oops, I meant:
sub <- Claims [ Claims$Year="Y1",]
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
-
Hi Kevin,
Try using ?dput for putting your code on the list, so people could easily
import and play with it.
I think you probably need to do this:
sub <- subset(Claims, Year="Y1")
This also should work:
sub <- Claims [ Year="Y1",]
Contact
Details:-
On Wed, Feb 8, 2012 at 6:46 PM, David Winsemius wrote:
>
> On Feb 8, 2012, at 8:00 PM, Yang Zhang wrote:
>
>> I'm trying to use ROCR to create a simple cutoff vs recall plot
>> (recall@p) on the example ROCR.simple dataset:
>>
>> library(ROCR)
>> data(ROCR.simple)
>> pred <- prediction(ROCR.simple
Hi,
This is only a small portion of the Data i am working on
I want to make a subset of this data set( Data Set=Claims)
MemberID ProviderID Vendor PCPYear Specialty
1 422869788013252 172193 37796 Y1Surgery
2 979032483316066 726296 5300Y3
Hi, I'm having the same problem, but the aforementioned solution didn't work
for me. I keep getting an error message and the Stemmer is still reportedly
unknown. See code below. Please let me know if I'm overlooking anything.
Thanks.
> Sys.setenv(NOAWT=TRUE)
> library(tm)
> library(Snowball)
>
Hi,
Can anyone manage to login to a google account via RCurl? All info on
the web appears to be out of date.
(1) both RGoogleDocs and RGoogleTrends on omegahat appears to be withdrawn:
http://www.omegahat.org/RGoogleDocs/
http://www.omegahat.org/RGoogleTrends/
Does anyone know why?
(2) The close
?options ## error = recover will allow you to browse state at the
point of error
?traceback ## invoke immediately after an error to see exactly in
which function the error occurred
-- Bert
On Wed, Feb 8, 2012 at 9:01 PM, ilai wrote:
> ?debug will satisfy your curiosity regarding "debug mode"
?debug will satisfy your curiosity regarding "debug mode" - strictly
speaking it is not a "mode", just another function.
On Wed, Feb 8, 2012 at 7:30 PM, R. Michael Weylandt
wrote:
> What is your question? More interestingly, what is "debug mode" in R?
>
> I'd suggest you look at traceback() --
On Feb 8, 2012, at 8:00 PM, Yang Zhang wrote:
I'm trying to use ROCR to create a simple cutoff vs recall plot
(recall@p) on the example ROCR.simple dataset:
library(ROCR)
data(ROCR.simple)
pred <- prediction(ROCR.simple$predictions, ROCR.simple$labels)
perf <- performance(pred, "rec")
plot(per
What is your question? More interestingly, what is "debug mode" in R?
I'd suggest you look at traceback() -- there's also the powerful, but
possibly advanced, options(error=recover)
Kerninghan said "The most effective debugging tool is still careful
thought, coupled with judiciously placed print
Works fine for me.
sessionInfo()?
Michael
On Wed, Feb 8, 2012 at 8:00 PM, Yang Zhang wrote:
> I'm trying to use ROCR to create a simple cutoff vs recall plot
> (recall@p) on the example ROCR.simple dataset:
>
> library(ROCR)
> data(ROCR.simple)
> pred <- prediction(ROCR.simple$predictions, ROCR
You can of course make your own function to do this all "in one step"
split2env <- function(x, f, drop = FALSE, ...){
list2env(split(x, f, drop), ...)
}
But why do you need this for other tasks as a one-liner?
M
On Wed, Feb 8, 2012 at 6:29 PM, Johannes Radinger wrote:
>
> Am 08.02.2012 u
Dear Vickie,
I'm afraid that the test problem that you've constructed makes no sense, and
doesn't correspond to the problem that you initially described, in which a
matrix of presumably 5 responses for presumably 140 observations is
regressed on 6 predictors. You regressed your randomly generated
Thank you!
John
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call pho
On Feb 8, 2012, at 7:48 PM, John Sorkin wrote:
I am trying to produce three boxplots and label the x axis values:
xvalues, yvalues, zvalues.
My code is below. The labels are not below the three boxplots. If
you could show me how to get the
labels below the columns I would be appreciative.
