G'day all,
On Mon, 15 Mar 2010 12:46:42 -0500
Marc Schwartz wrote:
> In turn, that reminds me of Stephen Senn's writing in Dicing with
> Death: Chance, Risk and Health:
>
> "We can predict nothing with certainty but we can predict how
> uncertain our predictions will be, on average that is."
A
On Sun, 14 Mar 2010, Jonathan Baron wrote:
> Just to make this thoroughly confusing,
> I will say that I am very happy with Fedora
I can second that, as I have found Fedora (and before that, RedHat) plus
KDE to create less response interference for those of us who use
Windows. Not by choice, b
On 03/16/2010 03:22 AM, Marc Schwartz wrote:
Hi all,
I thought that readers of R-Help might find the following article at
ScienceNews of interest:
Odds Are, It's Wrong
Science fails to face the shortcomings of statistics
By Tom Siegfried
March 27th, 2010; Vol.177 #7 (p. 26)
http
On 03/16/2010 02:43 AM, Uwe Dippel wrote:
...
Thanks, Jim,
this one works (with your random data)! (In case anyone reads and wants
this as well, package plotrix provides radial.plot.)
The overlap is normal, because it's random data. When the respondents
have a less random streak of answering (an
I think what you have done should be fine. read.table() will return a
data frame, which cor() can handle happily. For example:
my.data <- read.table("file.csv", header = TRUE, row.names = 1,
sep=",", strip.white = TRUE) # assign your data to "my.data"
cor(my.data) # calculate the correlation ma
Hello!
I am attempting to use svyglm {survey package} with a large set of predictors
and would like to be able to automatically use all the variables in my data as
the predictors without having to type out their names explicitly, similar to
the way one can do:
x1=c(1,2,3,4)
x2=c(3,5,4,1)
y = x1
>
> If you read each of your 230,000 variables in separately, you can
> combine them into a matrix or dataframe using cbind(variablename1, 2,
> etc.).
>
> HTH,
I used read.table("file.csv", header = TRUE, row.names = 1, sep=",",
strip.white = TRUE)
to read it in but I could easily only read in th
Hello Vincent,
The command to correlate two variables and a set is the same (see
?cor). How have you read the data in? If it is a matrix or data
frame, you should be able to just use cor(name_of_your_matrix) and it
will return the correlation matrix for all variables in your matrix or
data frame
Hi Zhongyi,
I must confess I not understood completely what you need, but...
Tau<-seq(0.05,0.95,0.05);
Pi <- seq(0.19,0.01,-0.01);
par(cex.axis=0.8,ps=9,mar=c(1.5,1,0.5,1), oma=c(1,1,0.2,1) ,tck=-0.01);
plot(Tau,Pi, type='l', xlab="Tau",ylab="Pi",col=4, xaxt="n", yaxt="n");
axis(1,labels=F)
axis(
So I am very new to R. Have been using python for a project and need to
calculate the correlation coefficient matrix for my data set. the data is in
the range of 10-15 observations of 230,000 variables. ie the correlation
matrix would be 230,000X230,000 Using python and the numpy.corrcoef() I run
Dear R users:
I am drawing a graph with the following code:
Tau<-seq(0.05,0.95,0.05);
Pi <- seq(0.19,0.01,-0.01);
par(cex.axis=0.8,ps=9,mar=c(1.5,1,0.5,1), oma=c(1,1,0.2,1) ,tck=-0.01);
plot(Tau,Pi, type='l', xlab="Tau",ylab="Pi",col=4);
I want to make the graph take as little space as possible.
For anyone who is knowledgeable about the randomForest package in R, I have
a question:
When I look at the variable importance for data, I see that my response
variable is included along with my predictor variables. That is, I am
getting a MeanDecreaseGini for my response variable, and therefore i
Dear R People:
Here are some steps for the "simulate" from the dse package:
mod1 <- ARMA(A=array(c(1,-.25,-.05), c(3,1,1)), B=array(1,c(1,1,1)))
AR <- array(c(1, .5, .3, 0, .2, .1, 0, .2, .05, 1, .5, .3) ,c(3,2,2))
VAR <- ARMA(A=AR, B=diag(1,2))
print(VAR)
simData <- simulate(
Hey Gabor,
Thanks, I tried that, although I can't compile it directly. Do you know
where I can get the R LaTeX definitions in order to compile that?
