You need to include how many random numbers you want to create; you
are asking for only 1, that is why they are are the same. You
probably want something like:
a$Z<-ifelse(a$Z=="L"
,sample(1:4, nrow(a), TRUE)
,ifelse(a$Z=="M"
,sample(5:9, nrow(a), TRUE)
,ifelse(a$Z=="U"
,sample(10:12, nrow(a), TRUE)
, -42 # you had a character which would have converted
everything to character
)
)
)
On Wed, Oct 10, 2012 at 8:36 PM, KoopaTrooper <ncoop...@tulane.edu> wrote:
> I have a data set (a) with three columns (X,Y,Z). The first 2 columns are
> numeric. The third (Z) is a factor with three levels A,B,C. I want to turn
> each A into a different random number between 1 and 4, each B into a
> different random number between 5 and 8, etc.
>
> I tried this:
>
> a$Z<-ifelse(a$Z=="L",sample(1:4,1),ifelse(a$Z=="M",sample(5:9,1),ifelse(a$Z=="U",sample(10:12,1),"")
>
> and it almost worked but changed all the "A's" into the same random number.
> I need a different random number for each A. Ideas?
>
> Thanks,
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Converting-factors-to-bounded-random-numerical-data-tp4645801.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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