Thank you very much for the suggestions, however I do not think they will
help. Please let me know if I misunderstand.
1) Just using "colSums" without the "(!is.na)" portion provides:
Error in FUN(X[[1L]], ...) :
'x' must be an array of at least two dimensions
2) In that context, sum appears to add the values, not the number of values.
Thank you,
Stephanie
On Fri, Nov 14, 2008 at 3:54 PM, jim holtman <[EMAIL PROTECTED]> wrote:
> Try something like this:
>
> amn <- tapply(a[,i], a[, 1], colSums, na.rm=TRUE))
>
> but since the result of the tapply is a vector, you can also use:
>
> amn <- tapply(a[,i], a[, 1],sum, na.rm=TRUE))
>
> On Fri, Nov 14, 2008 at 6:47 PM, Stephanie Shaw <[EMAIL PROTECTED]>
> wrote:
> > Hello,
> >
> > I am using tapply to pull out data by the day of week and then perform
> > functions (e.g. mean). I would like to have the number of values used for
> > the calcuation for the functions, sorted by each day of week. A number
> of
> > entries in any given column are NAs.
> >
> > I have tried the following code and simple variants with no luck.
> >
> > for (i in 1:length(a[1,])){
> > x<-tapply(a[,i],a[,1],mean, na.rm=TRUE)
> > amn<-tapply(a[,i],a[,1],colSums(!is.na),na.rm=T)}
> > Adding an explicit argument to colSums(!is.na) {e.g. colSums(!is.na
> (a[,i]))}
> > produced an error that said colSums was not a function. Trying an
> > imbedded tapply instead of the colSums didn't work either. Using the sum
> > function added the values, not the count of the values.
> >
> > Thank you for any suggestions,
> > Stephanie
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> > and provide commented, minimal, self-contained, reproducible code.
> >
>
>
>
> --
> Jim Holtman
> Cincinnati, OH
> +1 513 646 9390
>
> What is the problem that you are trying to solve?
>
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