On 02-Nov-07 00:12:19, Jeff Miller wrote: > Hi all, > Suppose I have a column vector of 600 measurements taken > in 1s intervals. > > What I want is a new vector with the averages for each min > (so there would be 10 entries). > > Is there an efficient way to do this? Ive been doing it > with a "for" loop but something tells me there is a simple > command that is more efficient.
A simple-minded thought is (constructing first such a vector S): S<-rnorm(600) colMeans(matrix(S,nrow=60)) [1] -0.0999271 0.1622274 0.2044960 -0.1503812 -0.0224353 [6] 0.1133577 0.2567317 -0.2510650 -0.1219953 0.0001626 Hoping this helps! Ted. -------------------------------------------------------------------- E-Mail: (Ted Harding) <[EMAIL PROTECTED]> Fax-to-email: +44 (0)870 094 0861 Date: 01-Nov-07 Time: 23:29:09 ------------------------------ XFMail ------------------------------ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
