This happened with older versions of R but its fixed in the more
recent R 2.6.0 versions.
On 10/1/07, Edna Bell <[EMAIL PROTECTED]> wrote:
> Hi again.
>
> I'm sure that this is really simple.
>
> I'm trying to build a package on a Windows Vista machine. I use
> Rcmd build --binary test
>
> but I
Hi again.
I'm sure that this is really simple.
I'm trying to build a package on a Windows Vista machine. I use
Rcmd build --binary test
but I get the "Please set TMPDIR to a valid temporary directory"
I tried TMPDIR=c:\temp
but to no avail.
Please help.
thanks
__
Dear Ben Bolker, Hadley Wickham, Jim Lemon and all
I'm very thank to you!
I tried all suggestion and I wiil comments it next.
Ben Bolker suggestion is very nice and I did a little changes in
col=c(1,1),pch=c(1,16) and I include a xlab, ylab and a legend(5, 4,
c("02H02","306"), pch = c(1,16), co
I am having a couple of problems someone may be able to cast some light on.
Question 1:
I am making a logistic model but when i do this:
glm.model = glm(as.factor(form$finished) ~ ., family=binomial,
data=form[1:15,])
I get this:
Error in model.frame(formula, rownames, variables, varname
Dear R Gurus;
Is there a simple way to convert a Linux produced tar.gz file (a
package) to a Windows binary zip package, please?
Thanks in advance
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the post
Hi Michael,
This type of thing is pretty simple to do in R (take a look at ?plot
and then ?par - very useful... necessary actually... for graphing).
One way to do it is to use the "axis" function:
my.labels <- c("a","b","c","d","e","f","g","h","i","j")
plot(1:10,rnorm(10),axes=F,ylab="whatev",xl
Try ordering the factors:
x <- read.table(textConnection("SemType, Length
GeoLocation, Sentence
GeneralInfo, Paragraphs
GeneralInfo, Paragraphs
GeneralInfo, Sentence
GeneralInfo, Paragraphs
NatLang, Phrase
Advice, Article
GeneralInfo, Article
Advice, Article
Resource, Sentence"), header=TRUE)
# o
jack,
i had a similar problem with Oracle at work. i don't have
access to my yahoo email account at work but i'll take a stab at
directing you to the solution here and now FWIW.
open Data Sources then click on the System DSN (i think?)
tab. highlight Oracle 10g and hit configure. there's a
defaul
Hi,
I am new to R.
I have a bit of data looking like this:
SemType, Length
GeoLocation, Sentence
GeneralInfo, Paragraphs
GeneralInfo, Paragraphs
GeneralInfo, Sentence
GeneralInfo, Paragraphs
NatLang, Phrase
Advice, Article
GeneralInfo
Advice, Article
Resource, Sentence
...
(roughly 40,000 lin
No, it's a little more complex. I do not want to interpolate var2 as a
function of time. I want interpolate var2 as a function of var1, but in
an iterative chronological sequence that does require matching times
first. So the two var1 values for the interpolation are chosen such that
var1 times
Hi - I think this is a classic question. I'm using fCalendar time series. I
have observations that have multiple instances at second level. Is there anyway
to handle this in R? I can inject millisecond unit arbitrarily inside there but
I don't feel it's a correct way to do. Any ideas would be re
Thanks for the help. I looked into it further and noticed that the src/RGtk2
directory was actually a symlink. The perl find() does not follow symlinks,
as invoked, but tar, as invoked, does. Thus, when the tar/untar effectively
copies the files, there is a mismatch with the exclude paths.
Is ther
On 2/10/2007, at 12:52 AM, Duncan Murdoch wrote:
> On 10/1/2007 8:39 AM, Megh Dal wrote:
>> Hi, Can anyone give me a good explanation about what is the
>> difference between Stochastic Process and Time Series? In my
>> knowledge Time series process is one type of Stochastic process.
>> Am I
This is confusing.
try this.
number.runs <- 1
if (number.runs == 1) run.number <- 1
if (number.runs > 1) {
for (i in 1:number.runs) {
print(i)
}
}
perhaps the easiest way to print 1 and then 1 2 would be
for (i in 1:number.runs) {
print(i)
}
but i'm not sure that is what you want.
i
Hi all,
This question involves using a "for" loop to make a "decision" in a script.
