Hi
>
> Hi, there,
>
> I run into the same sample size error in JM. Have you found the solution
for
> the error?
What error?
Petr
>
> Many thanks,
> Helena
>
> --
> View this message in context: http://r.789695.n4.nabble.com/the-problem-
> about-sample-size-tp1592855p4434009.html
> Sent from
Thank you for the suggestions you have included in the mail. Since this is
my first job and this is the first time I am coordinating with a mailing
list so I was not aware of these formalities.
My objective of writing this function is to produce a personalized report
using "R2HTML". We interna
Hello R users,
I would like to fit a generalized linear model for the binomial family
with some non standard link functions. For instance, this is the
Aranda-Ordaz link:
η = ln( ( (1 - π)^-α - 1 )/α)
I know how to define a new link function to use with glm(), but I my
problem is that I have
Hi There,
I don't understand how to order the label in ROCR package in order to
get the correct result. I am wondering whether you can help me.
library(ROCR)
data(ROCR.simple)
pred <- prediction(ROCR.simple$predictions,ROCR.simple$labels)
svm.auc <- performance(pred, 'tpr', 'fpr')
plot(svm.auc)
Hi There,
I don't understand how to order the label in ROCR package in order to
get the correct result. I am wondering whether you can help me.
library(ROCR)
data(ROCR.simple)
pred <- prediction(ROCR.simple$predictions,ROCR.simple$labels)
svm.auc <- performance(pred, 'tpr', 'fpr')
plot(svm.auc)
Hello,
Thank you for probably not so new question, but i am new to R.
Does any of packages have something like glm+regularization? So far i
see probably something close to that as a ridge regression in MASS but
I think i need something like GLM, in particular binomial regularized
versions of poly
Hi, there,
I run into the same sample size error in JM. Have you found the solution for
the error?
Many thanks,
Helena
--
View this message in context:
http://r.789695.n4.nabble.com/the-problem-about-sample-size-tp1592855p4434009.html
Sent from the R help mailing list archive at Nabble.com.
__
Hello,
>
> I have a large matrix (SNPs) that I want to cycle over with logistic
> regression with interaction terms. I have made a loop but I am struggling
> to identify to the formula the name of the column in a way which is
> meaningful to the formula. It errors becasue it is not evaluated propo
Michael - thank you so much! Just what I needed!
--
View this message in context:
http://r.789695.n4.nabble.com/Using-a-FOR-LOOP-to-name-objects-tp4430454p4433903.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org ma
Perhaps you need the forecast() function?
Michael
On Wed, Feb 29, 2012 at 12:01 PM, ForzaBruta wrote:
> hi all. i'm busy with some time series data, starting from an earlier period
> until the current day.
>
> i have created a time series forecast taking into account the entire data
> from the e
Simply type ur.ers on a line by itself to see how the calculation is
implemented.
Michael
On Wed, Feb 29, 2012 at 11:20 AM, ackbar03 wrote:
> I need some real help on this, really stuck
>
> how are the coefficients for
> ur.ers(y, type = c("DF-GLS", "P-test"), model = c("constant", "trend"),
>
Your method of constructing a formula is funny: is there a term called
"interaction" or do you mean an interaction in the statistical sense?
Once you do that, I'd think the easiest way to proceed is to use
as.formula() to construct your formula programmatically and then to
pass that to glm(). Somet
On Feb 29, 2012, at 7:41 PM, Dennis Fisher wrote:
> R 2.14.0
> OS X
>
> Colleagues
>
> Probably a simple question but it alludes me at the moment. I want to embed
> a registered sign in the text in a legend. The text would look like:
> SOMETEXT®
> with ® superscripted.
>
> Thanks in
Hi Keith,
Do you mean as "predict.lm" can do?
Regards,
Pascal
De : Keith Weintraub
À : r-help@r-project.org
Envoyé le : Jeudi 1 mars 2012 11h41
Objet : [R] Create a function "automatically" from lm formula and coefficients?
I hope the subject says it all.
I
Folks,
What is the best way to simulate values from a fitted "VAR {vars}" model.
