I am trying to implement some expert rules based on the presence or absence
of words in a sentence. I have given a reproducible example below. In this,
every time I come across the words lunch and bag in the same sentence, the
outcome would be 1. If lunch and pack are in the same sentence, then the
Janos,
Vegan has just been updated due to a problem with BiodiversityR and R 2.13,
not sure if its the same issue you are having, but updating vegan could be
worth a try.
Graham
On 1 June 2011 20:08, János Korponai wrote:
> Dear List!
>
> I installed R and quite a few packages I use. When I
Dear Dennis, Dear Peter,
thank you very much, as.character() worked perfectly. Nice solution :-)
All the best,
Marius
On 2011-06-03, at 03:42 , Dennis Murphy wrote:
> If you're trying to figure out a way to embolden a Greek letter in
> plotmath, it ain't gonna happen. From the plotmath help pa
On Jun 2, 2011, at 11:48 PM, Nipesh Bajaj wrote:
This is how strange? How and from where I would know that I need to
install something pdflatex separately? Can you point some legitimate
link which says I need to install that (like Rtools?) Even this link
'http://www.math.rug.nl/~trentelman/jaco
On Jun 2, 2011, at 11:21 PM, Soyoung Jang wrote:
The following are the first 6 rows of the data...I named it "file"
and I have no idea how I can extract column 15,
But, how did you make it. Is it a data.frame or a matrix?
because there are no headers in this data.Can you please help me
On Jun 2, 2011, at 10:54 PM, Rolf Turner wrote:
> On 03/06/11 10:26, CAB wrote:
>> Dear R users
>> I am modifying a column chart which I have created in R using barplot to
>> make it clearer. I have been able to change the settings to increase the
>> width of the axes lines and the text size but
Hi,
I use MikTeX on Windows and it works like a charm. Here's the link:
http://www.miktex.org/ I chose it after reading the installation
manual:
http://cran.r-project.org/doc/manuals/R-admin.html
The entire thing is very helpful, but particularly note Appendix D,
where you will find that for a
On the same token, is it possible to run a mlogit on a data set that has
differing numbers of "alt.vars"?
would this dataset be valid with the addition of the below bolded record?
1 1 air no 695910070 351
2 1 train no 343137271
The following are the first 6 rows of the data...I named it "file" and I have
no idea how I can extract column 15, because there are no headers in this
data.Can you please help me with that?
Thank you!
40 37 1 1 8 8 40 40 1 7 1 0 40 041344 716049158 21643 3246 1 4 2
25240 1
Here is one way you might do it.
> con <- textConnection("
+ characteristics_ch1.3 Stage: T1N0 Stage: T2N1
+ Stage: T0N0 Stage: T1N0 Stage: T0N3
+ ")
> txt <- scan(con, what = "")
Read 11 items
> close(con)
>
> Ts <- grep("^T", txt, value = TRUE)
> Ts <- sub("T([[:digit:]]+)N([[:digit:]]+)",
On 03/06/11 10:26, CAB wrote:
Dear R users
I am modifying a column chart which I have created in R using barplot to
make it clearer. I have been able to change the settings to increase the
width of the axes lines and the text size but I cannot find the code to
change the width of the lines which
This is how strange? How and from where I would know that I need to
install something pdflatex separately? Can you point some legitimate
link which says I need to install that (like Rtools?) Even this link
'http://www.math.rug.nl/~trentelman/jacob/pdflatex/pdflatex.html' do
not provide any download
You're still not reading the Help carefully/thoroughly.
Check the entry under the "relation" subargument for the "scales"
argument of xyplot. You need relation = "same", which is the default
and so can be omitted.
-- Bert
On Thu, Jun 2, 2011 at 2:02 PM, maxbre wrote:
> ok thanks again for your
Ungku Akashah [Thu, Jun 02, 2011 at 10:31:53AM CEST]:
> Error in lda.default(x, grouping, ...) :
> variables 1 3 5 8 10 15 17 20 27 29 34 appear to be constant within
> groups
Please do read the posting guide before posing a question here.
