
Em 10-10-2012 19:39, Brigid Mooney escreveu:
Sorry, I'm sure I'm not using the appropriate vocab here, which is
undoubtedly why I can't seem to find a fix to this (hopefully very
Hi Brigid,
as.numeric() extracts the index of the factor level, which is the way
R handles the likelihood that a factor is not actually numeric. Try:
> as.numeric(as.character(abc[1]))
[1] 2
and see also ?factor particularly the section on the interpretation of a factor.
Sarah
On Wed, Oct 10,
Sorry, I'm sure I'm not using the appropriate vocab here, which is
undoubtedly why I can't seem to find a fix to this (hopefully very
easy) problem.
Suppose you have a factor
abc <- factor(c(2,2,3,4,7,7))
And you want to know what the number in the nth spot in that would be
abc[1]
[1] 2
Levels:
It might help if you would bore us with at least one or two of the things
you have tried. It seems logical to read the file into a data frame using
read.table(). Then you can change it into any format you want:
> Listname <- read.table(text="key value
Key1 1
Key2 2
Key3 3", header=TRUE)
> Listname
Unsuccessfull? Why unsuccessfull? Have you noticed the call to rpois? It
beats runif by potential infinity.
Rui Barradas
Em 10-10-2012 18:30, David Winsemius escreveu:
On Oct 10, 2012, at 9:59 AM, Christian Hoffmann wrote:
What does the sudden appearance of "Contacting Delphi ..the oracle
Hello!
I'd like to know if it is correct to
test with anova two models specified like this:
m1=y~x1+s(x2,by=x3),family="poisson"
m0=y~x1+s(x2),family="poisson"
anova(m1,m0)
Cheers
Anna
Anna Freni Sterrantino
Department of Statistics
University of Bologna, Italy
via Belle Arti 41, 40124 BO.
I finally was able to compile/load it under windows 7. I had similar
problems to what you show below.
I set the MYSQL_HOME environmental variable through windows (start
button > control panel > System and Security > system > Advanced
System Settings > Environmental variables). I had to set it to
Its suddenness is only as sudden as your input that triggered it. Its oblique
nature is a reflection of the nature of your input.
http://lmgtfy.com/?q=R+contacting+Delphi+oracle+is+unavailable
---
Jeff Newmiller
HI,
By modifying the earlier solution using sapply()
set.seed(1)
dat1<-data.frame(keys=paste0("key",1:5),value=sample(1:15,5,replace=TRUE))
list2<-sapply(split(dat1,dat1$keys),`[`,2)
names(list2)<-dat1[,1]
list2$key2
#[1] 6
A.K.
- Original Message -
From: VA Smith
To: r-help@r-project
On Tue, Oct 9, 2012 at 10:35 AM, Jessica Streicher
wrote:
> Can i somehow append objects to an .Rdata file?
>
> I didn't see an option for it in the save() method.
>
> dump() won't work since i have s4 objects in there.
I'm not sure I completely understand the issues you're trying to work
around
Hi,
May be this:
set.seed(1)
dat1<-data.frame(keys=paste0("key",1:5),value=sample(1:15,5,replace=TRUE))
list1<-lapply(split(dat1,dat1$keys),`[`,2)
list1$key2
# value
#2 6
A.K.
- Original Message -
From: VA Smith
To: r-help@r-project.org
Cc:
Sent: Wednesday, October 10, 2012 1:29
Hello,
It's in the source code for `?`, file src/library/utils/R/question.R,
lines 32 to 35.
32cat("Contacting Delphi...")
33 flush.console()
34Sys.sleep(2+rpois(1,2))
35cat("the oracle is unavailable.\nWe apologize for any
inconvenience.\n")
36return(in
Apologies - I feel this is a very simple thing to do yet I am failing
massively. I keep finding information about how to do much more complicated
things (usually on this mailing list!), which then fail when I try to apply
it to my simple task.
Anyway, all I want to do is read in a series of key-va
On Oct 10, 2012, at 9:59 AM, Christian Hoffmann wrote:
> What does the sudden appearance of "Contacting Delphi ..the oracle is
> unavailable.
> We apologize for any inconvenience." mean? A bug? It appears at plotting.
In this instance an unsuccessful attempt at humor:
http://markmail.org/s
On Oct 10, 2012, at 7:58 AM, namrata mohapatra wrote:
> Hello
>
> I am interested to plot a contour plot using the colour : rainbow , however I
> want to reverse the order of the colour ( such that red represents max value
> and blue min value) and also remove the lines in white in the plot .
HI,
May be this helps you:
Using the dataset iris:
by.list<-by(iris, iris$Species, summary)
dat1<-do.call(rbind,lapply(by.list,function(x) gsub(".*\\:","",x)))
row.names(dat1)<-paste(rep(unlist(dimnames(by.list),use.names=F),each=6),unlist(lapply(lapply(by.list,`[`,1:6),function(x)
gsub("\\:.*"
Dear all,
I am trying to export my fixed effect results to Latex. I am using the plm
package with the summary function. However, it does not look like apsrtable,
stargazer, or any other package can accompany using the plm package.
I am interested in a classic table with the coefficient in one
Hi,
history()
gives Error in savehistory(file) : no history available to save
although I can scroll throu history with C^uparrow an C^downarrow.
How can I make history() work
and/or show the current history in a *file*, so that I can choose from
previous commands?