Also I have tried to use SVAR for a cointegration fit of y~x (just two
univariate time-series) but I can't figure out how to set up the "A" matrix so
that x_t can be used as a contemporaneous predictor of y_t.
Th
require(rms)
f <- ols(y ~ rcs(age,4)*sex + blood.pressure + rcs(height,5))
latex(f) # typeset algebraic form of model
Function(f) # create an R function that computes Y hat
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
http://r
I hope the subject says it all.
I want to be able to use an lm object and the associated coefficients to create
function that can produce "expected" "y" values given inputs.
Thanks,
KW
--
[[alternative HTML version deleted]]
__
R-help@r-pr
R 2.14.0
OS X
Colleagues
Probably a simple question but it alludes me at the moment. I want to embed a
registered sign in the text in a legend. The text would look like:
SOMETEXT®
with ® superscripted.
Thanks in advance.
Dennis
Dennis Fisher MD
P < (The "P Less Than" Company)
Pho
On Feb 29, 2012, at 5:01 PM, Faryabi, Robert (NIH/NCI) [F] wrote:
Hi there,
Here is the scenario:
I have a measurement of some sort for two variables, I would like to
figure out a rough pattern between them. Let say if the values of
the first variable are low, middle, high, and extremely
On Feb 29, 2012, at 7:05 PM, lidaky wrote:
the "*" character in front of the Temp variable is there because i
just
wanted to bold the variable in the threade that you can see where it
is
used.
I just restart my computer and R. Now the function is working great.
No clue
what was happenin
On Feb 29, 2012, at 7:08 PM, Leong Keat Chan wrote:
Hi, I would like to make a contour plot using R with the following
information (data at the end): x-axis= arranged according to day
(from 1 to 365, labels= use
I am really getting tired of seeing this message. This must be the
fourth du
Hi,
I have a large matrix (SNPs) that I want to cycle over with logistic
regression with interaction terms. I have made a loop but I am struggling
to identify to the formula the name of the column in a way which is
meaningful to the formula. It errors becasue it is not evaluated proporly.
(below
On 2012-02-29 15:45, David Winsemius wrote:
On Feb 29, 2012, at 6:39 PM, David Winsemius wrote:
On Feb 29, 2012, at 1:53 PM, Filoche wrote:
Hi everyone.
I have a DF with the first column being my independant variable and
all
other columns the dependent variables.
Something like:
x
my computer run under windows vista 64 sp2. The question about encoding, I
don't understand it, sorry ?
--
View this message in context:
http://r.789695.n4.nabble.com/TM-reader-with-text-tp4433394p4433526.html
Sent from the R help mailing list archive at Nabble.com.
the "*" character in front of the Temp variable is there because i just
wanted to bold the variable in the threade that you can see where it is
used.
I just restart my computer and R. Now the function is working great. No clue
what was happening, but now everything works.
Sorry for the false notic
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
On Feb 29, 2012, at 7:00 PM, Francesco Sarracino wrote:
Dear R listers,
I have a silly problem. I am trying to load a dta (Stata) file in R.
The dta is about 650 MB and contains the integrated World Values
Survey/ European Value Study data-set.
My problem is that I don't manage to load the fil
On 12-02-29 6:28 PM, Sarah Goslee wrote:
This is yet another problem with the Nabble interface to
the list.
On Wed, Feb 29, 2012 at 6:21 PM, Richard M. Heiberger wrote:
This line
TT<- *Temp*+273.15
makes it unexecutable. that is not the error you mentioned.
On nabble, that variable is in
Most, maybe all, of the example words you posted include ligatures,
With "financier" for example, the leading "fi" is rendered in PDF and in
most typesetting
situations as a ligature with the a single complex character representing
the "fi' combination.
ï¬ ï¬
I pasted the "fi" and "fl" ligature
Not sure I'm interpreting what you want to do correctly, but how about:
p2 <- pa + scale_x_continuous(limits=c(0,80))
p2
-Original Message-
From: John Kane
Sent: Wednesday, February 29, 2012 2:32 PM
To: r-help@r-project.org
Subject: [R] ggplot2 dot chart-start at zero
I am trying to
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
Dear R listers,
I have a silly problem. I am trying to load a dta (Stata) file in R.