The message would have benefitted from a title. M
try folllowing in general
>?ecdf
but what vector input consists of..??
On 3 June 2011 01:19, Alaios wrote:
> Dear all,
> do you know any easy way based on a vector input how to plot easily cdf and
> pdf.
>
> I would like to thank you in advance for your help
>
> Regards
> Alex
>
> ___
Hello cmaster1331,
I had asked a similar question sometime back. You may want to check out
these responses that I got.
A) http://code.google.com/p/gridextra/wiki/tableGrob
B)
1) latex (via xtable, Hmisc, r2lh, reporttools ...)
2) html (via xtable, r2lh, R2HTML, hwritter, HTMLUtils ...)
3) graphi
Look at the logspline package for one approach to doing this.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of teriri
Sent: Thursday, June 02, 2011 12:19 AM
To: r-help@r-project.org
Subject: [R] [Plea to the R Gods] Theoretical and E
On Jun 2, 2011, at 4:08 PM, Mark Aquino wrote:
Hi,
I have what would seem to be a very simple problem but have been
unable to find any way to go about solving it:
I am using heatmap.2 to create a heatmap and by default the x axis
label is at the bottom of the heatmap, I simply want to move
Hi,
I'm using the package gnm to perform non-linear models and I cannot
find how to write the formula for a power function model.
The equation is something like (1) y ~ A * x^B or (2)y ~ A *
B^x.
I guess it is using the nonlin function Mult(), but couldn't find how.
Thank you for y
Dear R users
I am modifying a column chart which I have created in R using barplot to
make it clearer. I have been able to change the settings to increase the
width of the axes lines and the text size but I cannot find the code to
change the width of the lines which create the bars/columns themselv
ok thanks again for your reply: this is what I worked out so far
#start code
xyplot(ped.avg ~ tv.avg | family,
data=mydata,
strip=strip.custom(bg='white'), col.line=1, main="title",
xlab = expression(paste('tv [ fg/', m^3, ' ]', sep = '')),
Hi all,
So my question is pretty simple, but unfortunately I have not been able to
find a good answer after extensive google searches.
I am trying to plot an "attractive" data table in R, such as:
http://t2.gstatic.com/images?q=tbn:ANd9GcRjfTbTEUWlnb73wtUkY1mbQblWA-2EKEgvTLXGzkqUSpH4mWrk
Such d
Hi
I would like to use the newton raphson method to find the root if the
equation x^3-0.165*x+0.0003993 without using any readliy available program
in r but instead by writing my own code and loop. the problem is that i
really cant understand how to write the loop so that it keeps using the last
Here is another solution, using apply() and lapply().
# list of sequences corresponding to each row in data1:
seqlist <- apply(data1, 1, function(x)seq(from=x[1], to=x[2]))
# Find which rows of data2 are inside those sequences:
rowsInSeq<- unlist(lapply(seqlist , function(x)which(data2$position
Hi,
I have what would seem to be a very simple problem but have been unable to find
any way to go about solving it:
I am using heatmap.2 to create a heatmap and by default the x axis label is at
the bottom of the heatmap, I simply want to move the label to the top of the
heatmap. Any help with
Hello! Haha, I am not doing this for a class...just trying to teach myself a
few things or two. Thank you both for the responses. I really appreciate it.
--
View this message in context:
http://r.789695.n4.nabble.com/Plea-to-the-R-Gods-Theoretical-and-Empirical-CDFs-tp3567636p3569609.html
Sent f
I am using MuMIn and LME4 for model averaging. Does anyone know if there is a
way to constrain the estimates of random effects to specific values?
--
View this message in context:
http://r.789695.n4.nabble.com/Constraining-estimates-for-random-effects-tp3569250p3569250.html
Sent from the R he
Hi all,
I would like to ask whether anyone knows if the censorReg in S-plus regress the
mean survival model or the hazard and if it uses the maximum likelihood in
order to estimate the values?
