Using 'str' to see what you have is excellent practice
(and very helpful to show in messages to R-help).
However, you need to look at the output you get
more carefully. You have a data frame that contains
a factor. So:
as.character(repo[, 1])
should do what you want.
Patrick Burns
patr...@burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of "The R Inferno" and "A Guide for the Unwilling S User")
Gundala Viswanath wrote:
Hi Bill,
However with as.character it fail show the actual strings.
It gives this:
new_repo <- as.character(repo)
str(new_repo)
chr "1:32267"
print(new_repo)
[1] "1:32267"
Instead of
str(new_repo)
chr [1:100] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...
print(new_repo)
[1] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...
- Gundala Viswanath
Jakarta - Indonesia
On Tue, Jan 13, 2009 at 2:40 PM, <bill.venab...@csiro.au> wrote:
as.character()
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gundala Viswanath
Sent: Tuesday, 13 January 2009 3:25 PM
To: r-h...@stat.math.ethz.ch
Subject: [R] Converting Factor to Vector
Hi all,
How can I convert factor like this:
str(repo)
'data.frame': 1000 obs. of 1 variable:
$ AAA: Factor w/ 1000 levels "AAT","AAC",..: 1 2 3 4 5 6 7 8 9 10 ...
print(repo)
AAA
1 AAA
2 AAT
3 AAC
...
into to simple vector
str(new_repo)
chr [1:100] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...
print(new_repo)
[1] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...
I tried as.vector(), but it remains the same factor.
- Gundala Viswanath
Jakarta - Indonesia
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