I've written a rather intricate script, and near the start of it, I
want it either to do a loop (if a variable called "number.runs" > 1)
or not do a loop (if "number.runs" is 1). This is probably trivial but
I can
see ?toupper
On 10/2/07, Michael Sun <[EMAIL PROTECTED]> wrote:
> Dear list,
>
> x <- c("year","date","time","starting price","end price","max","min")
>
> how can I change all these lower-case letter to capital letter?
>
> how can I use sub or gsub function???
>
> sub("year","YEAR",x)
> will only
Dear list,
x <- c("year","date","time","starting price","end price","max","min")
how can I change all these lower-case letter to capital letter?
how can I use sub or gsub function???
sub("year","YEAR",x)
will only change one each time...
Appreciate for any helps
Cheers
mam
[[alterna
On 2007-October-01 , at 23:13 , jiho wrote:
> [...]
> The end result looks like this:
> http://cbetm.univ-perp.fr/irisson/svn/
> to see what an inner view looks like:
> http://cbetm.univ-perp.fr/irisson/svn/distribution_data/tetiaroa/
> trunk/data/?rev=0&sc=1
> You can play around wi
First a quick summary of the beginning of an interesting discussion
(not all indented correctly but in the correct order at least):
> From: "Gabor Grothendieck" <[EMAIL PROTECTED]>
> On 9/30/07, hadley wickham <[EMAIL PROTECTED]> wrote:
>> On 9/30/07, jiho <[EMAIL PROTECTED]> wrote:
>>> [...]
>>
Isn't the message rather clear? You need to edit the package sources and
replace malloc.h by stdlib.h (or remove the former if the latter is
already there, as in this case).
And BTW, 'gcc-4.2.2' is unreleased, but imminent (as R 2.6.0 is).
On Mon, 1 Oct 2007, vittorio wrote:
> Under freebsd 6
Under freebsd 6.2-p7 i386, R 2.5.1,gcc-4.2.2 I'm unable to compile package
lpSolve because:
hpbsd# R CMD INSTALL lpSolve_5.5.8.tar.gz
* Installing to library '/usr/local/lib/R/library'
* Installing *source* package 'lpSolve' ...
** libs
cc -std=gnu99 -I/usr/local/lib/R/include -I/usr/local/lib/R/
It's a FAQ (7.22)
-thomas
On Mon, 1 Oct 2007, Samor Gandhi wrote:
> Hello,
> I am calling the following code with the loop! It makes 3 out graphs but
> empty! COuld you help me plase on that? Thank you in advance
>
> z1 <- dbConnect(MyData, "something", "A1", "A2")
> for (tt in c("x
On 10/1/2007 1:27 PM, Abu Naser wrote:
> Hi Duncan,
>
> Let me explain again about what I want to do.
>
> I have a three coordinates (x1,y1,z1),(x2,y2,z2), and (x3,y3,z3). I want to
> use (x1,y1,z1)
> and (x2,y2,z2) for defining axis of rotation
Okay so far: the axis is (x1-x2, y1-y2, z1-z2)
You might find it easier to use the ggplot2 (http://had.co.nz/ggplot2) package:
install.packages("ggplot2")
library(ggplot2)
qplot(mpg, wt, data=mtcars, colour=factor(cyl))
# or
qplot(mpg, wt, data=mtcars, shape=factor(cyl))
ggplot2 takes care of mapping the variable values to colours and
sizes,
On Mon, 1 Oct 2007, Letticia Ramlal wrote:
> I am trying to plot a graph but the points on the graph should be
> different symbols and colors. It should represent what is in the legend.
> I tried using the points command but this does not work.
WHAT "does not work" ???
points() puts points on a
Perhaps
plot(mtcars$wt,mtcars$mpg,xlab= "Weight(lbs/1000)", ylab="Miles per
Gallon", pch=c(3,17,19), col=c("blue", "red", "purple4"))
On 01/10/2007, Letticia Ramlal <[EMAIL PROTECTED]> wrote:
>
> I am trying to plot a graph but the points on the graph should be
> different symbols and colors. I
Thanks for your answer, I will try to make myself clearer and do not
worry to point out what I've got wrong.
> There is some confusion in your query.
> First, how do you know that your data are indeed normally distributed?