Thanks!
Gabor Grothendieck wrote:
Try:
R CMD Rdconv --type=latex myfile.Rd
On Mon, Mar 15, 2010 at 8:46 PM, statmobile wrote:
Hey Everyon
Try:
R CMD Rdconv --type=latex myfile.Rd
On Mon, Mar 15, 2010 at 8:46 PM, statmobile wrote:
> Hey Everyone,
>
> I wrote up a library for my dissertation work, and I'd love to include it as
> an appendix. I have found ways to export the Rd files as html, txt and
> pdf/ps, but not a raw tex expo
The closest I can get to the compiled LaTeX pdf version as possible as
an appendix. Is there a way to get the raw LaTeX code from the package
documentation, as well as the configuration/commands for compiling them?
stephen sefick wrote:
What would you like to do? Is it not the code that you
I have several responses, not necessarily consistent with each other.
1. An appendix should be a user manual with screen shots.
2. The archival version of the package should be Yourpackage_x.y-z.tar.gz
stored
at your university's archival web location. The actual usable version of
your package
w
Thanks, both of you.
Regards
Ronggui
2010/3/13 Uwe Ligges :
>
>
> On 13.03.2010 14:00, Michael Lawrence wrote:
>>
>> Actually, the problem is more likely that RGtk2 is not built against GTK+
>> 2.12 on Windows. I assume you're using an up-to-date version of R. I'll
>> ask
>> Uwe about getting a n
Are you referring to a truncated normal?
(http://en.wikipedia.org/wiki/Truncated_normal_distribution)
Glen
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What would you like to do? Is it not the code that you would like to
include in your dissertation?
Stephen
On Mon, Mar 15, 2010 at 7:46 PM, statmobile wrote:
> Hey Everyone,
>
> I wrote up a library for my dissertation work, and I'd love to include it as
> an appendix. I have found ways to exp
I was having a similar problem, then found that a previous format statement
had changed the column with the dash in front of it to a string. I changed
the column back into floats, and the dash worked fine, no longer giving me a
unary operator error.
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I really appreciate the advices and suggestions.
But Gail`s information about google docs it`s exactly what I need.
It`s amazing.
Thank you very much indeed.
Nilza Baroros
On Sun, Mar 14, 2010 at 9:33 PM, Farrel Buchinsky wrote:
> Tal Galili gmail.com> writes:
>
> >
> > Hi Nilza,
> > I just wr
Hey Everyone,
I wrote up a library for my dissertation work, and I'd love to include
it as an appendix. I have found ways to export the Rd files as html,
txt and pdf/ps, but not a raw tex export. I've had to resort to dumping
it into text files, and just using verbatim in my LaTeX code. Doe
I am using PROC LOGISTIC to model binary outcomes.
I have observed Y (1 or 0) from original data.
I also have got predicted probability for each observation (i.e. predicted
probability of event Y=1) from PROC LOGISTIC. Let us call it - p_hat.
for example, I would have two columns -
Y p_hat
I am comparing kknn and logistic regression for binary outcome prediction -
For kknn, I can do -
kknn_<-kknn(out_come ~ age + gender , learn_, valid_)
fit<-fitted(kknn_)
table(valid_$out_come, fit)
to get validation results in cross-tabulation.
-
For logistic, how can I do the equival
hello R-helpers,
I have an array
acuracia <- array(NA, dim = c(1, 1, A, B, C))
which is first defined and in the example above with dimensions 1x1xAxBxC.
My array is then filled using 3 loops (I am not well familiar yet with
lapply or sapply functions so I am still a loop-user):
for (i in 1:A)
Dear Xiang Gao,
See the OBrienKaiser example in ?Anova in the car package.
