Without a subset of data, it is hard to come up with a solution. Now
here is a way of determining what names are in common and then maybe
doing something:
B.names <- names(B.list)
A.names <- names(A.list)
common <- intersect(B.names, A.names)
for (i in common){
B.list[[i]] <- function(A.list[
Le mercredi 14 mars 2012 à 00:51 -0700, ali_protocol a écrit :
> Hi all,
> I want to do this:
>
> B.list$aa= (a loop containing My.fun acting on the reults of second
> function on a A.list$aa))
> or, overally
> B.list$aa = function (A.list$aa)
> B.list and A.list has ma
Hi all,
I want to do this:
B.list$aa= (a loop containing My.fun acting on the reults of second
function on a A.list$aa))
or, overally
B.list$aa = function (A.list$aa)
B.list and A.list has many sublists aa, ab and Is there a way I can
apply the function and
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