Moshe, Ted, & Chuck, All THREE approaches worked fine for me.
Thank you! Sincerely, Jeff Miller Internal Virus Database is out-of-date. Checked by AVG Free Edition. 3:09 PM
--- Begin Message ---Jeff Miller wrote: > Hi all, > Suppose I have a column vector of 600 measurements taken in 1s intervals. > > What I want is a new vector with the averages for each min (so there would > be 10 entries). > > Is there an efficient way to do this? I’ve been doing it with a ‘for’ loop > but something tells me there is a simple command that is more efficient. How about something like this? y <- runif(600) df <- data.frame(minute = rep(1:10, each=60), y = y) with(df, tapply(y, minute, mean)) 1 2 3 4 5 0.4664301 0.4622071 0.5159511 0.4744836 0.5282750 6 7 8 9 10 0.4670941 0.5091410 0.4648349 0.5227221 0.5251926 > Jeff > > > > > Internal Virus Database is out-of-date. > Checked by AVG Free Edition. > > 3:09 PM > > [[alternative HTML version deleted]] > > ------------------------------------------------------------------------ > > ______________________________________________ > R-help@r-project.org mailing list > [1]https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide [2]http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Chuck Cleland, Ph.D. NDRI, Inc. 71 West 23rd Street, 8th floor New York, NY 10010 tel: (212) 845-4495 (Tu, Th) tel: (732) 512-0171 (M, W, F) fax: (917) 438-0894 Internal Virus Database is out-of-date. Checked by AVG Free Edition. 10/21/07 3:09 PM References 1. https://stat.ethz.ch/mailman/listinfo/r-help 2. http://www.R-project.org/posting-guide.html
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______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
