On Feb 29, 2012, at 2:24 PM, Fred G wrote:
Computer Friends,
with the following example lines:
Modified to be correct R code. Please emulate my example in the future.
inp <-c( "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive,
1=dead): 1",
"99-625: Cell type: S; Surv(months): 21; STATUS(0=alive, 1=dead): 1")
i want to be able to isolate the number of months of survival for
each row.
is there a regular expression that can find the first instance of a
";",
delete everything in front of it-- and find the second instance of
an ";"
and delete everything behind it? in python there is a function
line.find(),
would be grateful to hear the R equiv; or, any other better
alternatives to
get the number of months of survival stored as a variable.
You can use either regex methods (noting that the "?" is necessary to
defeat the default greedy nature of regex match.
> sub( ";.+$", "", sub("^.+?;", "", inp) )
[1] " Surv(months): 6" " Surv(months): 21"
... or you can read these as lines and pass the results to read.table
with sep =";".
> read.table(text=inp, sep=";", stringsAsFactors=FALSE)[ ,2]
[1] " Surv(months): 6" " Surv(months): 21"
[[alternative HTML version deleted]]
Please learn to post in palin text.
--
David Winsemius, MD
West Hartford, CT
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