If x is your vector, one possibility is: y <- matrix(x,nrow=60) z <- apply(y,2,mean)
--- Jeff Miller <[EMAIL PROTECTED]> wrote: > Hi all, > > > > Suppose I have a column vector of 600 measurements > taken in 1s intervals. > > > > What I want is a new vector with the averages for > each min (so there would > be 10 entries). > > > > Is there an efficient way to do this? Ive been > doing it with a for loop > but something tells me there is a simple command > that is more efficient. > > > > Jeff > > > > > Internal Virus Database is out-of-date. > Checked by AVG Free Edition. > > 3:09 PM > > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