J
xlab = needs to be names = see ?boxplot
boxplot(jdata[,"x"],jdata[,"y"],jdata[,"z"],names=c("x
values","yvalues","zvalues"))
-Original Message-
From: John Sorkin
Sent: Wednesday, February 08, 2012 6:48 PM
Cc: r-help
Subject: [R] x-axis label for boxplot
I am trying to produce th
I'm trying to use ROCR to create a simple cutoff vs recall plot
(recall@p) on the example ROCR.simple dataset:
library(ROCR)
data(ROCR.simple)
pred <- prediction(ROCR.simple$predictions, ROCR.simple$labels)
perf <- performance(pred, "rec")
plot(perf)
But R crashes on me on the last line.
I'm usi
On Wed, Feb 8, 2012 at 4:02 PM, moli wrote:
> I want to evaluate f with the mean=7
>
> mean=7
> f <- expression(-(x-mean)^2/2)
> then get a new expression:
>
> -(x-7)^2/2
> How could I do it? Thanks.
>
You can leave out the initial as.expression if you don't mind having a
call object instead:
I am trying to produce three boxplots and label the x axis values:
xvalues, yvalues, zvalues.
My code is below. The labels are not below the three boxplots. If you could
show me how to get the
labels below the columns I would be appreciative.
John
jdata<-data.frame(x = rnorm(100),y=rnorm(100,1),
Hi,
I have to debug my program. When I execute my function (in debug mode), I
have got an error but I do not know which line is concerned. I do not want
to do an infinite "Browse[2]>n with each line in my function...
THanks for your help,
ikuzar
--
View this message in context:
http://r.7896
I want to evaluate f with the mean=7
mean=7
f <- expression(-(x-mean)^2/2)
then get a new expression:
-(x-7)^2/2
How could I do it? Thanks.
--
View this message in context:
http://r.789695.n4.nabble.com/evaluate-one-variable-in-an-expression-with-two-variables-tp4370877p4370877.html
Sent fr
Oh cool! I didn't realize you could assign a different value to a substring
like that.
Thanks!
Joy
From: Petr Savicky [savi...@cs.cas.cz]
Sent: Wednesday, February 08, 2012 3:26 PM
To: r-help@r-project.org
Subject: Re: [R] String position character replace
On 9 February 2012 13:02, David Winsemius wrote:
>
> On Feb 8, 2012, at 6:33 PM, Tom Roche wrote:
>
>>
>> Peter Langfelder Thu Feb 9 00:01:31 CET 2012
>>>
>>> I'm exploring using a version control system
>>
>>
>> +1! welcome to the new millenium :-)
>>
>>> to keep better track of changes to the [R
On Feb 8, 2012, at 6:33 PM, Tom Roche wrote:
Peter Langfelder Thu Feb 9 00:01:31 CET 2012
I'm exploring using a version control system
+1! welcome to the new millenium :-)
to keep better track of changes to the [R] packages I maintain. I'm
leaning towards git
I like 'git' too, but one t
Try this:
sapply(mapply(replace, x = strsplit(avec, NULL), list = alist, MoreArgs =
list(values = "-")), paste, collapse = "")
On Wed, Feb 8, 2012 at 3:33 PM, Yang, Joy (NIH/NHGRI) [F]
wrote:
> Hi,
>
> Is there a way to efficiently replace specified indices in a string with
> another character?
