Hi,
The following works by appending NA to make up the maximum length of the
list.
> test4
$Row1
[1] "a" "b" "c" "d" "e"
$Row2
[1] "a" "b" "c" "d" "e" "f" "g"
$Row3
[1] "h" "i" "j" "k" "l" "m" "n"
> as.data.frame(t(sapply(1:length(test4),
> function(x){c(test4[[x]],rep(NA,max(sapply(1:length(test4),function(x)length(test4[[x]])))-length(test4[[x]])))})))
V1 V2 V3 V4 V5 V6 V7
1 a b c d e <NA> <NA>
2 a b c d e f g
3 h i j k l m n
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