Jeff Miller wrote:
> Hi all,
> Suppose I have a column vector of 600 measurements taken in 1s intervals.
>
> What I want is a new vector with the averages for each min (so there would
> be 10 entries).
>
> Is there an efficient way to do this? I’ve been doing it with a ‘for’ loop
> but something tells me there is a simple command that is more efficient.
How about something like this?
y <- runif(600)
df <- data.frame(minute = rep(1:10, each=60), y = y)
with(df, tapply(y, minute, mean))
1 2 3 4 5
0.4664301 0.4622071 0.5159511 0.4744836 0.5282750
6 7 8 9 10
0.4670941 0.5091410 0.4648349 0.5227221 0.5251926
> Jeff
>
>
>
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