On Mar 5, 2015 8:32 PM, "Sarah Goslee" wrote:
>
> Hi,
>
> On Thursday, March 5, 2015, JS Huang wrote:
>
> > Hi,
> >
> > There is a lot of if-else statement. r syntax rejects them. Here is
an
> > example of if-else example. In r we can code *ifelse(x>2,y <-
> > 1,ifelse(x>1,y <- 0.5, y <- 0)
Hi,
On Thursday, March 5, 2015, JS Huang wrote:
> Hi,
>
> There is a lot of if-else statement. r syntax rejects them. Here is an
> example of if-else example. In r we can code *ifelse(x>2,y <-
> 1,ifelse(x>1,y <- 0.5, y <- 0))* for the following.
I'm not sure what you are talking about:
Why should he? seq_len() is part of base R.
On Thursday, March 5, 2015, JS Huang wrote:
> Hi Curtis,
>
> Maybe you forgot to tell us how the function seq_len is defined.
>
>
>
> -
> JS Huang
> --
> View this message in context:
> http://r.789695.n4.nabble.com/problem-with-function-that-add
Hello, I have a list object with many dataframes (example provided below). Each
coulmn in a dataframe represents a simluation and each dataframe represents a
clmate station. I want to fit an extreme value distribution on each coulmn of a
dataframe and then average the confidence intervals and es
Hi,
There is a lot of if-else statement. r syntax rejects them. Here is an
example of if-else example. In r we can code *ifelse(x>2,y <-
1,ifelse(x>1,y <- 0.5, y <- 0))* for the following.
if (x > 2)
{
y = 1
}
else
{
if (x > 1)
{
y = 0.5
}
else
{
y = 0
}
}
---
Hi Curtis,
Maybe you forgot to tell us how the function seq_len is defined.
-
JS Huang
--
View this message in context:
http://r.789695.n4.nabble.com/problem-with-function-that-adds-rows-to-dataframe-based-on-conditional-statement-tp4704228p4704237.html
Sent from the R help mailing list
On 03/05/2015 01:21 AM, Zaynab Mousavian wrote:
Hi all,
I have tried to install GO.db package in R, but the following error is
please ask questions about Bioconductor packages on the Bioconductor support
forum https://support.bioconductor.org. Please also review answers to your
question on B
On Mar 5, 2015, at 10:09 AM, Evelyne1991 wrote:
> Hi everyone,
>
> I would like to divide a map of Germany vertically by the electoral results
> of 2013:
>
>> VoteGermany2013
>Party Result
> 1 CDU/CSU 49.4
> 2 SPD 30.5
> 3 LINKE 10.2
> 4 GRUENE 10.0
>
> What I'm looking for
That blog post refers to the authors own function, as.data.frame.list,
that you would have to download from github. It makes data.frame()
act quite differently than the usual way. I would not recommend it.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Thu, Mar 5, 2015 at 1:53 AM, harini_v
wr
Hello everyone,
I'm having a problem with a function that I wrote that is supposed to add a
row to dataframe based upon a conditional statement. To explain I've used
an example below:
#create data frame
animals=c("bird","dog","cat")
animals=rep(animals,each=4)
animals=animals[1:11]
animalYears=c(
Dear all
I get the following error message when I try to load one specific RData object
in R:
Error: ReadItem: unknown type 64, perhaps written by later version of R
The error message is odd because (a) this RData object was created just one
hour berfore in a previous script (in a s
Hi there
I am Ms. Harini and I am trying to solve a problem with the function
data.frame. The problem I am trying to solve is similar to the one listed
under the title Example Four in this website:
http://www.r-bloggers.com/converting-a-list-to-a-data-frame/
For some reason when I try to replica
Hi,
The following works by appending NA to make up the maximum length of the
list.
> test4
$Row1
[1] "a" "b" "c" "d" "e"
$Row2
[1] "a" "b" "c" "d" "e" "f" "g"
$Row3
[1] "h" "i" "j" "k" "l" "m" "n"
> as.data.frame(t(sapply(1:length(test4),
> function(x){c(test4[[x]],rep(NA,max(sapply(1:leng
Hi everyone,
I would like to divide a map of Germany vertically by the electoral results
of 2013:
> VoteGermany2013
Party Result
1 CDU/CSU 49.4
2 SPD 30.5
3 LINKE 10.2
4 GRUENE 10.0
What I'm looking for is very simple: a map divided like a one-bar graph,
with 49.4% of the leng
Hi all,
I have tried to install GO.db package in R, but the following error is
given to me:
biocLite(c("GO.db"))
BioC_mirror: http://bioconductor.org
Using Bioconductor version 2.13 (BiocInstaller 1.12.1), R version 3.0.2.
Installing package(s) 'GO.db'
trying URL
'http://bioconductor.org/pac
Hello,
I have a database and I would like to fit a Nadaraya-Watson Gaussian kernel
estimator and produce the confidence bands around the mean estimate. Any
ideas how to do this with R? I cannot find a way to produce the confidence
bands. I will use a fixed bandwidth.