I hope this helps,
John
John Fox
Senator William McMaster
Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/
In addtition to the example I mentioned previously,
demo("MMC.WoodEnergy-aov", "HH")
Please also see
demo("MMC.WoodEnergy", "HH")
In this example, since anova(energy.aov.4),
shows that the Wood factor and Stove:Wood interaction are significant,
all possible pairwise comparisons of the 12 Stove:Wo
On 15-Mar-10 21:10:03, Matthew Keller wrote:
> Hi all,
> Thanks for the responses. Ted - thank you for your help. I had
> to laugh. I'm no computer guru, but I do know unix well enough
> to know not to type "". But then again, my original code
> did contain a matrix with >>2^31-1 elements, so maybe
This gives the first mode in each group:
# test data
xx <- structure(list(v1 = c(1, 1, 1, 2, 2, 2, 3, 3, 3, 1),
v2 = structure(c(1L, 2L, 2L, 2L, 4L, 4L, 3L, 3L, 5L, 1L),
.Label = c("A", "B", "D", "W", "Z"), class = "factor")),
.Names = c("v1", "v2"), row.names = c(NA, 10L), class = "data.f
On Mar 15, 2010, at 17:10 , Matthew Keller wrote:
Hi all,
Thanks for the responses. Ted - thank you for your help. I had to
laugh. I'm no computer guru, but I do know unix well enough to know
not to type "". But then again, my original code did contain a
matrix with >>2^31-1 elements, so maybe
So you are parsing a *URL* instead of a local HTML file? I guess it
might have something to do with your internet connection as well as
the web server for that URL (some servers may restrict your access if
you visit it too frequently). Can you provide a reproducible example?
Regards,
Yihui
--
Yihu
Hi all,
Thanks for the responses. Ted - thank you for your help. I had to
laugh. I'm no computer guru, but I do know unix well enough to know
not to type "". But then again, my original code did contain a
matrix with >>2^31-1 elements, so maybe your assumption was reasonable
;)
Anyway, all your k
On Mar 15, 2010, at 16:20 , Matthew Keller wrote:
Hi all,
Thanks Simon and Duncan for the help. Sorry to be dense, but I'm still
unsure how to interrupt such processes. Here's an example:
for (i in 1:10){
a <- matrix(rnorm(10*10),ncol=10)
b <- svd(a) }
If you
[Though I'm not using a Mac, OS X is a Unix variant and should
have the commands used below installed]
Did you *literally* do
kill -s INT
without substituting the R PID for " Hi all,
>
> Thanks Simon and Duncan for the help. Sorry to be dense, but I'm still
> unsure how to interrupt such proce
Peter -
While the message hasn't been shown in more recent versions
of R, older (< 2.9) versions of R used to print the following:
library(eda)
Warning message:
package 'eda' has been merged into 'stats'
So I would guess the functions you're looking for are now automatically
loaded when you
Hi,
Urgent help- I have not been using R and statistics in my research for a
long time, but still remember some concept. I would like to have a sample
code for Manova analysis of Split-plot experiment. Could someone please post
a sample code and a short input sample as well?
Thank you so much!
I am using RGui version 2.10.1 (2009-12-14) for Windows. When I enter the call
library(eda)
the following message ensues.
Error in library(eda) : there is no package called 'eda'
I thought that eda was a standard library for exploratory data analysis.
However I could not find it in the l
Hi all,
Thanks Simon and Duncan for the help. Sorry to be dense, but I'm still
unsure how to interrupt such processes. Here's an example:
for (i in 1:10){
a <- matrix(rnorm(10*10),ncol=10)
b <- svd(a) }
If you run this, R will hang (i.e., it's a legitimate exe
Hello All,
My question is not directly related to R but rather on which statistical
method I should look in to for capturing the entropy of a data-set as a
number. In this figure http://www.twitpic.com/18sob5 are two data sets blue
and green (x-axis is time) that fluctuate between (-1,+1). Clearly
Patrick,
Thanks. I tried colnames, but it doesn't work. Seems more transformation
is needed. But now I got names, that's good enough.
Best.
Xumin
Patrick Burns
03/15/2010 04:04 PM
To
Xumin Zeng
cc
Subject
Re: [R] assign colnames to data
Those are names, not colnames.
See the 'Mo
I would have to agree with Mike Miller. As a novice to both R and Linux I
choose to use Ubuntu.
The substantial amount of help guides and forums really made the transition
easier and will save
some frustration. Once you get used to linux you can always try a
different distribution later, if you
Thanks, it works.
Xumin
Henrique Dallazuanna
03/15/2010 03:57 PM
To
Xumin Zeng
cc
r-help@r-project.org
Subject
Re: [R] assign colnames to data
Try:
names(a) <- b
On Mon, Mar 15, 2010 at 4:55 PM, Xumin Zeng wrote:
> Hi,
>
> Do you know how to assign colnames from one list to anoth
Try:
names(a) <- b
On Mon, Mar 15, 2010 at 4:55 PM, Xumin Zeng wrote:
> Hi,
>
> Do you know how to assign colnames from one list to another, for example.