The dta is about 650 MB and contains the integrated World Values
Survey/ European Value Study data-set.
My problem is that I don't manage to load the file. After almost 1
hour I issued the following command:
data
Michael (OP),
Not that it's necessary, but you might also find
confint(aa)
to be instructive.
Peter Ehlers
On 2012-02-29 07:20, R. Michael Weylandt wrote:
Formally, look at Pr(>|z|). Informally, look at the null and residual
deviances from print(aa).
Michael
On Wed, Feb 29, 2012 at 10:14 AM
On Feb 29, 2012, at 6:00 PM, Mickael R problem wrote:
Hello everybody,
I work, I try, with TM but I have a problem with some special words in
french. I think this is due to the manner to transform PDF to text,
but I'm
not perfectly sure.
Let's see to the example :
findFreqTerms(tdm1,30)
On Feb 29, 2012, at 6:39 PM, David Winsemius wrote:
On Feb 29, 2012, at 1:53 PM, Filoche wrote:
Hi everyone.
I have a DF with the first column being my independant variable and
all
other columns the dependent variables.
Something like:
x y1 y2 y3
... ... ...
On Feb 29, 2012, at 2:14 PM, lidaky wrote:
index.refraction <- function(Temp,Press, RH, CO2)
{
#define constant
lambda <- 531 #nm
Co <- 299792458 #m/s
ww <- c(295.235,2.6422,-0.03238,0.004028)
kk <- c( 238.0185 ,5792105 ,57.362 ,167917)
aa <- c( 1.58123 * 10^(-6) , -2.9331 * 10^(-8)
On Feb 29, 2012, at 1:53 PM, Filoche wrote:
Hi everyone.
I have a DF with the first column being my independant variable and
all
other columns the dependent variables.
Something like:
x y1 y2 y3
... ... ... ...
... ... ... ...
What I'm trying to do
gsub('.+; (.+);.+','\\1',x)
or if you just want the value out:
gsub('.+; Surv\\(months\\): ([0-9]+);.+','\\1',x)
You can also look at strsplit:
> strsplit(x,';')
[[1]]
[1] "99-625: Cell type: S"" Surv(months): 21" "
STATUS(0=alive, 1=dead): 1"
> lapply(strsplit(x,';'),'[',2)
[
On Wed, Feb 29, 2012 at 2:24 PM, Fred G wrote:
> Computer Friends,
>
> with the following example lines:
>
> [107] "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive, 1=dead): 1"
>
> [108] "99-625: Cell type: S; Surv(months): 21; STATUS(0=alive, 1=dead): 1"
>
> i want to be able to isolate the
On Feb 29, 2012, at 2:24 PM, Fred G wrote:
Computer Friends,
with the following example lines:
Modified to be correct R code. Please emulate my example in the future.
inp <-c( "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive,
1=dead): 1",
"99-625: Cell type: S; Surv(months): 21; ST
This is yet another problem with the Nabble interface to
the list.
On Wed, Feb 29, 2012 at 6:21 PM, Richard M. Heiberger wrote:
> This line
>
> TT <- *Temp*+273.15
> makes it unexecutable. that is not the error you mentioned.
On nabble, that variable is in bold. When it's reformatted for
the p
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
This line
TT <- *Temp*+273.15
makes it unexecutable. that is not the error you mentioned.
should that be
TT <- "Temp"+273.15
or
TT <- Temp+273.15
or something else?
On Wed, Feb 29, 2012 at 2:14 PM, lidaky wrote:
> here is the code:
>
> index.refraction <- function(Temp,Press, RH, CO2)
> {
Hello everybody,
I work, I try, with TM but I have a problem with some special words in
french. I think this is due to the manner to transform PDF to text, but I'm
not perfectly sure.
Let's see to the example :
findFreqTerms(tdm1,30)
[33] """n" "nancement"
"nancier"
Good day everybody!
Please help me with NaN result in nlminb function.
