Le mercredi 14 mars 2012 à 00:51 -0700, ali_protocol a écrit : > Hi all, > I want to do this: > > B.list$aa= (a loop containing My.fun acting on the reults of second > function on a A.list$aa)) > or, overally > B.list$aa = function (A.list$aa) > B.list and A.list has many sublists aa, ab and.... Is there a way I can > apply the function and loop on all sublists of A.list and get B.list? Please provide a small example, you can easily create two lists to illustrate your point. It's hard to help without that, it would require us mocking up an example for you, and we might get it wrong.
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