> a=c(1,2,3)
> b=c("A","B","C")
>
> how can I get the dataset
>
> A B C
> 1 2 3
>
> where A, B and C are colnames. Thanks.
>
> Xumin
>
>
Hi,
Do you know how to assign colnames from one list to another, for example.
a=c(1,2,3)
b=c("A","B","C")
how can I get the dataset
A B C
1 2 3
where A, B and C are colnames. Thanks.
Xumin
[[alternative HTML version deleted]]
__
R-help@r-p
Hi,
How to fit data to cumulative normal distribution?
I tried such way:
library(MASS)
ed<-c(1:10)
cnd<-function(mn,sdd){pnorm(c(1:10),mn,sdd)}
fitdistr(ed,cnd,start=list(mn=mean(ed),sdd=sd(ed)))
.but an error occured:
Error in solve.default(res$hessian) :
function Lapack 'dgesv': system are
Hi,
How to fit data to cumulative normal distribution?
I tried such way:
library(MASS)
ed<-c(1:10)
cnd<-function(mn,sdd){pnorm(c(1:10),mn,sdd)}
fitdistr(ed,cnd,start=list(mn=mean(ed),sdd=sd(ed)))
.but an error occured:
Error in solve.default(res$hessian) :
function Lapack 'dgesv': system are
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and provide commented, minimal
On Sun, 14 Mar 2010, Jonathan Baron wrote:
Just to make this thoroughly confusing, I will say that I am very happy
with Fedora
Just to make this less confusing: choose Ubuntu. I say this because it is
easy to use, has great repositories and it is the most popular Linux
distro, so it should
Luke,
Thanks for your previous advice on using misc3d; I've been able to get a good
start with it. Most of my colleagues use Tecplot for graphing and are
wondering if I can make "cut-aways" using R. An example is attached. The idea
is show a 3D isosurface of one property together with a 2D c
There is a new FAQ #13 in the zoo-faq vignette in the development
version of the zoo package which illustrates several approaches to
this (all of which work in the current version of zoo as well). See:
http://pages.citebite.com/l2m2b3i4k5fnv
On Mon, Mar 15, 2010 at 1:02 PM, Joe Calderon wrote:
On Mar 15, 2010, at 14:42 , Adam D. I. Kramer wrote:
+1--this is the single most-annoying issue with R that I know of.
My usual solution, after accomplishing nothing as R spins idly for a
couple
hours, is to kill the process and lose any un-saved work.
save.history() is
my friend, but is
try this:
> x <- data.frame(day=rep(1:10, each=4), site=rep(sample(101:104, 10, TRUE),
each=4))
> s.f <- function(start){
+ start <- start[1] + 0:3 # generate the sequence
+ ifelse(start > 104, start - 4, start)
+ }
> x$siteNew <- ave(x$site, x$day, FUN=s.f)
> x
day site siteNew
11
a hah,
that works :)
simple but sweet,
thanks,
Rob
On Mon, Mar 15, 2010 at 1:59 PM, Henrique Dallazuanna wrote:
> Try this:
>
> do.call(rbind, lapply(list(list1, list2), as.data.frame))
>
> On Mon, Mar 15, 2010 at 3:42 PM, Rob Forler wrote:
> > Hi,
> >
> > This has bugged me for a bit. First
Using the maptools function "map2poly" I have created a map/polylist object
- a map of the Great Lakes. My goal is to passively plot additional data on
this map. Unfortunately I am not able to change (distort) the relative scale
of the axes for the map, and so the sample points do not line up corre
On 15/03/2010 2:42 PM, Adam D. I. Kramer wrote:
+1--this is the single most-annoying issue with R that I know of.