In addition, is there anyone knowing why censorReg does not exist in R and
what's the difference betwee
List members,
Via searches I've seen similar discussion of this topic but have not seen
resolution of the particular issue I am experiencing. If my search on this
topic failed, I apologize for the redundancy. I am attempting to generate
random covariance matrices but would like the corresponding c
Hi,
I'm trying to implement the DBSCAN algorithm to get O(N*LogN) complexity
and I'd need a spatial tree of some sort (kd,r,bd..), or a function that
computes radius-based search on spatial data, i.e. given a radius eps
finds ALL the points which fall in the corresponding hypersphere
centered
I have a dataset that looks like:
set.seed(144)
sam<-sample(1000,100)
dat<-data.frame(id=letters[1:10],value=rnorm(1000),day=c(rep(1,100),rep(2,100),rep(3,100),rep(4,100),rep(5,100)))
I want to "normalise" it using the following function (unless you have
a better idea...):
adj.values<-function(
On 02/06/2011 5:03 PM, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages. I use graphics like this
plot(1, main="
On 02/06/2011 2:30 PM, Nipesh Bajaj wrote:
What else I need to do? In the Read-and-delete-me file following steps
are asked to perform:
* Edit the help file skeletons in 'man', possibly combining help files
for multiple functions.
* Edit the exports in 'NAMESPACE', and add necessary imports.
* Pu
On 03/06/11 12:16, Joshua Wiley wrote:
Okay, that might have been a little strong. "screams bloody murder"
is a warning, not technically an error, and does not occur when simply
running R CMD build. That said, the OP did mention using R CMD check
and pdflatex is not an issue when only building
Okay, that might have been a little strong. "screams bloody murder"
is a warning, not technically an error, and does not occur when simply
running R CMD build. That said, the OP did mention using R CMD check
and pdflatex is not an issue when only building anyway. Still, it is
not the cause of th
On Thu, Jun 2, 2011 at 4:49 PM, Rolf Turner wrote:
> On 03/06/11 11:33, Joshua Wiley wrote:
>>
>> Hi,
>>
>> On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajaj
>> wrote:
>>>
>>> I editied the help page for fn1() function (as I already communicated
>>> in previous mail) as follows:
>>> \name{fn1}
>>> \a
On 03/06/11 11:33, Joshua Wiley wrote:
Hi,
On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajaj wrote:
I editied the help page for fn1() function (as I already communicated
in previous mail) as follows:
\name{fn1}
\alias{fn1}
\title{
A function.
}
\description{
A function.
}
\usage{
A function.
W
> Absolutely not! Did you *read* the OP's question? He wants to break
> the line in the code --- for readable code presumably --- but ***not***
> in the output! Your advice is the antithesis of what is required.
>
> cheers,
>
> Rolf Turner
I stand corrected, indeed I missed the cruci
On 03/06/11 10:16, Peter Langfelder wrote:
On Thu, Jun 2, 2011 at 3:13 PM, Rolf Turner wrote:
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my
script
I use break long lines to avoid lines hiden on my monitor and in sweav
Hi,
On Thu, Jun 2, 2011 at 11:30 AM, Nipesh Bajaj wrote:
> I editied the help page for fn1() function (as I already communicated
> in previous mail) as follows:
> \name{fn1}
> \alias{fn1}
>
> \title{
> A function.
> }
>
> \description{
> A function.
> }
>
> \usage{
> A function.
What makes you t
On 2011-06-02 15:50, Marius Hofert wrote:
Dear all,
How can I get a bold "1000" in the title? I would like to use a variable (as opposed to
putting in "1000" directly).
library(lattice)
N<- 1000
xyplot(0~0, xlab.top=list(label=as.expression(bquote(bold("foo" ~ .(N) ~
"bar"))), font=2, cex=1.2
Dear all,
How can I get a bold "1000" in the title? I would like to use a variable (as
opposed to putting in "1000" directly).