Lets use this database fo
On Wed Mar 4 21:32:30 CET 2015 Chris Vanlangenberg writes:
>
> I want to compute the numerical values for modified second order bessel
> function given x and other parameters, currently base R has a bessel
> function for 1st order and I have tried to use the relationship between 1st
> and 2nd order
These two commands will compute the cell frequencies and then sort them:
e <- as.data.frame(xtabs(~ctry+member, Dataset))
f <- e[order(e$Freq, decreasing=TRUE),]
Then draw your subset
g <- head(f, 10)
or
g <- f[cumsum(f$Freq)/sum(f$Freq) >.8,]
Finally merge the sample with the original data a
Well, I obviously don't use it either, as I'm just quoting the docs.
I either use by(), or tapply().
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll
On Thu,
Bert: using the sample data frame from below, try to interpret the output of
this:
aggregate( dat[,1:2], dat[,"g",drop=FALSE, FUN=function(x){print(x);class(x)})
The help text you quote is probably not as clear as it should be. Would the
following be better?
"... and FUN is applied to each col
A consulting client has a large data set with a binary response
(negative) and two factors (ctry and member) which have many levels,
but many occur with very small frequencies. It is far too sparse with a
model like glm(negative ~ ctry+member, family=binomial).
> str(Dataset)
'data.frame': 1
I don¹t understand an error message from a thielsen function call within a
dplyr do function call.
by.CaseNo <- group_by(as.data.frame(MAP.dt), CaseNo)
> MAP.thielsen <- by.CaseNo %>%
+ do(model = thielsen(noninvMAP ~ invMAP, symmetric = T, data = .,
+ x = T, y = T, model =
Jim,
Have you looked at:
names: group labels which will be printed under each boxplot. Can
be a character vector or an expression (see plotmath).
You could use "" where you want a blank. I believe that "at" may work
here also.
Clint
Clint BowmanINTERNET:
On Mar 4, 2015, at 2:02 PM, Typhenn Brichieri-Colombi via R-help wrote:
> Hello,
>
> I am trying to use the following custom function in an aggregatefunction, but
> cannot get R to recognize my data. I’ve read the help on function()and on
> aggregate() but am unable to solve my problem. How ca
I have the following R code for a boxplot. But I keep getting 4 1's, 4 2's
and 4 3's on the x asis for which I reall want to relace the 1's by
agegroup 1 the 2's by age group 2 etc. And I don't want to replce it 4
times just once. Can anyone help.
boxplot(data.all ~ age.group, data = data.plots,
That's not what ?aggregate says:
"aggregate.data.frame is the data frame method. If x is not a data
frame, it is coerced to one, which must have a non-zero number of
rows. Then, each of the variables (columns) in x is split into subsets
of cases (rows) of identical combinations of the components o
I don't see your point. No matter which version of aggregate you use, FUN is
applied to vectors. Those vectors may be columns in a data frame or not, but
FUN is always given one vector at a time by aggregate.
---
Jeff Newmill
Using HTML email is, as usual, obscuring what you are doing on this end of the
communication. The error message indicates that you have single quotes around
the BOS term, but they are not visible in the code you have presented. In
addition, there is a syntax error in having the word 'from' befor
Sorry, Jeff. aggregate() is generic.
>From ?aggregate:
"## S3 method for class 'data.frame'
aggregate(x, by, FUN, ..., simplify = TRUE)"
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainl
The aggregate function applies FUN to vectors, not data frames. For example,
the default "mean" function accepts a vector such as a column in a data frame
and returns a scalar (well, a vector of length 1). Aggregate then calls this
function once for each piece of the column(s) you give it. Your
Please don't. This violates basic principles of functional design for a very
minor degree of convenience. In fact, the whole concept of a function interface
that accepts a caller's package name strikes me as brittle design. If your
function needs to do callbacks, give it a function to call. If y
On Thu, 5 Mar 2015, Michael Friendly wrote:
Why not make the legend fit on one line above or below the plot matrix?
?legend
-- look at ncol=, horiz= and xpd= args
Michael,
That's just the pointer I was hoping to see. There's no reason not to have
the legend outside the plot matrix and now I
Why not make the legend fit on one line above or below the plot matrix?
?legend
-- look at ncol=, horiz= and xpd= args
On 3/4/2015 4:39 PM, Rich Shepard wrote:
I have a matrix plot of ternary diagrams (pdf attached) generated with
these commands:
opar <- par(xpd=NA,no.readonly=T)
plot(Wint
Dear all,
I have several pacakges which all use some generic functions stored in
package. Let's call the package with generic functions 'auxiliary', a
package which uses those functions 'main'.
'auxiliary' has a function that needs the name of the package it is called
by. Currently I solve this b
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