My usual solution, after accomplishing nothing as R spins idly for a couple
hours, is to kill the process and lose any un-saved work. save.history() is
my friend, but is a big delay
Arnaud -
A reproducible example would be nice, but something
like this might work, assuming your data is in a file
called 'traj.txt':
dat = readLines('traj.txt')
triallines = grep('trial',dat)
starts = triallines + 2
ends = c(triallines[-1] - 1,length(dat))
thetrials = sub('# *trial *(\\d+)
Try this:
do.call(rbind, lapply(list(list1, list2), as.data.frame))
On Mon, Mar 15, 2010 at 3:42 PM, Rob Forler wrote:
> Hi,
>
> This has bugged me for a bit. First question is how to keep classes with
> rbind, and second question is how to properly return vecotrs instead of
> lists after turnin
+1--this is the single most-annoying issue with R that I know of.
My usual solution, after accomplishing nothing as R spins idly for a couple
hours, is to kill the process and lose any un-saved work. save.history() is
my friend, but is a big delay when you work with big data sets as I do, so I
d
Hi,
This has bugged me for a bit. First question is how to keep classes with
rbind, and second question is how to properly return vecotrs instead of
lists after turning an rbind of lists into a data.frame
list1=list(a=2, b=as.Date("20090102", format="%Y%m%d"))
list2=list(a=2, b=as.Date("20090102"
How can I eliminate the border drawn by default around a wireframe plot? I've
tried using border=NA and box=FALSE to no avail.
Scott Waichler
Pacific Northwest National Laboratory
scott.waich...@pnl.gov
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https://s
Hi,
I'm trying to read some trajectory files (text files) which have the form:
# trial n
# t X Y
0 1 2
0.2 1 3
0.41.2 4
...
# trial n+1
# t X Y
0 1 2
0.2 1.3 3.3
0.4 1.5 5
...
...
where the symbol # means that the
Which in turn reminds me of Box & Tiao's line
"Since small differences in probability cannot be appreciated by the human
mind, there seems little point in being excessively precise about
uncertainty."
Box, G. E. P. & Tiao, G. C. (1973), Bayesian inference in statistical
analysis, Addison-Wesle
Dear R-help members,
I have a question regarding how to use varComb function to specify a
variance function for the "weights" in the gls. I need to fit a
linear model with heteroscedasticity. The variance function is
exp(c0+nu0*W +nu1*W^2) where W is a covariate. Initially I want to use
varFu
Thanks for the example, but I'm still not sure from this example how to see
the pairwise comparisons for the interaction. For example, if I have two
factors, X and Y; and X has 2 levels, A and B, and Y has 3 levels, 1, 2, and
3, a TukeyHSD would give the following comparisons with p-values for eac
Normally the command to create the device allows you to specify parameters
like width and height. pdf() has width, height and paper arguments.
Other than that, I'm not certain what you mean by:
"without having
to manually tinker with it to show everything in terms of tick marks and x/y
lims that y
Hi all,
I have been struggling with this one. When creating graphic devices, how do
you go about resizing the output device window automatically without having
to manually tinker with it to show everything in terms of tick marks and x/y
lims that you specify?
I have tried the aspect="" function,
On 3/15/2010 1:37 PM, jlu...@ria.buffalo.edu wrote:
> What is an easy way to stack a matrix multiple times? E.g. I have a 6x6
> matrix that I need to stack vertically 154 times to get a 6*154 by 6
> matrix. I would rather not rbind(X,X,...,X) matrices.--Joe
X <- matrix(runif(36), ncol=6)
On Mar 15, 2010, at 12:21 PM, Ted Harding wrote:
> On 15-Mar-10 16:22:13, Marc Schwartz wrote:
>> Hi all,
>> I thought that readers of R-Help might find the following article at
>> ScienceNews of interest:
>>
>> Odds Are, It's Wrong
>> Science fails to face the shortcomings of statistics
>> By
Greetings Everyone -
I have a data frame "x" that looks like this:
v1 v2
1 A
1 B
1 B
2 B
2 W
2 W
3 D
3 D
3 Z
What I would like to do is create a new data frame, "y", that has one row
for each unique value of v1, and returns the corresponding mode of v2. If
Hi all.
In a GLM in which g(mu) = b0 + b1X1 + b2X2 + b3X3 + b4X4 + b5X5 + b6X6 +
b7X7, if I want to test if b1 + b5 = b2 + b6, I can use the contrast package or
multicomp package. How can I do a similar test if I am fitting a GAMLSS using
the gamlss package? Thank you for your help. Gustavo
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Uwe Dippel
> Sent: Monday, March 15, 2010 8:27 AM
> To: Dennis Murphy
> Cc: r-help@r-project.org
> Subject: Re: [R] Frequencies from a matrix - spider from frequencies
>
> Denni
how about
y = X[rep(1:nrow(X), 6), ]
?