On Feb 8, 2012, at 6:29 PM, Johannes Radinger wrote:
Am 08.02.2012 um 23:47 schrieb David Winsemius:
On Feb 8, 2012, at 5:06 PM, Johannes Radinger wrote:
Am 08.02.2012 um 22:19 schrieb David Winsemius:
On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
Hi,
I want to split a dataf
Am 08.02.2012 um 23:47 schrieb David Winsemius:
>
> On Feb 8, 2012, at 5:06 PM, Johannes Radinger wrote:
>
>>
>> Am 08.02.2012 um 22:19 schrieb David Winsemius:
>>
>>>
>>> On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
>>>
Hi,
I want to split a dataframe based on a gro
Peter Langfelder Thu Feb 9 00:01:31 CET 2012
> I'm exploring using a version control system
+1! welcome to the new millenium :-)
> to keep better track of changes to the [R] packages I maintain. I'm
> leaning towards git
I like 'git' too, but one thing to consider (though keep in mind that
I'm
Hi all, in particular package developers,
I'm exploring using a version control system to keep better track of
changes to the packages I maintain. I'm leaning towards git (although
mercurial also looks good) but am not sure what is the best way to set
up the repository. It seems I can't set the re
Dear Prof Fox,
I tried anova but got the following error message:
mat <- matrix(rnorm(700), ncol=5, dimnames=list( paste("f", c(1:140), sep="_"),
c("A", "B", "C", "D", "E")))
summary(Anova(lm(cbind(A, B, C, D, E) ~ factor(rownames(mat)),
data=as.data.frame(mat
Error in summary(Anova(lm(cbi
On Feb 8, 2012, at 5:06 PM, Johannes Radinger wrote:
>
> Am 08.02.2012 um 22:19 schrieb David Winsemius:
>
>>
>> On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
>>
>>> Hi,
>>>
>>> I want to split a dataframe based on a grouping variable (in one
>>> column). The resulting new
>>> dataframes
I'm going to declare this SOLVED. Yes, if you don't want a separate
script for batch, you will need to modify the original script so it
either readline or skips it. Here is an example:
# Save in file myTest.R
# Add this local function to the beginning of your original "program
Thanks you Peter,
It works perfectly.
Sylvia
-Original Message-
From: Peter Langfelder [mailto:peter.langfel...@gmail.com]
Sent: Tuesday, February 07, 2012 1:59 PM
To: Wilkerson, Sylvia (NIH/CIT) [E]
Cc: r-help@r-project.org
Subject: Re: [R] .Random.seed not found
You need to use set
Am 08.02.2012 um 22:19 schrieb David Winsemius:
>
> On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
>
>> Hi,
>>
>> I want to split a dataframe based on a grouping variable (in one column).
>> The resulting new
>> dataframes should be stored in a new variable. I tried to split the
>> dat
Dear Vicki,
I think that the Anova() function in the car package will do what you want
(and will also properly handle models with more structure, such as
interactions).
Best,
John
John Fox
Senator William McMaster
Professor of Social Statistics
Department of S
loop is too slow.
it appears that sparseMatrix does what I want:
ll <- lapply(l,length)
i <- rep(1:4, ll)
vv <- unlist(l)
j1 <- as.factor(substring(vv,1,1))
t <- table(j1)
j <- position of elements of j1 in names(t)
sparseMatrix(i,j,x=as.numeric(substring(vv,2,2)), dimnames = names(t))
so, the qu
When compute time is important it often helps
to loop over columns instead of over rows (assuming
there are fewer columns than rows, the usual
case). E.g., putting your code into a function f0
and the column-looping version into f1:
f0 <- function(v) {
n <- length(v)
d <- data.frame(A=vector(
summary: how to write an R script that requires certain 'modules'
(in the modules.sourceforge.net sense, not the generic sense)?
details:
I'm writing an R script (beginning
#!/usr/bin/env Rscript
) that uses a system call to one of the fine NCO tools
http://nco.sourceforge.net/
to run on a
On Feb 8, 2012, at 4:24 PM, Rolf Turner wrote:
On 09/02/12 10:00, David Winsemius wrote:
On Feb 8, 2012, at 3:50 PM, summer wrote:
Hi, there is p value and number of events from coxph results. How
can I keep
record of every p value and number of events automatically if I
run 100
times?
On Wed, Feb 08, 2012 at 03:56:12PM -0500, Sam Steingold wrote:
> To be clear, I can do that with nested for loops:
>
> v <- c("A1B2","A3C4","B5","C6A7B8")
> l <- strsplit(gsub("(.{2})","\\1,",v),",")
> d <- data.frame(A=vector(length=4,mode="integer"),
> B=vector(length=4,mode="int
Sorry, it's in package compiler, now part of the standard distro. My bad.
-- Bert
On Wed, Feb 8, 2012 at 1:23 PM, Sam Steingold wrote:
>> * Bert Gunter [2012-02-08 13:02:00 -0800]:
>>
>> A few extra minutes of computing time to save many more minutes of
>> programming time seems a reasonable tr
On 09/02/12 10:00, David Winsemius wrote:
On Feb 8, 2012, at 3:50 PM, summer wrote:
Hi, there is p value and number of events from coxph results. How can
I keep
record of every p value and number of events automatically if I run 100
times?