library(lattice)
N <- 1000
xyplot(0~0, xlab.top=list(label=as.expression(bquote(bold("foo" ~ .(N) ~
"bar"))), font=2, cex=1.2))
## => "font=2" is ignored (of course)
On Jun 2, 2011, at 6:13 PM, Rolf Turner wrote:
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I
my script
I use break long lines to avoid lines hiden on my monitor and in
sweave
document pages. I use graphics like this
On Jun 2, 2011, at 5:07 PM, Marius Hofert wrote:
Dear Dennis, Dear Uwe, Dear David,
many thanks for helping. Dennis and David, your solutions seemed
perfectly fine, but when I applied it to my original problem, it did
not show a title. Below is a (longer) minimal example (the first
part
On Thu, Jun 2, 2011 at 3:13 PM, Rolf Turner wrote:
> On 03/06/11 09:03, Walmes Zeviani wrote:
>>
>> Hello list,
>>
>> I have plots with long strings in main=, ylab= or xlab=. So, in I my
>> script
>> I use break long lines to avoid lines hiden on my monitor and in sweave
>> document pages. I use g
I don't use windows, but this error message you report:
>>> Error in texi2dvi("Rd2.tex", pdf = (out_ext == "pdf"), quiet = FALSE, :
>>> pdflatex is not available
>>> Error in running tools:: texi2dvi
strongly indicates that you need to install pdflatex, don't you think?
If you don't have non-R co
On 03/06/11 09:03, Walmes Zeviani wrote:
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages. I use graphics like this
plot(1, main="
bbb
Still I am struggling to get some inputs from the experts here :(
Definitely We can shere our experiences once I am done (really, it
seems to me very hard nut to crack!) I strongly feel that related
documentations should be more Statistician-friendly, than some Engg.
guys
Thanks,
On Fri, Jun 3, 2
On Jun 2, 2011, at 1:42 PM, Filippo Beleggia wrote:
> Hi!
>
> I am very new to R, I hope someone can help me.
>
> I have two dataframes:
>
> data1<-data.frame(from=c(1,12,16,40,55,81,101),to=c(10,13,23,45,67,99,123))
> data2<-data.frame(name=c(1,2,3,4,5,6,7,8,9),position=c(2,14,20,50,150,2000,2
I hope you're successful because I'm having issues as well building a simple
package on
windows. maybe when you're finished you can share back a step by step
guide.
On Thu, Jun 2, 2011 at 12:21 PM, Nipesh Bajaj wrote:
> I have run R CMD check trial1 and saw an error. This says that:
>
> * chec
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Marius Hofert
> Sent: Thursday, June 02, 2011 1:20 PM
> To: Uwe Ligges
> Cc: Help R
> Subject: Re: [R] plotmath: paste string and expression [from
> a vectorof expressions]
>
>
Dear Dennis, Dear Uwe, Dear David,
many thanks for helping. Dennis and David, your solutions seemed perfectly
fine, but when I applied it to my original problem, it did not show a title.
Below is a (longer) minimal example (the first part is from the help page of
bbmle). Is this a bug in bbmle?
Hello list,
I have plots with long strings in main=, ylab= or xlab=. So, in I my script
I use break long lines to avoid lines hiden on my monitor and in sweave
document pages. I use graphics like this
plot(1, main="
")
but I would like a plot
(1) For crying out loud don't muck about with par(new=TRUE)
like that. Use points() and lines() (and other plot functions) to
add graphical constructs to existing plots. (And use "TRUE"
not "T" --- it's a lot safer.)
(2) In general for shading in regions between two lines
on a plot, use polygo
On Jun 2, 2011, at 4:19 PM, Rob James wrote:
The rms package includes the nomogram function, which generates a
list object that can be passed to plot for graphical production of
nomograms.
I would like to remove the "linear predictor" line in the graph,
which means (I suspect) removing
The documentation includes this: nomogram(fit, ..., lp=FALSE)
Frank
Rob James-2 wrote:
>
> The rms package includes the nomogram function, which generates a list
> object that can be passed to plot for graphical production of nomograms.
>
> I would like to remove the "linear predictor" line i
On Jun 2, 2011, at 2:41 PM, Hess, Michael wrote:
> Hello R people,
>
> I am looking to pay someone to help write some R code.