The notion of having re
On Wed, Oct 10, 2012 at 12:52 PM, Christian Hoffmann
wrote:
>
> Am 10.10.12 18:17, schrieb Steve Lianoglou:
>
>> Hi,
>>
>> On Wed, Oct 10, 2012 at 12:03 PM, Christian Hoffmann
>> wrote:
>>>
>>> Hi,
>>>
history()
>>>
>>> gives Error in savehistory(file) : no history available to save
>>>
>>>
Hi all,
I'm running into some computer issues when trying to run a binomial model
for spatially correlated data using glmmPQL and was wondering if anyone
could help me out.
My whole dataset consists of about 300,000 points for which I have a suite
of environmental variables (I'm trying to come up
What does the sudden appearance of "Contacting Delphi ..the oracle
is unavailable.
We apologize for any inconvenience." mean? A bug? It appears at plotting.
Thanks
Christian
--
Christian W. Hoffmann,
CH - 8915 Hausen am Albis, Switzerland
Rigiblickstrasse 15 b, Tel.+41-44-7640853
c-w.hoffm
No, the desired points are not a subset of the convex hull.
E.g., x=c(0,1:5), y=c(0,1/(1:5)).
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: William Dunlap
> Sent: Wednesday, October 10, 2012 9:46 AM
> To: 'tonja.krue...@web.de'; r-help@r-project.org
Are the points you are looking for (those data points with no other data
points above or to the right of them) a subset of the convex hull of the
data points? If so, chull(x,y) can quickly give you the points on the convex
hull (typically a fairly small number) and you can look through them for
th
> * Prof Brian Ripley [2012-10-08 06:37:07 +0100]:
>
> On 08/10/2012 02:57, Peter Ehlers wrote:
>> On 2012-10-07 14:44, Sam Steingold wrote:
* Peter Ehlers [2012-10-07 10:03:42 -0700]:
On 2012-10-07 08:34, Sam Steingold wrote:
> I know it does not look very good - using the sam
What do you mean by "connect"? And how did you succeed under Windows?
i.e. what is your expectation?
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Wed, Oct 10, 2012 at 4:57 AM, ATANU wrote:
In addition to Bert's answer. If the 0 and/or 100 are hard boundaries
(you know that values cannot be outside those values) and you have
data points near one or both of the bounds, then the functions in the
logspline package may be of use.
On Tue, Oct 9, 2012 at 2:38 PM, Bert Gunter wrote:
> ??
Hi,
On Wed, Oct 10, 2012 at 12:03 PM, Christian Hoffmann
wrote:
> Hi,
>
>> history()
>
> gives Error in savehistory(file) : no history available to save
>
> although I can scroll throu history with C^uparrow an C^downarrow.
>
> How can I make history() work and/or show the current history in a fi
Hi,
> history()
gives Error in savehistory(file) : no history available to save
although I can scroll throu history with C^uparrow an C^downarrow.
How can I make history() work and/or show the current history in a file,
so that I can choose from previous commands?
The web did not throw up a
Hi,
This answer may be a bit overdue, but I had a similar problem and it took
me quite some time to find a good solution. When searching with google,
your post kept showing up, so I post this to help others.
The command that worked for me was interaction.plot.
Example:
x <- data.frame(Score=rno
i want to show histogram in innovative way (good if interactive) in html
report..is threre any tutorials/hint
also there is any package to show correalation plot
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Sent from the R help mailing
Hello,
Your model is equivalent to the model below. As for standard errors, try
predict.lm with the appropriate argument.
?predict.lm
model <- lm(decrease ~ rowpos + colpos*treatment, data = OrchardSprays)
predict(model, se.fit = TRUE, interval = "confidence")
Hope this helps,
Rui Barradas
E
Hello,
If 'by' is giving you trouble, why not 'aggregate'?
agg.df <- aggregate(iris, list(iris$Species), FUN = summary)
str(agg.df)
Hope this helps,
Rui Barradas
Em 10-10-2012 15:02, Alex van der Spek escreveu:
Thank you Petr,
Try this
str(by(iris, iris$Species, summary))
and you will see
On 10/10/2012 10:56 AM, R. Michael Weylandt wrote:
write.table() should append just fine. write.csv() doesn't append I'm
told because there's no guarantee it matches the column headings of
the original file. That said, write.table(..., append = TRUE, sep =
",") is a pretty good approximation.
Y
Hi Bert,
I just looked at An Introduction to R - and I do apologize if my questions
are trivial. I see that they use predict as a function in lm, but I'm not
sure how to incorporate it into a command.
Thank you,
S
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On Wed, Oct 10, 2012 at 4:09 PM, Poizot Emmanuel
wrote:
> Le 10/10/2012 17:02, R. Michael Weylandt a écrit :
>>
>> Change 1 to some other number to get more points from runif()
>>
>> More generally, take a look at "An Introduction to R" and read most
>> everything you can find on the topic of vect
On 10-10-2012, at 16:15, Poizot Emmanuel wrote:
> Dear all,
>
> I have two coordinates vectors, say X and Y of length n.
> I want to generate for each couple of coordinates X1,Y1 X2,Y2 X3,Y3Xn,Yn
> a random coordinate which is located in a square define as X +/- dx and Y +/-
> dy.
> I saw
Change 1 to some other number to get more points from runif()
More generally, take a look at "An Introduction to R" and read most
everything you can find on the topic of vectorization. If you don't
know how to get "An Introduction to R", try typing help.start() at
your prompt and it should happen
write.table() should append just fine. write.csv() doesn't append I'm
told because there's no guarantee it matches the column headings of
the original file. That said, write.table(..., append = TRUE, sep =
",") is a pretty good approximation.
Cheers,
Michael
On Wed, Oct 10, 2012 at 3:44 PM, Alex
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