?replicate
Another question is how can I change th
> * Bert Gunter [2012-02-08 13:02:00 -0800]:
>
> A few extra minutes of computing time to save many more minutes of
> programming time seems a reasonable tradeoff.
in this case, many hours of computing time.
> see ?compile to compile your
Error: object 'compile' not found
--
Sam Steingold (
On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
Hi,
I want to split a dataframe based on a grouping variable (in one
column). The resulting new
dataframes should be stored in a new variable. I tried to split the
dataframe using split() and
to store it using a FOR loop, but thats not
Hi,
I want to split a dataframe based on a grouping variable (in one column). The
resulting new
dataframes should be stored in a new variable. I tried to split the dataframe
using split() and
to store it using a FOR loop, but thats not working so far:
df <- data.frame(A=c("A1","A1","A2","A2"),B
On 02/08/2012 12:13 PM, Ben Ganzfried wrote:
Hi Uwe,
Thanks for the help. R version 2.14.0 (2011-10-31). The file in question
looks like this (w/ a few minor edits for privacy):
There are two 'description' entries; the second might be combined with
the existing 'details'. Martin
\name{c
Sam:
On Wed, Feb 8, 2012 at 12:56 PM, Sam Steingold wrote:
> To be clear, I can do that with nested for loops:
>
> v <- c("A1B2","A3C4","B5","C6A7B8")
> l <- strsplit(gsub("(.{2})","\\1,",v),",")
> d <- data.frame(A=vector(length=4,mode="integer"),
> B=vector(length=4,mode="integer
On Feb 8, 2012, at 3:50 PM, summer wrote:
Hi, there is p value and number of events from coxph results. How
can I keep
record of every p value and number of events automatically if I run
100
times?
?replicate
Another question is how can I change the true or faulse statment to
1 and 0.
Dear R fans,
I have got a difficult sounding problem.
For fitting a linear model using continuous response and then for re-fitting
the model after excluding every single variable, the following functions can be
used.
library(MASS)
model = lm(perf ~ syct + mmin + mmax + cach + chmin + chmax, dat
I suspect there are cleverer ways to do it, especially using packages
like stringr and gsubfn, but using base tools, you can hack it without
too much effort:
?gregexpr
is the key. To get started (x is your example vector of character strings):
> gregexpr("[[:alpha:]]+[[:digit:]]+",x)
[[1]]
[1] 1
Hi Ray (& all),
Many apologies to Ray--apparently my intuition stinks!! The projection is
based on the unit sphere (R=1), so the projected coordinates really are
dimensionless--as you said! So to scale up to the earth, just multiply
the projected coordinate values from mapproject by your favorite
On Feb 8, 2012, at 2:29 PM, Ron Michael wrote:
Okay, so I understood that appending can only happen row-wise.
Therefore I tried with following code:
write.csv(matrix(1:5, 1), "dat.csv")
write.csv(matrix(1:5, 1), "dat.csv", append = TRUE)
Warning message:
In write.csv(matrix(1:5, 1), "dat.c
To be clear, I can do that with nested for loops:
v <- c("A1B2","A3C4","B5","C6A7B8")
l <- strsplit(gsub("(.{2})","\\1,",v),",")
d <- data.frame(A=vector(length=4,mode="integer"),
B=vector(length=4,mode="integer"),
C=vector(length=4,mode="integer"))
for (i in 1:len
Hi, there is p value and number of events from coxph results. How can I keep
record of every p value and number of events automatically if I run 100
times?
Another question is how can I change the true or faulse statment to 1 and 0.
such as w=1<2, I want the value of w to be 1 not true.
Thank you.
Hi,there,
I am using R package "boot" to bootstrap. I have one question here: does
anybody possibly know how the boot package generates the "indices" which is
used in the statistic function?
I thought "indices = sample(data, replace=TRUE)", but when I replaced
"indices" with this command and used
Okay, so I understood that appending can only happen row-wise. Therefore I
tried with following code:
> write.csv(matrix(1:5, 1), "dat.csv")
> write.csv(matrix(1:5, 1), "dat.csv", append = TRUE)
Warning message:
In write.csv(matrix(1:5, 1), "dat.csv", append = TRUE) :
attempt to set 'append' i
Suppose I have a vector of strings:
c("A1B2","A3C4","B5","C6A7B8")
[1] "A1B2" "A3C4" "B5" "C6A7B8"
where each string is a sequence of pairs
(fixed width, in this example both value and name are 1 character, in
reality the column name is 6 chars and value is 2 digits).