On Mon, Mar 15, 2010 at 5:37 PM, wrote:
> What is an easy way to stack a matrix multiple times? E.g. I have a 6x6
> matrix that I need to stack vertically 154 times to get a 6*154 by 6
> matrix. I would rather not rbind(X,X,...,X) matrices. --Joe
>
What is an easy way to stack a matrix multiple times? E.g. I have a 6x6
matrix that I need to stack vertically 154 times to get a 6*154 by 6
matrix. I would rather not rbind(X,X,...,X) matrices.--Joe
[[alternative HTML version deleted]]
On 15-Mar-10 16:22:13, Marc Schwartz wrote:
> Hi all,
> I thought that readers of R-Help might find the following article at
> ScienceNews of interest:
>
> Odds Are, It's Wrong
> Science fails to face the shortcomings of statistics
> By Tom Siegfried
> March 27th, 2010; Vol.177 #7 (p. 26)
Try this:
apply(m, 2, tapply, part, mean)
On Mon, Mar 15, 2010 at 2:10 PM, Christophe Genolini
wrote:
> Hi the list,
>
> As it is say in its doc, the aggregate function remove empty subsets. Is it
> possible to NOT remove empty subset ?
> --- 8< ---
> m <- matrix(1:12,4)
> part <- factor(c("
Try this:
x
V1 V2
1 2010-03-01 9
2 2010-03-03 17
3 2010-03-04 2
4 2010-03-05 9
5 2010-03-07 3
rng <- range(as.Date(x$V1))
with(merge(data.frame(V1 = seq(rng[1], rng[2], by = 'day')),
x, all = TRUE), aggregate(V2, list(V1), FUN = sum, na.rm = TRUE))
On Mon, Mar 15, 2010 at 2
Hi the list,
As it is say in its doc, the aggregate function remove empty subsets. Is
it possible to NOT remove empty subset ?
--- 8< ---
m <- matrix(1:12,4)
part <- factor(c("A","B","A","B"),levels=c("A","B","C"))
aggregate(m,list(part),mean)
### I get:
# Group.1 V1 V2 V3
# 1 A 2
hello *, im new to the list (and R in general), i have a problem that
im hoping someone can help me solve. i have data that i want to turn
into a time series per day,
ex.
2010-03-01 9
2010-03-03 17
2010-03-04 2
2010-03-05 9
2010-03-07 3
is there an easy way to fill in the gaps for the m
The problem has been cope after I copy a new *.mdb file, just wondering if it
will be happened again beyond future... :confused:
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Hi!
That should do it:
yourtime$min+yourtime$hour*60
In case your object is of class POSIXlt. Otherwise, convert it with
as.POSIXlt first.
Miguel
On Mon, Mar 15, 2010 at 3:57 PM, Carlos Nader wrote:
> Hi there!
>
> I have some data in POSIXlt format:
>
> 2009-07-18 5:53:00
> 2008-11-23 7:27:0
Hi there!
I have some data in POSIXlt format:
2009-07-18 5:53:00
2008-11-23 7:27:00
2008-11-24 5:25:00
and would like to extract information about only the minutes of the day,
like:
5:53 --> 353 minutes
7:27 --> 447 minutes
can you help me?
Carlos Nader
[[alternative HTML version del
Hi all,
I thought that readers of R-Help might find the following article at
ScienceNews of interest:
Odds Are, It's Wrong
Science fails to face the shortcomings of statistics
By Tom Siegfried
March 27th, 2010; Vol.177 #7 (p. 26)
http://www.sciencenews.org/view/feature/id/57091/title/O
Yeah, that sounds inefficient to me also. I think you'd be better off using
multidimensional arrays instead of lists, since all your values are numeric.
See ?array.
Miguel
2010/3/15 Márcio Resende
>
> Hello R-helpers,
> I have the following code that works well,
>
> b <-list()
> for (i in 1:3)
Hi,
I was trying to import data from MS Access while face some capacity problem.