I use the following:
The function that present weighted maximum likelihood:
garchLLH<-
function(parm) {
mu = parm[1]; omega = parm[2]; alpha = parm[3]; beta = parm[4]
z = (x-mu); Mean = mean(z^2)
# Use Filter Representation:
e
Hi, I would like to make a contour plot with the data below, x-axis= Day
(increasing order, day number is out of 365 days of a year), y-axis= Depth
(varies), and z=pH. I tried to use filled.contour function, but not sure the
proper way to ordinate my z results into a matrix with different x and y
l
Computer Friends,
with the following example lines:
[107] "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive, 1=dead): 1"
[108] "99-625: Cell type: S; Surv(months): 21; STATUS(0=alive, 1=dead): 1"
i want to be able to isolate the number of months of survival for each row.
is there a regula
Hello,
babyluck wrote
>
> Dear helpers
>
> I have two data sets saved as vectors (temperature and velocity). Now I
> need to "take out" a span of temperature and its corresponding velocity in
> the other vector. How can I achieve that?
>
> I tried to write a function,which takes a vector entr
Hi everyone.
I have a DF with the first column being my independant variable and all
other columns the dependent variables.
Something like:
x y1 y2 y3
... ... ... ...
... ... ... ...
What I'm trying to do is to perform a linear model for each of my "y". I
here is the code:
index.refraction <- function(Temp,Press, RH, CO2)
{
#define constant
lambda <- 531 #nm
Co <- 299792458 #m/s
ww <- c(295.235,2.6422,-0.03238,0.004028)
kk <- c( 238.0185 ,5792105 ,57.362 ,167917)
aa <- c( 1.58123 * 10^(-6) , -2.9331 * 10^(-8) , 1.1043 * 10^(-10))
Hi there,
Here is the scenario:
I have a measurement of some sort for two variables, I would like to figure out
a rough pattern between them. Let say if the values of the first variable are
low, middle, high, and extremely high, then what would be the corresponding
pattern of the second variab
Typically this list doesn't support general statistical questions and
unfortunately I don't have a better recommendation. It may be more helpful for
you to work with a statistician than seek help here.
My point is simply that quantile regression is not for modeling outcomes that
are quantiles.
On Wed, Feb 29, 2012 at 1:23 PM, Doran, Harold wrote:
>
> The OP is looking for a way to deal with outcomes scores that are quantiles,
> not a method that models different quantiles of the conditional distribution
> where an outcome is a continuous variable. So, I don't think QR methods is
> wh
Hi.
Maybe this will help you:
set.seed(1)
temp <- 1:100
v <- rnorm(100)
temp[temp<16 | temp>38]
v[temp<16 | temp>38]
Andrija
On Wed, Feb 29, 2012 at 7:09 PM, babyluck wrote:
> Dear helpers
>
> I have two data sets saved as vectors (temperature and velocity). Now I need
> to "take out" a span
Yes! That works.
Thank you so much!
-Steve
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Petr Savicky
Sent: Wednesday, February 29, 2012 4:41 PM
To: r-help@r-project.org
Subject: Re: [R] Trying to eliminate a for loop
On Wed,
> * [2012-02-29 13:55:25 -0600]:
> On Wed, 29 Feb 2012, Sam Steingold wrote:
>> compacting garbage collector is our best friend!
>
> Which R does not use because of the problems it would create for
> external C/Fortran code on which R heavily relies.
Well, you know better, of course.
However, I
On 01/03/12 04:43, John Kane wrote:
(mydata<- as.factor(c("1","2","3", ">2", "5", ">2")))
str(mydata)
newdata<- as.character(mydata)
newdata[newdata==">2"]<- 0
newdata<- as.numeric(newdata)
str(newdata)
We really need to keep Excel (and other spreadsheets) out of peoples hands.
Amen, bro'!!!
On Wed, Feb 29, 2012 at 03:52:15PM -0500, Steven Wolf wrote:
> I keep trying to eliminate for loops when I arrive at them, but this one is
> stumping me. What is the nifty way to do this?
