Try something like this:
amn <- tapply(a[,i], a[, 1], colSums, na.rm=TRUE))
but since the result of the tapply is a vector, you can also use:
amn <- tapply(a[,i], a[, 1],sum, na.rm=TRUE))
On Fri, Nov 14, 2008 at 6:47 PM, Stephanie Shaw <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I am using tapply to pull out data by the day of week and then perform
> functions (e.g. mean). I would like to have the number of values used for
> the calcuation for the functions, sorted by each day of week. A number of
> entries in any given column are NAs.
>
> I have tried the following code and simple variants with no luck.
>
> for (i in 1:length(a[1,])){
> x<-tapply(a[,i],a[,1],mean, na.rm=TRUE)
> amn<-tapply(a[,i],a[,1],colSums(!is.na),na.rm=T)}
> Adding an explicit argument to colSums(!is.na) {e.g. colSums(!is.na(a[,i]))}
> produced an error that said colSums was not a function. Trying an
> imbedded tapply instead of the colSums didn't work either. Using the sum
> function added the values, not the count of the values.
>
> Thank you for any suggestions,
> Stephanie
>
> [[alternative HTML version deleted]]
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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