In this specific case I *know* that my data is normally distributed
becaus
On Mon, 1 Oct 2007, Ranjan Bagchi wrote:
> I'm fairly new to R, coming from a programming background -- it's quite
> nice to work with dataframes, though, as opposed to explicit iteration.
>
> One thing I've found, which is surprising is that zero-length dataframes
> seem to cause errors:
It's no
I am trying to plot a graph but the points on the graph should be
different symbols and colors. It should represent what is in the legend.
I tried using the points command but this does not work. Is there
another command in R that would allow me to use different symbols and
colors for the points?
formulas have environments and since most model structures
include the formula the entire environment of the formula will be pulled in.
On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
> Why are you using eval and not:
>
> path <- paste( "C://Program Files//R//R-2.5.1//arima//",nn, sep="")
>
On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
> > These seem nearly identical to what you can get with R-Forge or with
> > TortoiseSVN (and likely other svn clients too). Since any developer
> > is likely to have an svn client a web interface more sophisticated than
> > what is already ava
Why are you using eval and not:
path <- paste( "C://Program Files//R//R-2.5.1//arima//",nn, sep="")
save(x, file = path)
?
It's possible that extra environments are getting saved. (Someone
with more knowledge of eval might suggest a better solution, but that
might be a good place to start)
Had
> These seem nearly identical to what you can get with R-Forge or with
> TortoiseSVN (and likely other svn clients too). Since any developer
> is likely to have an svn client a web interface more sophisticated than
> what is already available via the net has less utility than if this info were
> n
DEAR SIR
How can I use ts.plt() function for time series of unequal length?
Regards
--
AMINA SHAHZADI
Department of Statistics
GC University Lahore, Pakistan.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://
Dear Sir:
When I try to save large and very complex recursive objects with some
components containing models (such as the output from arima or lm ),
the resulting file sizes increase by 4 meg per save.
example directory:
amex8 meg
argentina 12 meg
australia 16 m
On Mon, 1 Oct 2007, Maura E Monville wrote:
> Now that I've loaded a file into an R data.frame and played with
> linear regression until I got a good model, my next step is clustering
> using the coefficients of the regression model (I have many files)
> Thanks to some R experts' guidelines I co
Hi Duncan,
Let me explain again about what I want to do.
I have a three coordinates (x1,y1,z1),(x2,y2,z2), and (x3,y3,z3). I want to use
(x1,y1,z1) and (x2,y2,z2) for defining axis of rotation and then calculate the
angle of rotation of a line from (x1,y1,z1) and (x3,y3,z3) around that axis o
Now that I've loaded a file into an R data.frame and played with
linear regression until I got a good model, my next step is clustering
using the coefficients of the regression model (I have many files)
Thanks to some R experts' guidelines I could find plenty of
documentation on regression analys
See ?ts.plot
Also ?plot.zoo and ?xyplot.zoo in the zoo package.
On 10/1/07, amna khan <[EMAIL PROTECTED]> wrote:
> Dear Sir
>
> I want to plot the two time series having unequal number of observations,
> say, one series having values from year 1960 to year 2000 and other having
> values from year
On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
> On 10/1/07, Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
> > On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
> > >
> > > The biggest drawback (to me) to both google code and R-forge, is their
> > > failure to offer a nice interface to b
Dear Sir
I want to plot the two time series having unequal number of observations,
say, one series having values from year 1960 to year 2000 and other having
values from year 1975 to year 2000. How to plot them on a single graph
sheet.
Regards
--
AMINA SHAHZADI
Department of Statistics
GC Univ
You were on the right track with the for loop, but often you can do
the same thing looplessly (I know, it's not really a word) in R:
If your data is like this:
data<-data.frame(ID=rep(letters[1:4], 5), size=runif(20))
then apply either
tapply(data$size, data$ID, mean)
or
aggregate(data$size
Thanks... that's very helpful. Sorry about the typo too
> t1 <- t[t$bob < 50, ,drop=F]
> t1
[1] bob
<0 rows> (or 0-length row.names)
> order(t$bob)
[1] 1
>
On Mon, 1 Oct 2007, Petr PIKAL wrote:
> Hi
>
> [EMAIL PROTECTED] napsal dne 01.10.2007 18:01:13:
>
>> I'm fairly new to R, coming from a pr
--- [EMAIL PROTECTED] wrote:
> Dear list,
> this must be an easy one:
>
> I have a data.frame of two columns, "ID" with four
> different levels (A
> to D) and numerical "size", and each of the 4
> different IDs is
> repeated a
> different number of times. I would like to get the
> mean size
On 10/1/2007 11:09 AM, Abu Naser wrote:
> Hi Duncan,
> Sorry, I forgot to mention. I meant (x1,y1,z1) and (x3,y3,z3).