>
> Inputs:
> Study identifier: ID Number for the study, each ID number is for one study
> only each block set should only be used for that study. This will require
On Jun 2, 2011, at 4:19 PM, Marius Hofert wrote:
Dear Uwe,
thanks for your help. Actually, I first thought about writing your
solution in the email in order to make clear that it is not the
solution I'm looking for :-) My goal is to work with the vector
"vars" of expressions. The example
Dear Rxperts!
Below are relevant lines of code, I am having problems with.. I am not sure
if it is a bug in R or OS related or something else...
When viewing the pdf file, I notice overlaid plots in a panel of the plot
are shifted to the right. The Y-axes and X-labels are not exactly on top of
eac
On Jun 2, 2011, at 4:21 PM, Ben Ganzfried wrote:
> Thank you very much for your help. It saved me a lot of time and it
> worked perfectly. I have a quick follow-up as I'm not sure I
> understand yet why the code works and where it comes from.
>
> For example, in: Tstg <- sub(".*T(\\d)N.", "
Hi:
This seems to work:
vars2 <- c(quote(alpha), quote(beta)) # returns a list of mode call
plot(0, 0, main = bquote(bold('Foo '~.(vars2[[2]]
Expressions are only evaluated once, which means that inner
expressions are not evaluated. You need a call object rather than an
expression inside o
Thank you very much for your help. It saved me a lot of time and it worked
perfectly. I have a quick follow-up as I'm not sure I understand yet why
the code works and where it comes from.
For example, in: Tstg <- sub(".*T(\\d)N.", "\\1", tmp)
*How exactly does the substitution operation work?
Dear Uwe,
thanks for your help. Actually, I first thought about writing your solution in
the email in order to make clear that it is not the solution I'm looking for
:-) My goal is to work with the vector "vars" of expressions. The example is
only a minimal example and for that your solution is
The rms package includes the nomogram function, which generates a list
object that can be passed to plot for graphical production of nomograms.
I would like to remove the "linear predictor" line in the graph, which
means (I suspect) removing it from the nomogram output object. I've
looked at
On 02.06.2011 20:43, Marius Hofert wrote:
Dear all,
I have a vector of expressions and would like to "paste" some string to it
before using it in a plot:
vars<- vector("expression", 2)
vars[1]<- expression(alpha)
vars[2]<- expression(beta)
plot(0, 0, main=substitute(bold("Foo" ~~ VAR), list(
Greetings
Grateful for any help on this one:
In the following demo code, I am trying to get the points in the line to
appear over the same x-axis labels as are used by the paired Bars. It
appears, however, that R/lattice ignores the x-axis points used by the bars
and plots the x points
Dear all,
do you know any easy way based on a vector input how to plot easily cdf and pdf.
I would like to thank you in advance for your help
Regards
Alex
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Hello R people,
I am looking to pay someone to help write some R code.
Inputs:
Study identifier: ID Number for the study, each ID number is for one study
only each block set should only be used for that study. This will require
that you store the results from the blocks someplace on the fil
Doesn't deal with what problems?
Hadley
On Thursday, June 2, 2011, rmje wrote:
> I have been browsing the pages about ggplot and it really doesn't deal with
> such problems as far as I can see.
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/re-write-plot-function-for-
On Jun 2, 2011, at 2:54 PM, Ben Ganzfried wrote:
Hi,
First of all, I would like to introduce myself as I will probably
have many
questions over the next few weeks and want to thank you guys in
advance for
your help. I'm a cancer researcher and I need to learn R to
complete a few
projec
I have run R CMD check trial1 and saw an error. This says that:
* checking pdf version of manual without hyperrefs or index ... ERROR
Re-running with no redirection of stdout/stderr.
Hmm... looks like a package
Error in texi2dvi("Rd2.tex", pdf = (out_ext == "pdf"), quiet = FALSE, :
pdflatex is no
Hi,
eset is an expressionset based on hgu133plus2 platform.
Using hgu133plus2.db package, I want to map probes to UniGene cluster IDs.
It results in an error message.
>xx=hgu133plus2UNIGENE
>uniaf1=xx[[as.character(featureNames(eset))]]
Error in .checkKeys(value, Lkeys(x), x@ifnotfound) :
v
You did not read the help files carefully enough.
