On 2012-02-29 15:45, David Winsemius wrote:
On Feb 29, 2012, at 6:39 PM, David Winsemius wrote:
On Feb 29, 2012, at 1:53 PM, Filoche wrote:
Hi everyone.
I have a DF with the first column being my independant variable and
all
other columns the dependent variables.
Something like:
x y1 y2 y3
... ... ... ...
... ... ... ...
What I'm trying to do is to perform a linear model for each of my
"y". It is
pretty simple with loops, but I'm trying to vectorize it using
*apply*.
For instance, I tried something like:
apply(DF, 1, function(DF){lm(DF[,1] ~ Band1[,2:5])})
apply( DF[2:5], 2, function(x){lm(DF[,1] ~ x)})
You need to use the variable name that you created in the function
call and loop over columns, not rows.
I read the request wrong. It would be:
apply( DF[2:5], 2, function(y){y ~ DF$x)})
Another possibility: from ?lm:
"If response is a matrix a linear model is fitted separately by
least-squares to each column of the matrix."
Peter Ehlers
But apparently it does not work.
For about four or five reasons.
.
David Winsemius, MD
West Hartford, CT
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David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