I need to convert it
On Wed, Feb 08, 2012 at 01:30:55PM -0500, Sarah Goslee wrote:
> And here's an alternative solution:
>
> subchar <- function(string, pos, char="-") {
> for(i in pos) {
> string <- gsub(paste("^(.{", i-1, "}).", sep=""), "\\1-", string)
> }
> string
> }
Hi.
Try the followin
Hi Uwe,
Thanks for the help. R version 2.14.0 (2011-10-31). The file in question
looks like this (w/ a few minor edits for privacy):
\name{curatedData-package}
\alias{curatedData-package}
\alias{curatedData}
\docType{package}
\title{Cancer Gene Expression Analysis}
\description{The curatedData
Hi, I am wondering if it is possible to get an estimate of standard error of
the predicted posterior probability from LDA using lda() from MASS? Logistic
regression using glm() would generate a standard error for predicted
probability with se.fit=T argument in predict(), so would it make sense t
On 08.02.2012 17:19 (UTC+1), Jean Jacques Dureau wrote:
Hi rainer,
how can I control dependend packages?
You did not tell us very much about your installation and versions of
packages you are using.
On my system sessionInfo() gives me the following after loading your
example:
sessionInfo
A somewhat common idiom is to use readline() with "Please press
to continue:" as the prompt and not to store the value
anywhere.
Michael
On Wed, Feb 8, 2012 at 2:45 PM, Juan Andres Hernandez
wrote:
> Hi all, I have some time trying to find a way to stop a loop for( ) until the
> user presses th
>> On 12/08/2011 03:45 AM, Xavier Fernández i Marín wrote:
>> > Hello,
>> >
>> > Although I have used a general search engine, r-seek, and browsed
>> > CRAN for contributed packages and R Gallery, I have not been able
>> > to find an implementation of Hinton Diagrams for representing
>> > weightin
Hi all, I have some time trying to find a way to stop a loop for( ) until the
user presses the enter key or any other one and the loop can continue.
This could
be an example:
library(MASS)
data <- data.frame(mvrnorm(1000,rep(0,5),Sigma=diag(1,5)))
for(i in 1:dim(data)[2]){
plot(density(data[,
On 07.02.2012 16:03, Mark Na wrote:
Dear R-helpers,
Please see the attached plot.
The problem is that I have too much space between the x-axis label
(which is mtext in an outer margin) and the plots.
My par settings for this plot are:
par(mfrow=c(1,3),oma=c(2,2,2,2),mar=c(5.1,4.1,4.1,2.1),
On 06.02.2012 12:29, Karthi KN wrote:
hi all, i am new to r
It is called R - well, everything lower case, shift key is broken?
, i am trying to run data mining algorithms using map
reduce framework.. *
*i have few basic doubts*
*1. can i give file in hdfs to kmeans( ) ? ?I tried as
file
Sorry Elai for the confusions.
Let me try to reframe my predicament. The main program "myTest.R" has
been written in interactive mode with many readline() lines embedded.
Suppose a user has already run the program once before in interactive
mode with all the answers saved in a text file called ans
I (and you as well) should have seen that before: use write.table in
order to append. The reason for that is given in ?write.table / ?write.csv:
‘write.csv’ and ‘write.csv2’ provide convenience wrappers for
writing CSV files. They set ‘sep’ and ‘dec’ (see below), ‘qmethod
= "doub
On 08.02.2012 17:43, Justin Fincher wrote:
Howdy,
This should be simple, but I am finding that I can't find a simple
solution. I have a plot to which I am manually adding the annotations
to the y-axis with this command:
axis(2,
c(-4,-3,-2,-1,0,1,2,3,4,5,6,7),labels=c(-4,-3,-2,-1,0,1,2,3,
On 08.02.2012 19:32, Journals wrote:
I run into a slight syntax proble while using nls that seems to require
some advice from the R community
I have a nonlinear regression problem where I observe the sum of the
responses (y) of many individuals (X1 Xn). The properties (x1..xn)
of these in
On 08.02.2012 18:44, Ben Ganzfried wrote:
Hi--
I googled the above error and found previous postings about this error on
the list. I was having a little difficulty implementing the advice though.