The Help for panel.text tells you that it is the same function as
ltext. ltext lists a bunch of parameters, srt among them, and refers
you to the corresponding base R graphics function, which is text().
?text then refers you to par for this and ot
Hi,
First of all, I would like to introduce myself as I will probably have many
questions over the next few weeks and want to thank you guys in advance for
your help. I'm a cancer researcher and I need to learn R to complete a few
projects. I have an introductory background in Python.
My questi
Greetings to all,
I have a similar issue with Snowball.
I am runing R version 2.12.1 (2010-12-16) on windows 7
Here is my script :
library(tm)
custom.xml <- system.file("texts", "custom.xml", package = "tm")
print(readLines(custom.xml), quote = FALSE)
myXMLReader <- readXML(
spe
Hi!
I am very new to R, I hope someone can help me.
I have two dataframes:
data1<-data.frame(from=c(1,12,16,40,55,81,101),to=c(10,13,23,45,67,99,123))
data2<-data.frame(name=c(1,2,3,4,5,6,7,8,9),position=c(2,14,20,50,150,2000,2001,2002,85))
I want to know which of the entries in "position" of
Dear all,
I have a vector of expressions and would like to "paste" some string to it
before using it in a plot:
vars <- vector("expression", 2)
vars[1] <- expression(alpha)
vars[2] <- expression(beta)
plot(0, 0, main=substitute(bold("Foo" ~~ VAR), list(VAR=vars[2]) ))
Although I tried hard, I j
On Jun 2, 2011, at 11:04 AM, Sakti wrote:
Hi guys!
I'm new to R, but I was wondering if one could plot many histograms
into a
single graph each having a different color. To make things clear:
Suppose you have a matrix of 100 rows and 10 columns. I'm interested
in
plotting the histogram f
What else I need to do? In the Read-and-delete-me file following steps
are asked to perform:
* Edit the help file skeletons in 'man', possibly combining help files
for multiple functions.
* Edit the exports in 'NAMESPACE', and add necessary imports.
* Put any C/C++/Fortran code in 'src'.
* If you h
On 02/06/2011 2:03 PM, Nipesh Bajaj wrote:
Thanks Prof. Ripley and Duncan for your pointers. Noting down your
points I have modified my way of building package and have done
following so far:
1. In my C: drive I create one working folder naming "R_PackageBuild"
2. In R console I have written fol
Thanks again Rob for your help.
In terms of parameter comparison there won't be a problem. However, if
one wants to assume a particular distribution (and not the one given
by the imposed condition), for example an uniform distribution to
obtain all the possible combinations (all the multidimension
On Thu, 2 Jun 2011, Jonathan Daily wrote:
I would recommend trying to fix the installation of R 2.13.0 rather
than trying to obtain old packages. Try downloading the installer
again from a different mirror.
He has already been given help (3x) to that effect. People who fail
to acknowledege a
Thanks Prof. Ripley and Duncan for your pointers. Noting down your
points I have modified my way of building package and have done
following so far:
1. In my C: drive I create one working folder naming "R_PackageBuild"
2. In R console I have written following codes:
> setwd("c:/R_packageBuild")
>
try using `...`
function <- function(x, ...) {
#do stuff
plot(xy, ...)
}
On Thu, Jun 2, 2011 at 1:26 PM, eldor ado wrote:
> Hello,
>
> following problem:
>
> i have a written my own function to draw some sophisticated graphic,
> which after manipulating data somewhere contains a plot comand
> f
I would recommend trying to fix the installation of R 2.13.0 rather
than trying to obtain old packages. Try downloading the installer
again from a different mirror.
On Thu, Jun 2, 2011 at 10:33 AM, jmdpulido wrote:
> Dear all...