I'm afraid I still don't understand what angle you are trying to calculate.
Duncan Murdoch
>
> With regards,
> Abu
>
> > Date: Mon, 1 Oc
Hi All,
I am trying to make a matrix with a particular value for all the elements
above and including diagonal and another particular value for all the
elements below diagonal. Obviously , Matrix function in Matrix package does
not work since it only allow filling by either row or column. So I am
Hi
It is preferable to echo your posts to r-help, you usually get more
answers and some definitelly superb to mine.
It is also better to start a new mail if your question has nothing to do
with original subject
"Maura E Monville" <[EMAIL PROTECTED]> napsal dne 01.10.2007
17:44:43:
> Unluckil
data <- data.frame(ID = rep(letters[1:4],5),size=rnorm(20,0,1))
aggregate(data$size, by = list(data$ID),mean)
<[EMAIL PROTECTED]
e.ehu.es>
Hi
[EMAIL PROTECTED] napsal dne 01.10.2007 18:01:13:
> I'm fairly new to R, coming from a programming background -- it's quite
> nice to work with dataframes, though, as opposed to explicit iteration.
>
> One thing I've found, which is surprising is that zero-length dataframes
> seem to cause
Dear R-listers,
I am working with generalized linear mixed models to quantify the
variance due to two nested random factors, but have hit a snag in the
interpretation of variance components. Despite my best efforts with
Venables & Ripley 2002, Fahrmeir & Tutz 2001, R-help archives, Google,
and ot
I'm fairly new to R, coming from a programming background -- it's quite
nice to work with dataframes, though, as opposed to explicit iteration.
One thing I've found, which is surprising is that zero-length dataframes
seem to cause errors:
> t <- data.frame(bob=c(100))
> order(t$bob)
[1] 1
> t1
Dear list,
this must be an easy one:
I have a data.frame of two columns, "ID" with four different levels (A
to D) and numerical "size", and each of the 4 different IDs is
repeated a
different number of times. I would like to get the mean size for each
ID as another data.frame. I have tried th
On 10/1/07, Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
> On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
> >
> > The biggest drawback (to me) to both google code and R-forge, is their
> > failure to offer a nice interface to browser the svn repository and
> > view the timeline of changes.
It may not be misleading, but does it really help you understand the
problem more than a scatterplot of rugosity vs. elevation would?
Hadley
On 10/1/07, Monica Pisica <[EMAIL PROTECTED]> wrote:
>
> Well,
>
> I agree that plots with multiple y-axes can be very confusing but i am
> not sure
Hi,
I have only recently started to use the R package and I was wondering how to
perform a multiple regression on a set of data were there is no intercept
and a condition that none of the coefficients can be less than zero.
I would appreciate if anybody could help!
Thanks
Ultan
--
View this me
Try this
plot.new()
plot.window(xlim=c(0,10), ylim=c(0,15))
rect(1,0,2,10)
rect(2,0,4,4.1,col="grey")
rect(2,4.1,4,10,col="grey")
segments(0, 0, 5, 0)
segments(0, 10, 5, 10)
text(3,3.5,"41")
text(3,6, "51")
text(4.5,3..5,"G/V")
text(4.5,6, "U")
Ju
maybe I didn't understand the problem, but you can do sth like
formula<-y~X1+X2+X3
lm(update.formula(formula,f(Y)~.))
maybe
?all.vars
or
?terms
will help you too.
hth.
Rebecca Sela schrieb:
> I am writing a program in which I would like to take in a formula, change the
> response (Y) variable
On Thu, 27 Sep 2007, David Koons wrote:
> I have a very general question about what the centering option in
> basehaz does to factors. (basehaz computes the baseline cumulative
> hazard for a coxph object using the Breslow estimator).
