Without a subset of data, it is hard to come up with a solution. Now
here is a way of determining what names are in common and then maybe
doing something:
B.names <- names(B.list)
A.names <- names(A.list)
common <- intersect(B.names, A.names)
for (i in common){
B.list[[i]] <- function(A.list[[i]])
}
On Wed, Mar 14, 2012 at 3:51 AM, ali_protocol
<mohammadianalimohammad...@gmail.com> wrote:
> Hi all,
> I want to do this:
>
> B.list$aa= (a loop containing My.fun acting on the reults of second
> function on a A.list$aa))
> or, overally
> B.list$aa = function (A.list$aa)
> B.list and A.list has many sublists aa, ab and.... Is there a way I can
> apply the function and loop on all sublists of A.list and get B.list?
>
>
> Thanks in advance.
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Apply-a-loop-containing-a-function-on-a-list-tp4471188p4471188.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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