If you could describe exactly what is it that you're trying to
accomplish, we could be of better help (the reason I say this is
because the way you're trying to implement things is a bit
inefficient).
Anyways, you can't use two indices with a list.
One approach would be to nest lists, and you'd get to extract elements
using calls like b[[i]][[j]]. The example below shows an example, but
it can be greatly improved depending on your specific scenario
f <- function(.x) lapply(1:4, function(.x) matrix(runif(1), 3, 3))
b <- lapply(1:3, f)
b[[1]][[2]]
--benilton
2010/3/15 Márcio Resende <mresende...@yahoo.com.br>:
>
> Hello R-helpers,
> I have the following code that works well,
>
> b <-list()
> for (i in 1:3){
> a <- matrix(runif(1),3,3)
> b[[i]] <- a
> }
> b
>
> however, I need to do something similar with two loops and I was looking for
> something that would look like
>
> b <- list()
> for (i in 1:3){
> for (j in 1:4){
> a <- matrix(runif(1),3,3)
> b[[i,j]] <- a #but this doesn´t work
> }
> }
>
> Anyway, I wanted "b" to loop like
> [[i=1, j=1]] [[i=1, j=2]] (...)
> a[i=1, j=1] a[i=1,j=2] (...)
>
> [[i = 2, j=1]] (...)
> a[i = 2, j = 1] (...)
>
> (...)
>
> Can anybody help me?
> Thanks
>
> --
> View this message in context:
> http://n4.nabble.com/storing-matrix-variables-in-loop-tp1593461p1593461.html
> Sent from the R help mailing list archive at Nabble.com.
>
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>
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