>
> Lets say I'm interested in a survival model with two (di
When I try to load the DCluster package I get the following error
message (R 2.5.1; PowerBook G4; Mac OS X 10.4.10)
(Load needed package)
Lade nötiges Paket: spdep
(error: package spdep could not been loaded)
Fehler: Paket 'spdep' konnte nicht geladen werden
(additional warning message)
Zusätzli
On 10/1/07, hadley wickham <[EMAIL PROTECTED]> wrote:
>
> The biggest drawback (to me) to both google code and R-forge, is their
> failure to offer a nice interface to browser the svn repository and
> view the timeline of changes. I particularly like trac (e.g.
> http://src.ggobi.org/) despite it'
For circles look at the symbols function. For ellipses see the ellipse package
and the my.symbols function in the TeachingDemos package.
-Original Message-
From: "Friedman, Steven" <[EMAIL PROTECTED]>
To: "r-help@r-project.org"
Sent: 10/1/07 7:10 AM
Subject: [R] Adding circles or ellips
Hi Duncan,
Sorry, I forgot to mention. I meant (x1,y1,z1) and (x3,y3,z3).
With regards,
Abu
> Date: Mon, 1 Oct 2007 10:48:12 -0400>
From: [EMAIL PROTECTED]> To: [EMAIL PROTECTED]> CC: r-help@r-project.org>
Subject: Re: [R] orientlib>> On 10/1/2007 9:44 A
Well,
I agree that plots with multiple y-axes can be very confusing but i am not
sure that always they are also misleading One time i was asked to make a 2
y-axes plot, one y axes was for elevation (heights in meters) and one for
rugosity (values between 1 and 2 - unitless). The ide
> >> It's something I have thought a little bit about, but I haven't made
> >> much progress. Ideally, if it's something that I do for ggplot2, I
> >> should do it for all my other R packages too.
>
> I don't see why doing it for *some* package(s) should entail
> doing it for all of the
Hi
> Did you try reading the help pages or looking at the examples in the
> help pages? Did you even make an attempt at using the command? If so,
> did you get an error or unexpected results?
>
> I don't know how you can expect people to help you when you appear to
> have made no effort yourself.
Rebecca,
you can keep formula as a character vector that can be easily manipulated
formula1 <- "Y~X1+X2+X3"
formula2 <- gsub("Y","newY",formula1)
lm(as.formula(formula1),data=mydata)
lm(as.formula(formula2),data=mydata)
best,
peter
On 10/1/07, Rebecca Sela <[EMAIL PROTECTED]> wrote:
>
> I am
Did you try reading the help pages or looking at the examples in the
help pages? Did you even make an attempt at using the command? If so,
did you get an error or unexpected results?
I don't know how you can expect people to help you when you appear to
have made no effort yourself.
On 10/1/07,
Hello James,
first I have to thank you for your help but there are some things I
don´t understand now.
I am not sur if I understand what this example gives me back:
ratings <- data.frame(id = c(1,2,3,4), att1 = c(1,1,0,1), att2 = c
(1,0,0,1), att3 = c(0,1,1,1))
ratings
id att1 att2 att3
On 10/1/2007 9:44 AM, Abu Naser wrote:
> Hi Duncan,
>
> Thanks for your replay.
> I am confused as I dont have the quaternion backgorund.
>
> Let me explain what I am trying to do:
> I have 3 coordinates in space (x1,y1,z1),(x2,y2,z2), and (x3,y3,z3) . Now, I
> use (x1,y1,z1) and (x2,y2,z2) to
The local maximum (x* = 0.106) found by the golden-section search does lie
in the interval [x_1, x_2]. So, it is consistent with the explanation on
the help page.
---
Ravi Varadhan, Ph.D.
Assistant Professor, The C
I may be misunderstanding, but my example seems to violate the "local
minimum inside [x_1,x_2] will be found as solution, even when f is
constant in there" rule since the search in my example continues on
towards +1.
On 1-Oct-07, at 10:40 AM, Ravi Varadhan wrote:
> Please read the help for
When you call xyplot in a for loop you have to use the print command. For
instance modifying the xyplot example:
The following wont work:
Depth <- equal.count(quakes$depth, number=8, overlap=.1)
for(i in 1:3){xyplot(lat ~ long | Depth, data = quakes)}
But this will:
for(i in 1:3){print(x
?write.csv
--- elyakhlifi mustapha <[EMAIL PROTECTED]>
wrote:
> Hello,
> I wanna know how to export a data frame to Excel.