>
> My object data.cca is the output of the cancor function (for some two
> datasets X and Y) (data.cca is a
Hi David,
thanks a lot! Actually, I was looking for the graph since I still
have obtained the table... but It can help...
Best,
Marcio
www.dsr.inpe.br/~mello
On 2/29/12 5:34 PM, David L Carlson wrote:
Something like this?
x<- round(runif(100, 0, 40), 0)
y<- round(runif(100, 0, 40), 0)
On 01/03/12 10:27, Elaine Kuo wrote:
Hello Rolf,
Thank you for the response.
I tried your command but it did not work.
plot(1:10,ylab="y",xlab=expression(plain(km)^2))
Please kindly advise any other method to make "2" in km2 become a
uppercase number.
Thanks again.
The expression ``upperc
Try
plot(1:10,ylab="y",xlab=expression(km^2))
and if that fails, you'll need to tell us what you mean by "did not
work."
Sarah
On Wed, Feb 29, 2012 at 4:27 PM, Elaine Kuo wrote:
> Hello Rolf,
>
> Thank you for the response.
>
> I tried your command but it did not work.
> plot(1:10,ylab="y",xlab
Hello Rolf,
Thank you for the response.
I tried your command but it did not work.
plot(1:10,ylab="y",xlab=**expression(plain(km)^2))
Please kindly advise any other method to make "2" in km2 become a uppercase
number.
Thanks again.
Elaine
On Tue, Feb 21, 2012 at 8:24 AM, Rolf Turner wrote:
I keep trying to eliminate for loops when I arrive at them, but this one is
stumping me. What is the nifty way to do this?
My object data.cca is the output of the cancor function (for some two
datasets X and Y) (data.cca is a numeric vector)
data.cca <- cancor(X,Y)
Xcen=0*X
for(i in 1:dim(X)[1]
Something like this?
x <- round(runif(100, 0, 40), 0)
y <- round(runif(100, 0, 40), 0)
xgroup <- cut(x, seq(0, 40, 10), include.lowest=TRUE)
ygroup <- cut(y, seq(0, 40, 10), include.lowest=TRUE)
xy <- table(xgroup, ygroup)
image(xy)
You'll still have to work with the plot commands to label it pro
I am trying to create a simple dot-plot in ggplot2 with a solid line from the
y-axis to the dot, something I first saw in Cleveland's 1984 book
What I would like is to have the graph start at zero on the x-axis but leave
some space on the right side of the plot area.
I assumed that I should be
Michael gmail.com> writes:
>
> Hi all,
>
> As you can see from below, the result is strange...
>
> I would imagined that the bb result should be much higher and close to 1,
> any way to improve the fit?
>
> Any other classification methods?
>
> Thank you!
>
> data=data.frame(y=rep(c(0, 1),
Rob
The OP is looking for a way to deal with outcomes scores that are quantiles,
not a method that models different quantiles of the conditional distribution
where an outcome is a continuous variable. So, I don't think QR methods is what
is needed.
From
On 29.02.2012 15:19, Jason Love wrote:
Dear R users,
I'm a newbie for R and want to ask some basic questions.
So, after I open the R software, I typed library(DAAG). Then, I get massive
warning messages as shown below.
Why does it happen?
Also, here are few specific questions regarding each
On Wed, 29 Feb 2012, Sam Steingold wrote:
* Milan Bouchet-Valat [2012-02-29 18:18:50 +0100]:
I think you're simply hitting a (terrible) OS limitation. Linux is
very often not able to reclaim the memory R has used because it's
fragmented. The OS can only get the pages back if nothing is above
Thanks all. This is tremendously helpful.
Best,
Adam
On Feb 29, 2012, at 12:58 PM, David Reiner wrote:
> My understanding is that TLS, EIV, and orthogonal regression are closely
> related but separate concepts.
> If you read the 'Talk' at the Wikipedia page referenced below, you will see
>
I have a large file backed big. matrix, with millions of rows and 20
columns.
The columns contain data that I simply need to tabulate. There are a few
dozen unique
values. and I just want a frequency count
Test code with a small "big" matrix.
library(bigmemory)
library(bigtabulate)
test <- bi
My understanding is that TLS, EIV, and orthogonal regression are closely
related but separate concepts.