>
> I am looking for the zip file of an old version of the ARM packa
Hi,
this is my R-script
I need to make a confusion matrix
but the last row return me an error
require(mixOmics)
require(SDMTools)
file <- "C:\\data.txt"
d <- read.table(file, header=T, row.names = NULL)
X <- as.matrix(d[,2:11])
Y <- as.factor(d[,1])
i <- 1
samp <- sample(1:3, nrow(X), replace
Hello,
three commands might do the job (NOTE: df=your data frame,
obser=Observation, var1=Variable 1 [TYPE: string], var1flag=Variable 1
flag [TYPE: string])
1. df$var1flag<-NA
2. df$var1flag[ is.na(as.numeric(df$var1)) ]<-df$var1[
is.na(as.numeric(df$var1)) ]
3. df$var1<-as.numeric(df$var1
Hello,
following problem:
i have a written my own function to draw some sophisticated graphic,
which after manipulating data somewhere contains a plot comand
function <- function(x) {
...
plot(xy)
}
to tidy up my final graphs, it would be very handy to be able forward
all low-level graphic para
Thanks for the quick reply,
I understand that the predict(zip1A, type = "response") command is computing
the fitted_means and these are different than the probabilities
predict(zip1A, type = "prob"). Although, according to Martin (2005), the
highest probabilities do not simply lead to the true co
Duarte Viana gmail.com> writes:
>
> Thanks Rob and Ravi for the replies.
>
> Let me try to explain my problem. I am trying to make a kind of
> sensitivity analysis where I have 5 parameters (the margins of the
> Latin hypercube), 3 of them are proportions that should sum to one. My
> idea is to
?cor
Example:
> dd <- data.frame(x1 = rnorm(40), x2 = rnorm(40), x3 = runif(40, 0, 10))
'data.frame': 40 obs. of 3 variables:
$ x1: num -0.5585 1.3831 -1.7862 0.0572 0.2825 ...
$ x2: num -0.5247 -0.8636 -0.0749 0.2399 -0.1592 ...
$ x3: num 7.698 5.259 0.918 3.251 5.169 ...
> cor(dd)
Hi:
Here's one approach using geom_ribbon() in ggplot2 - the 'overlap' is
the change in color where the two ribbons intersect. Using your
example data with the same names and the 'one.month' variable removed,
library(ggplot2)
ggplot() +
geom_ribbon(data = target, aes(x = i.value, ymin = X25, ym
I have a data frame in R with the following values.
cars
autocar
cars info
what is that
donna drive
car
telephone
i need car...
I want to select all values which contain 'car', values with three
words, and those keywords with car that contain three words.
The first part is done with :
sqldf("SE
To whom it may concern,
I am a new user to R and I need help in my if and for statements as I need a
place marker.
I would like to convert the following table:
Observation | Variable 1
|-
1 | 1
2 | A
3 | 631
Into :
Observation| Variable 1 | Variable 1 Flag
-
Hi list, based on the following data.frame I would like to create a variable
that indicates the number of occurrences of A in the 3 years prior to the
current year:
DF = data.frame(read.table(textConnection(" A B
8025 1995
8026 1995
8029 1995
8026 1996
8025 1997
8026 1997
8025 1997
8027
I use package multicore, and it works very well. There is, however, one thing I
wonder if I don't do correctly, here is one example: I read ca 5.5 mill
records into a dataframe, using read.dta through a one-line function rdam1. It
runs nicely in parallel with other activitites.
p1 <- parall
Hi,
I used the package vars for my project but when the impulse response plots
were produced, some of the levels are out of the confidence band. I was
wondering what the problem is and also, does anyone know what type of
bootstrapping the package is using: is it parametric, case resampling,
gauss
Hi guys!
I'm new to R, but I was wondering if one could plot many histograms into a
single graph each having a different color. To make things clear:
Suppose you have a matrix of 100 rows and 10 columns. I'm interested in
plotting the histogram for each row, but it should not appear as bars but
r
Dear all...
I am looking for the zip file of an old version of the ARM package
compatible for R 2.10.1 version.
When I try to charge the ARM package I get the following message "package
'arm' was built under R version 2.13.0 ".
I can not update R to 2.13.0 as I always get this error "the setup
thank you so much for the very detailed indications which turned out to be a
real help in ponting me to the right direction;
referring back to my previous questions there is something still open:
2- I'm in trouble with the point labels because I would like to rotate them
by an angle of 90 degree
1 - 100 of 130 matches
Mail list logo
