But repo is a dataframe. AAA is a factor within repo. You probably need to apply as.character to repo$AAA.

--
David Winsemius


On Jan 13, 2009, at 12:50 AM, Gundala Viswanath wrote:

Hi Bill,

However with as.character it fail show the actual strings.

It gives this:

new_repo <- as.character(repo)
str(new_repo)
chr "1:32267"
print(new_repo)
[1] "1:32267"

Instead of

str(new_repo)
chr [1:100] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...

print(new_repo)
[1] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...


- Gundala Viswanath
Jakarta - Indonesia



On Tue, Jan 13, 2009 at 2:40 PM,  <bill.venab...@csiro.au> wrote:
as.character()


Bill Venables
http://www.cmis.csiro.au/bill.venables/


-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org ] On Behalf Of Gundala Viswanath
Sent: Tuesday, 13 January 2009 3:25 PM
To: r-h...@stat.math.ethz.ch
Subject: [R] Converting Factor to Vector

Hi all,

How can I convert factor like this:

str(repo)
'data.frame':   1000 obs. of  1 variable:
$ AAA: Factor w/ 1000 levels "AAT","AAC",..: 1 2 3 4 5 6 7 8 9 10 ...
print(repo)
AAA
1  AAA
2  AAT
3  AAC
...

into to simple vector

str(new_repo)
chr [1:100] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...

print(new_repo)
[1] "AAA" "AAT" "AAC" "AAG" "ATA" "ATT"...


I tried as.vector(), but it remains the same factor.

- Gundala Viswanath
Jakarta - Indonesia

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