If you read the 'Talk' at the Wikipedia page referenced below, you will see
that many people have
terminology problems as well.
My take is that TLS is a special case of EIV and orthogonal line
Hi Ralf,
have you solved your problem?! If so, could you share? I have the same
problem...
Best,
Marcio
On 3/25/10 6:03 PM, Ralf B wrote:
Hi all,
I have simple x/y data from screen recording in a sequence:
number,x,y
1,10,30
1,20,
1,43,110
1,74,18
1,88,112
and would like
On 02/28/2012 08:13 AM, aishsk wrote:
Hi I am using the ggplot2 package for the volcano plot and I am using the
following code for the same:
g = ggplot(data=data, aes(x=data[11], y=-log10(data[12]), colour=threshold))
+
+ geom_point(alpha=0.4, size=1.75) +
+ opts(legend.position = "none") +
Hi: I can't find it anywhere on the internet but I have a book that shows
that, as long
as the SVD of the X matrix can be obtained, then the coefficient solution
to TLS ( least angle regression ) is only a function of the eigenvectors.
Therefore, principal components can be used to obtain the coef
On Tue, Feb 28, 2012 at 3:54 PM, Rob James wrote:
> I have a dataset that does not include native scores, but only serial
> quantile rankings for a set of units.
>
> Clearly these observations are dependent (in that you can't alter one
> observation without also altering others).
>
> Are there met
Frank,
This can be done directly with a variant of the panel.axis function.
See function panel.axis.right in the HH package. This was provided for me
by David Winsemius in response to my query on this list in October 2011
https://stat.ethz.ch/pipermail/r-help/2011-October/292806.html
The email t
On Wed, Feb 29, 2012 at 11:58:04AM -0500, Ayyappa Chaturvedula wrote:
> Dear Group,
>
> I have the following dataset:
>ID REPI DV CONC SS
> 11 156.84 116 0
> 1 2 146.56 116 0
>13 115.13 116 0
>14 207.81 116 0
> 15 129.53 116 0
> 16 151.48
Dear helpers
I have two data sets saved as vectors (temperature and velocity). Now I need
to "take out" a span of temperature and its corresponding velocity in the
other vector. How can I achieve that?
I tried to write a function,which takes a vector entry and then decides
wether to delete the t
In the age of google, I have found that concepts such as these are more complex
than what Wikipedia provides. Going far beyond a cursory search, it appeared to
me there are subtle differences between these terms. I was hoping this
knowledgeable community could provide insight on an R package to
On Wed, Feb 29, 2012 at 7:53 AM, Adam Waytz
wrote:
>
> Hello,
>
> I am extremely new to R and have found some leads to this question in the
> archives, but I am still a bit uncertain.
> I am looking for an R package to carry out orthogonal distance regression. I
> found some answers regarding D
>From your description, I believe the ladder function in the HH package is
what you are looking for.
## install.packages("HH") ## if necessary
library(HH)
data(tv)
ladder(life.exp ~ ppl.per.phys, data=tv, scales=list(relation="free"))
Rich
On Wed, Feb 29, 2012 at 6:21 AM, agent dunham wrote:
Hi Alok
See ?createCovariates in MSToolkit.
Best wishes
Chris
Chris Campbell
MANGO SOLUTIONS
Data Analysis that Delivers
+44 1249 705450
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Bhupatkar, Alok
Sent: 29 February 2012 16:
> * Milan Bouchet-Valat [2012-02-29 18:18:50 +0100]:
>
> I think you're simply hitting a (terrible) OS limitation. Linux is
> very often not able to reclaim the memory R has used because it's
> fragmented. The OS can only get the pages back if nothing is above
> them, and most of the time there i
On Feb 29, 2012, at 12:34 PM, ibid...@gmx.at wrote:
Hello,
sorry i'm an R newbie and wan't to install
ggplot2 on my ubuntu system.
