Hi! That should do it: yourtime$min+yourtime$hour*60
In case your object is of class POSIXlt. Otherwise, convert it with as.POSIXlt first. Miguel On Mon, Mar 15, 2010 at 3:57 PM, Carlos Nader <tamanduabande...@gmail.com>wrote: > Hi there! > > I have some data in POSIXlt format: > > 2009-07-18 5:53:00 > 2008-11-23 7:27:00 > 2008-11-24 5:25:00 > > and would like to extract information about only the minutes of the day, > like: > > 5:53 --> 353 minutes > 7:27 --> 447 minutes > > can you help me? > > Carlos Nader > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