> For example I wanna export this data frame
>
> > M[1:5,]
> var1 var2 distance
> 1 41 42 0.2
> 2 41 43 0.304347826086957
> 3 41 46 0.
Hello,
I am calling the following code with the loop! It makes 3 out graphs but
empty! COuld you help me plase on that? Thank you in advance
z1 <- dbConnect(MyData, "something", "A1", "A2")
for (tt in c("xyz", "abc", "m1")) {
message(paste("Here", tt, "!!!"))
mydata <- dbReadTable(z1, t
> "GaGr" == Gabor Grothendieck <[EMAIL PROTECTED]>
> on Sun, 30 Sep 2007 21:15:37 -0400 writes:
GaGr> On 9/30/07, hadley wickham <[EMAIL PROTECTED]> wrote:
>> On 9/30/07, jiho <[EMAIL PROTECTED]> wrote:
>> > On 2007-September-30 , at 22:40 , hadley wickham wrote:
>> >
Peter Dalgaard wrote:
> Kevin E. Thorpe wrote:
>> Dear List:
>>
>> I have a data frame prepared in the couting process style for including
>> a binary time-dependent covariate. The first few rows look like this.
>>
>> PtNo StartEnd Status Imp
>> 1 1 0 608.0 0 0
>> 2 2
Kevin E. Thorpe wrote:
> Dear List:
>
> I have a data frame prepared in the couting process style for including
> a binary time-dependent covariate. The first few rows look like this.
>
> PtNo StartEnd Status Imp
> 1 1 0 608.0 0 0
> 2 2 0 513.0 0 0
> 3
It does this via an exclude list which it uses to remove files from a
staged build. Printing out the exclude list (at ca line 232) should be
informative. One possibility is simply that there is a permissions issue
in deleting that directory.
On Sun, 30 Sep 2007, Michael Lawrence wrote:
> Hi,
Check out the function coxpath() in the package "glmpath". This is a better
approach than doing stepwise covariate selection.
Best,
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and Healt
Following on from your example:
write.table(M,file="Myfile.csv",sep=",",row.names=F)
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Yves Moisan
Sent: 01 October 2007 14:45
To: r-help@r-project.org
Subject: Re: [R] export csv
Hello,
I wanna know how
Hi Duncan,
Thanks for your replay.
I am confused as I dont have the quaternion backgorund.
Let me explain what I am trying to do:
I have 3 coordinates in space (x1,y1,z1),(x2,y2,z2), and (x3,y3,z3) . Now, I
use (x1,y1,z1) and (x2,y2,z2) to define axis of rotaion. Then, I wanted to use
3rd co
Hello,
I wanna know how to export a data frame to Excel.
For example I wanna export this data frame
> M[1:5,]
var1 var2 distance
1 41 42 0.2
2 41 43 0.304347826086957
3 41 46 0.19047619047619
4 41 47 0.156
5 41 48 0.209302325581395
I do
Please read the help for optimize() carefully. The following excerpted from
there should help explain your problem:
"The first evaluation of f is always at x_1 = a + (1-phi)(b-a) where (a,b) =
(lower, upper) and phi = (sqrt 5 - 1)/2 = 0.61803.. is the golden section
ratio. Almost always, the seco
Try this:
fo <- y ~ x
fo[[2]] <- as.name("z")
fo
On 10/1/07, Rebecca Sela <[EMAIL PROTECTED]> wrote:
> I am writing a program in which I would like to take in a formula, change the
> response (Y) variable into something else, and then pass the formula, with
> the new Y variable to another funct
Dear List:
I have a data frame prepared in the couting process style for including
a binary time-dependent covariate. The first few rows look like this.
PtNo StartEnd Status Imp
1 1 0 608.0 0 0
2 2 0 513.0 0 0
3 2 513 887.0 0 1
4 3
I am writing a program in which I would like to take in a formula, change the
response (Y) variable into something else, and then pass the formula, with the
new Y variable to another function. That is, I am starting with
formula <- Y~X1+X2+X3
and I'd like to do something like
Hello,
I wanna know how to export a data frame to Excel.
