Thank you, that took care of it!
Stephanie
On Mon, Nov 17, 2008 at 12:33 PM, Jorge Ivan Velez <[EMAIL PROTECTED]
> wrote:
>
> Dear Sephanie,
> Try the following:
>
> # Data set including some NA values
> set.seed(123)
> X=cbind(c(3, 2, 2, 1, 2, 5, 5, 4, 1, 1),matrix(rnorm(100),ncol=10))
> colname
Dear Sephanie,
Try the following:
# Data set including some NA values
set.seed(123)
X=cbind(c(3, 2, 2, 1, 2, 5, 5, 4, 1, 1),matrix(rnorm(100),ncol=10))
colnames(X)=c('day',paste('X',1:10,sep=""))
X[2,2]<-X[5,10]<-X[3,8]<-NA
X
# mean excluding NA values
# in parenthesis are the number of observati
Thank you very much for the suggestions, however I do not think they will
help. Please let me know if I misunderstand.
1) Just using "colSums" without the "(!is.na)" portion provides:
Error in FUN(X[[1L]], ...) :
'x' must be an array of at least two dimensions
2) In that context, sum appears
Try something like this:
amn <- tapply(a[,i], a[, 1], colSums, na.rm=TRUE))
but since the result of the tapply is a vector, you can also use:
amn <- tapply(a[,i], a[, 1],sum, na.rm=TRUE))
On Fri, Nov 14, 2008 at 6:47 PM, Stephanie Shaw <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I am using tapply t
Hello,
I am using tapply to pull out data by the day of week and then perform
functions (e.g. mean). I would like to have the number of values used for
the calcuation for the functions, sorted by each day of week. A number of
entries in any given column are NAs.
I have tried the following code a
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