The suggestions were to use: traceback() and checkRd(). I'm using R in
the directory in which
On 08.02.2012 20:14, Ron Michael wrote:
Dear all, let say I want to write a vector to a CSV file. So I can have
following syntax:
write.csv(rnorm(10), "dat.csv")
Now I want to add one more column into that existing file. If I use the same
code then existing file will be destroyed. Is there
On 06.02.2012 18:42, Timothy Bates wrote:
hi,
Does factanal() force the user to use the formula interface if they wish to
specify an na.action?
Yes, as the help page says:
"na.action: The ‘na.action’ to be used if ‘x’ is used as a formula."
Uwe Ligges
v1<- c(1,1,1,1,1,1,1,1,NA,1,3,3,3,
I run into a slight syntax proble while using nls that seems to require
some advice from the R community
I have a nonlinear regression problem where I observe the sum of the
responses (y) of many individuals (X1 Xn). The properties (x1..xn)
of these individuals have been measured but sin
On 07.02.2012 15:23, anaraster wrote:
Hi!
I am new to BUGS and running BUGS from R. I am trying to run a regression
model from R, however I have this error message:
Error in file(con, "wb") : cannot open the connection In addition: Warning
messages:
1: In file.create(to[okay]) : cannot cre
Thank you both! I was working along the lines of Jorge's method, but was taking
longer than it should. Sarah's is actually a lot faster.
Thanks again,
Joy
From: Sarah Goslee [sarah.gos...@gmail.com]
Sent: Wednesday, February 08, 2012 1:30 PM
To: Yang, Joy
Dear all, let say I want to write a vector to a CSV file. So I can have
following syntax:
write.csv(rnorm(10), "dat.csv")
Now I want to add one more column into that existing file. If I use the same
code then existing file will be destroyed. Is there any functionality to add
without destroyi
Gang,
Maybe someone here has a different take on things. I'm afraid I have
no more insights on this unless you explain exactly what you are
trying to achieve, or more importantly why? That may help understand
what the problem really is.
Do you want to save an interactive session for future runs? t
On Wed, Feb 8, 2012 at 12:33 PM, Yang, Joy (NIH/NHGRI) [F]
wrote:
> Hi,
>
> Is there a way to efficiently replace specified indices in a string with
> another character? For example, if I had a vector of strings such as
>
> [1] "hellohowareyoudoing"
> [2] "imgoodhowareyou"
> [3] "goodandyou"
> [4
And here's an alternative solution:
subchar <- function(string, pos, char="-") {
for(i in pos) {
string <- gsub(paste("^(.{", i-1, "}).", sep=""), "\\1-", string)
}
string
}
> subchar("hellohowareyoudoing", 3)
[1] "he-lohowareyoudoing"
> subchar("hellohowareyoudo
Hi Joy,
Perhaps not the easiest way, but the following seems to work:
x <- c("hellohowareyoudoing", "imgoodhowareyou", "goodandyou",
"yesimgoodijusttoldyou", "ohyesthatsright")
pos <- list(c(3, 9), c(3,4), c(4,7), 5:9, c(2, 5, 7, 12))
sapply(1:length(pos), function(i){
xx <- strsplit(x, "")[
On 08.02.2012 17:14, oluwole oyebamiji wrote:
Hi all,
I want to do a linear regression with lm package in MASS, my data is
59199 rows by 29 column.
I got this error message can not allocate a vector of size 1.5Gb.
I have read some of the previous related posting on this but I couldnt sti
Hi,
Is there a way to efficiently replace specified indices in a string with
another character? For example, if I had a vector of strings such as
[1] "hellohowareyoudoing"
[2] "imgoodhowareyou"
[3] "goodandyou"
[4] "yesimgoodijusttoldyou"
[5] "ohyesthatsright"
and had a list of positions that I
It's compiled code so you can't view it in R. Download the source from CRAN (in
your browser, not through R), decompress it, and look through the src/
directory with your favorite text editor.
Michael
On Feb 8, 2012, at 8:51 AM, "J. Augusiak" wrote:
> Dear R list,
>
> I have a package downl
Dear John,
interesting. There must be a bottleneck somewhere, which possibly went
unnoticed because econometricians seldom use so many data points. In
fact 'plm' wasn't designed to handle "only" 700 Megs of data at a time;
but we're happy to investigate in this direction too. E.g., I was aware
of
Hi--
I googled the above error and found previous postings about this error on
the list. I was having a little difficulty implementing the advice though.