during installation i got the error warning:
Warnmeldung:
In install.packages("reshape") :
Installation des Pakets 'reshape' hatte Exit-Status ungleich 0
Please,
On 29.02.2012 18:34, ibid...@gmx.at wrote:
Hello,
sorry i'm an R newbie and wan't to install
ggplot2 on my ubuntu system.
during installation i got the error warning:
Warnmeldung:
In install.packages("reshape") :
Installation des Pakets 'reshape' hatte Exit-Status ungleich 0
Please, give m
On 28.02.2012 07:04, Yashwanth M.R wrote:
Hi Mr. Uwe Ligges,
Yashwanth M.R,
this is the R-help mailing list, not my personal mail account (and "Mr."
is inappropriate in any case).
I really thankful for the reply. I even tried the same,
means writing the new function
On 29.02.2012 17:36, Raúl Fernández Naranjo wrote:
Hi everyone, I was using rattle. I used a database with 4 individuals and
50 variables. Reading the database was OK and that was made by rattle but when
y was trying to draw the tree, rattle shows the image attached.
And have
1.0d+0 is Fortran (not C) for a double precision value,
1.0 * 10^0.
1.0e+0 is Fortran for a single precision value, 1.0 * 10^0
and C for a double precision value.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-h
Hello,
sorry i'm an R newbie and wan't to install
ggplot2 on my ubuntu system.
during installation i got the error warning:
Warnmeldung:
In install.packages("reshape") :
Installation des Pakets 'reshape' hatte Exit-Status ungleich 0
Please, give me a idea, how can i fix this error/warning
-
hi all. i'm busy with some time series data, starting from an earlier period
until the current day.
i have created a time series forecast taking into account the entire data
from the earlier date up until 2007, using the "forecast" package for R. i
am comparing this forecasted data to the actual/
I am a relatively new R user and have recently built a multivariate dataset
without the demographic information.
Is there any package or code to simulate subgroup dataset (race, sex, age)
using R?
Any help would be appreciated.
Thanks,
Alok
[[alternative HTML version deleted]]
__
Hello,
I am extremely new to R and have found some leads to this question in the
archives, but I am still a bit uncertain.
I am looking for an R package to carry out orthogonal distance regression. I
found some answers regarding Deming
regression and Total Least Squares regression, but I was u
Hi everyone, I was using rattle. I used a database with 4 individuals and
50 variables. Reading the database was OK and that was made by rattle but when
y was trying to draw the tree, rattle shows the image attached.
Please help me.
Raúl Fernández
Thank you Michael.
I also wrote to the author of this program, Palph, he suggested the same
thing. It worked!!
It is a very useful tool. In case for someone who is interested, I found the
package here:
http://cran.r-project.org/web/packages/hier.part/
--
View this message in context:
http://r
That worked!
Thanks a lot Jeremy.
--
View this message in context:
http://r.789695.n4.nabble.com/Installing-package-QRMlib-tp4425269p4431895.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://st
Hello,
Try the following.
(In Andrija's code I've changed 'df' to 'DF', 'df' is a R function name)
DF <- read.table( ... etc ...
tc <- textConnection("
Column1(Gen)Column2(Name)
A_1 Wynda
A_2 A_2
B_1
Dear all,
I have an issue concerning the lme function and I couldn't find the solution
elsewhere.
I have a data frame with id, Ages, Parameter1 and Parameter2.
The Ages can belong to one of two categories "early" or "late".
Then for example an id can have several values of Parameter1 at differ
I need some real help on this, really stuck
how are the coefficients for
ur.ers(y, type = c("DF-GLS", "P-test"), model = c("constant", "trend"),
lag.max = 0)
The max lag is set at zero, so the regression should simply be
Diff(zt) = a*z(t-1)
where a is the value i'm trying to find and z(t
Le mercredi 29 février 2012 à 11:42 -0500, Sam Steingold a écrit :
> > * William Dunlap [2012-02-28 23:06:54 +]:
> >
> > You need to walk through the objects, checking for environments on
> > each component or attribute of an object.
>
> so why doesn't object.size do that?
>
> > > f <- fun
1 - 100 of 167 matches
Mail list logo