There was only 320 rows sqlFetch into R even though I write max equal to 0:
>sqlFetch(channel, tablenames='Sample', max=0)
When I try sqlFetchMore there was only shown -1. May I know if there gotta
better way t
On Mon, 15 Mar 2010, ? wrote:
Dear all,
I need to fit a set of empirical data to cumulative normal distribution to
find the mean and sd of theoretical distribution. But I assume that my data
set describes only part of PDF, for example, only half of theoretical
distribu
Dear R users,
Due to too many children in my clustering result, I would like to prune
the tree-like hclust object into a certain groups. However, an error:
> clip.clust: no data provided for hclust object
always shows up.
Firstly, I tried the example in the maptree package, and it worked wel
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Márcio Resende
> Sent: Monday, March 15, 2010 7:45 AM
> To: r-help@r-project.org
> Subject: [R] storing matrix(variables) in loop
>
>
> Hello R-helpers,
> I have the following c
Jim Lemon wrote:
Hi Uwe,
Here's one way to get your spider plot:
ld1<-matrix(sample(1:5,310,TRUE),nrow=31)
ld2<-apply(ld1,2,table)
radial.plot(ld2,line.col=2:6,rp.type="p",
radial.pos=seq(0,9*pi/5,by=pi/5),
labels=paste("Q",1:10,sep=""),start=pi/2,
clockwise=TRUE,main="Frequency of respons
Dear Dwight,
The tcltk package *is* part of the standard R distribution. It is Tcl/Tk
itself for X11 that you needed to install. I think that it too is part of
the standard R distribution and am not sure why wasn't on your system. I'm
copying this reply to Rob Goedman, who is much more knowledgeab
Just in case...
b=array(NA,c(3,3,3,4))# that means b[matrix-row,matrix-col,i,j]
for (i in 1:3){
for (j in 1:4){
b[,,i,j]=matrix(runif(1),3,3)
}
}
b
(I think there are better ways to do this anyway...)
Miguel
[[alternative HTML version deleted]]
__
If you could describe exactly what is it that you're trying to
accomplish, we could be of better help (the reason I say this is
because the way you're trying to implement things is a bit
inefficient).
Anyways, you can't use two indices with a list.
One approach would be to nest lists, and you'd g
quick and dirty, use 'paste'
> b <- list()
> for (i in 1:3){
+ for (j in 1:4){
+ a <- matrix(runif(1),3,3)
+ b[[paste(i,j)]] <- a #but this doesn´t work
+ }
+ }
> b
$`1 1`
[,1] [,2] [,3]
[1,] 0.2059746 0.2059746 0.2059746
[2,] 0.2059746 0.2059746 0.2059746
[3,] 0.2059746 0.2059
Hello R-helpers,
I have the following code that works well,
b <-list()
for (i in 1:3){
a <- matrix(runif(1),3,3)
b[[i]] <- a
}
b
however, I need to do something similar with two loops and I was looking for
something that would look like
b <- list()
for (i in 1:3){
for (j in 1:4){
a <- matrix(r
Dear Gabor,
require(sqldf)
file(description="http://n4.nabble.com/file/n1593282/test_sql_psd.txt";,
open="")
file(description="http://n4.nabble.com/file/n1593282/test_sql_tsf.txt";,
open="")
test_sql_psd <-
read.table(file="http://n4.nabble.com/file/n1593282/test_sql_psd.txt";,
header=TRUE, se
> "JL" == Jim Lemon
> on Mon, 15 Mar 2010 17:53:40 +1100 writes:
JL> On 03/15/2010 03:12 AM, ElManuelito wrote:
>> I'm open to any suggestions and improvements...
>> ...
>> #plot.loglog(f,S,type="o",col=4,pch="",xaxs="i",yaxs="i");
>>
JL> Hi ElManuelito, The
Thanks very much, John. Installing that tcltk package is all that is required.
It would be nice to make this a part of the download of 2.10.1 as it is wasting
a significant amount of time for R Commander users on the Mac.
Dwight
-Original Message-
From: John Fox [mailto:j...@mcmaster.c
Please see the maiz example in ?MMC in the HH package.
maiz is the last example in the help file. Keep going all the way to the
end of
the help file. See also the
demo("MMC.WoodEnergy-aov", "HH")
These examples show how to use glht in the presence of interactions and
covariates.
Rich
Sorry, I missed the [,4] :
aggregate(datjan[,4],by=list(datjan[,4]),sum)
Miguel
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