For example I wanna export this data frame
> M[1:5,]
var1 var2 distance
1 41 42 0.2
2 41 43 0.304347826086957
3 41 46 0.19047619047619
4 41 47 0.156
5 41 48 0.209302325581395
I don'
Marcelo Laia wrote:
> Hi,
>
> I have a data set like this:
>
> MutantRepTime OD
> 02H02100.029
> 02H02200.029
> 02H02300.023
> 02H02180.655
> 02H02280.615
> 02H02380.557
> 02H021121.776
> 02H0221
Hello,
I'm developing an ordination using metaMDS (package vegan). The analysis
identifies 3 distinct groups that I'd like to define by either adding
circles or ellipses to help identify the groups. The data set is a
spatial temporal data base depicting change in each of 4 areas over 3
time pe
John Sorkin wrote:
>
> Windows XP
> R 2.3.1
>
> I have a funciton
> fit1<-lm(y~x+z)
> Is there a function that will produce a 3-dimensional plot of y,x,z?
>
> I looked at the help files, but did not find a clean answer to my questio
>
Check out ?scatter3d in the Rcmdr package.
Ben Bolker
On 10/1/2007 8:47 AM, Bernd Stampfl wrote:
> ERRORLOG
>
> Just wanted to import a bulk of data into R via BLOOMBERG.
>
> And it crashed.
>
> Is there any useful "something" like an ERRORLOG?
>
> Checked the web but did not get useful information.
If by "crashed" you don't mean crashed, then t
On 10/1/2007 8:42 AM, Bos, Roger wrote:
> Rainer,
>
> This works: paste(x, sep="", collapse="")
>
> I would have thought this 'paste(x) would work, but it didn't.
>
> Perhaps someone else can tell us why we need collapse="". What would
> break if the default was collapse="" instead of collapse
We need both sep and collapse to deal with situations where we are
pasting two character vectors and also where we are pasting just one.
paste(c("T","i","o","s"), c("his ", "s ", "ne ",
"entence."),sep="",collapse="")
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
O
R-helpers,
n <- 100
arcoefs <- c(0.8)
macoefs <- c(-0.6)
p <- length(arcoefs)
q <- length(macoefs)
require(nlme)
tmp <- corARMA(value=c(arcoefs,macoefs), form=~1, p=p, q=q)
Sigma <- corMatrix(tmp, covariate = 1:n) # results in segfault
Have I used these commands in an improper way?
Thanks
Ben
_
Thanks a million
Rainer
[EMAIL PROTECTED] wrote:
> x <- c("This ", "is ", "one ", "sentence.")
> paste(x,collapse="")
>
>
>
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] Behalf Of Rainer M. Krug
> Sent: 01 October 2007 13:23
> To: r-help
> Subject: [R] Con
On 10/1/2007 8:39 AM, Megh Dal wrote:
> Hi, Can anyone give me a good explanation about what is the difference
> between Stochastic Process and Time Series? In my knowledge Time series
> process is one type of Stochastic process. Am I right? I need a further
> explanation.
You're partly right.
ERRORLOG
Just wanted to import a bulk of data into R via BLOOMBERG.
And it crashed.
Is there any useful "something" like an ERRORLOG?
Checked the web but did not get useful information.
Cheers, Bernd
--
View this message in context:
http://www.nabble.com/Errorlog-tf4548140.html#a12978580
S
Hello Jeff,
thanks a lot for your help. It seems to work well now.
Greetings
Birgit
Am 28.09.2007 um 20:33 schrieb Jeffrey Robert Spies:
> Hi Birgit,
>
> I've updated the recipe here, including a change to the
> dissimilarity function (making it more efficient):
>
> http://www.r-cookbook.com
Rainer,
This works: paste(x, sep="", collapse="")
I would have thought this 'paste(x) would work, but it didn't.
Perhaps someone else can tell us why we need collapse="". What would
break if the default was collapse="" instead of collapse=NULL?
Thanks,
Roger
-Original Message-
From:
Hi, Can anyone give me a good explanation about what is the difference between
Stochastic Process and Time Series? In my knowledge Time series process is one
type of Stochastic process. Am I right? I need a further explanation.
Thanks and regards,
-
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