The suggestions were to use: traceback() and checkRd(). I'm using R in
the directory in which the .Rd file with the problem is located, but I
On Wed, Feb 08, 2012 at 06:17:40AM -0800, n wrote:
> Hi,
>
> How can I draw a random sample from a truncated distribution (especially
> lognormal)?
>
> I found the functions for truncated normal but not for many other
> distributions.
Hi.
A variable Y with a log-normal distribution may be obtain
Howdy,
This should be simple, but I am finding that I can't find a simple
solution. I have a plot to which I am manually adding the annotations
to the y-axis with this command:
axis(2,
c(-4,-3,-2,-1,0,1,2,3,4,5,6,7),labels=c(-4,-3,-2,-1,0,1,2,3,4,5,6,7),cex.axis=8)
The issue is that, apparen
On Wed, Feb 08, 2012 at 03:36:45PM +0100, Francisco wrote:
> Hello,
> I have a dataset with many rows, starting from a row that I choose I
> would like to find the other rows in the dataset which are identical to
> this row (with the same values per each column) and assign them to a
> variable.
Hi rainer,
how can I control dependend packages?
thanks
jj
Il 08 febbraio 2012 17:10, Rainer Hurling ha scritto:
> On 08.02.2012 15:35 (UTC+1), Jean Jacques Dureau wrote:
>>
>> I have these R code:
>>
>>
>> ###
>> time.tes
Hye,
I am writing to request your help.
I am working on survival curve analysis with Cox model (cox.zph). After to test
the proportionality condition for each covariant (independence to the time),
the time effect is very significant and I must adapt my model, by the addition
of a function dep
Hi all,
I want to do a linear regression with lm package in MASS, my data is 59199
rows by 29 column.
I got this error message can not allocate a vector of size 1.5Gb.
I have read some of the previous related posting on this but I couldnt still
got it right.
I have an Ubuntu machine of 64bi
8-02-2012, 22:22 (+0545); Christofer Bogaso escriu:
> And the Session info is here:
>
> > sessionInfo()
> R version 2.14.0 (2011-10-31)
> Platform: i386-pc-mingw32/i386 (32-bit)
Not an expert, but I think that 32-bit applications can only address
up to 2GB on Windows.
--
Bye,
Ernest
_
32 bit windows has a memory limit of 2GB. Upgrading to a computer thats
less than 10 years old is the best path.
But short of that, if you're just generating random data, why not do it in
two or more pieces and combine them later?
mat.1 <- matrix(rnorm(5*2000),nrow=5)
mat.2 <- matrix(rno
On Wed, Feb 8, 2012 at 7:09 AM, mails wrote:
> Hello,
>
> I used read.xlsx to read in Excel files but for large files it turned out to
> be not very efficient.
> For that reason I use a programme which writes each sheet in an Excel file
> into tab-delim txt files.
Note that that is how read.xls i
Dear all, I know this problem was discussed many times in forum, however
unfortunately I could not find any way out for my own problem. Here I am
having Memory allocation problem while generating a lot of random number.
Here is my description:
> rnorm(5*6000)
Error: cannot allocate vector of s
I don't know if this completely solves your problem, but here are some
arguments to read.table/read.delim you might try:
row.names=FALSE
fill=TRUE
The details section also suggests using the colClasses argument as the
number of columns is determined from the first 5 rows which may not be
Yuanwei,
You are correct. The initial seed value is the raw sum, starting with
TTR_0.21-0.
As it says in the TTR/CHANGES file (among other things):
- Changed wilderSum to seed initial value with raw sum. This matches
Wilder's original calculations. Thanks to Mahesh Bp for the report.
HTH,
--
Jo
Hi Ray,
Thanks for responding! However, it would certainly be very non-intuitive
if you're correct about the units for the projected coordinates. As I'm
sure you know, in a GIS geographic coordinates are usually in
degrees--although it's quite possible for these to be in radians instead, I
guess
On Feb 8, 2012, at 7:32 AM, hithit168 wrote:
Thanks a lot, David.
Uh...this is not really an R question, but I couldn't find answer
nowhere...
Questions that relate to how to use editors (and this is especially so
for Microsoft products) simply do NOT belong on R-help. There must be
lit
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