Rui, that doesn't answer the question as I understood it: Your suggestion returns the numeric value of the second value of the levels: > as.numeric(levels(abc)[2]) [1] 3
But I read the question as wanting the numeric value of the second element of abc: > as.numeric(as.character(abc[2])) [1] 2 On Wed, Oct 10, 2012 at 2:52 PM, Rui Barradas <ruipbarra...@sapo.pt> wrote: > Hello, > > Try instead > > ?levels > abc <- factor(c(2,2,3,4,7,7)) > as.numeric(levels(abc)[1]) > > Hope this helps, > > Rui Barradas > Em 10-10-2012 19:39, Brigid Mooney escreveu: > >> Sorry, I'm sure I'm not using the appropriate vocab here, which is >> undoubtedly why I can't seem to find a fix to this (hopefully very >> easy) problem. >> >> Suppose you have a factor >> >> abc <- factor(c(2,2,3,4,7,7)) >> >> And you want to know what the number in the nth spot in that would be >> >> abc[1] >> [1] 2 >> Levels: 2 3 4 7 >> >> shows the correct label of the first element - but if I want to pull >> out the numeric value of that label, I thought... >> >> as.numeric(abc[1]) >> >> but that gives >> [1] 1 >> >> which is the position of the label in the levels vector of the factor. >> >> Ideas? >> >> Thanks! >> -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
