Using 'str' to see what you have is excellent practice
(and very helpful to show in messages to R-help).
However, you need to look at the output you get
more carefully. You have a data frame that contains
a factor. So:
as.character(repo[, 1])
should do what you want.
Patrick Burns
patr...@bu
But repo is a dataframe. AAA is a factor within repo. You probably
need to apply as.character to repo$AAA.
--
David Winsemius
On Jan 13, 2009, at 12:50 AM, Gundala Viswanath wrote:
Hi Bill,
However with as.character it fail show the actual strings.
It gives this:
new_repo <- as.characte
Hi Bill,
However with as.character it fail show the actual strings.
It gives this:
> new_repo <- as.character(repo)
> str(new_repo)
chr "1:32267"
> print(new_repo)
[1] "1:32267"
Instead of
>> str(new_repo)
> chr [1:100] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...
>
>> print(new_repo)
> [1] "AAA" "
as.character()
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gundala Viswanath
Sent: Tuesday, 13 January 2009 3:25 PM
To: r-h...@stat.math.ethz.ch
Subject: [R] Converting
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