On Wed, May 27, 2015 at 12:59:53AM -0700, Dave Yost wrote:
> OK, I can make it to work in bash if I say
> echodo a=b\\ c
> but then zsh tries to execute c. Can’t win.
>
> The problem is: how do I write this function so that it can be invoked
> identically in zsh and bash with identical results
OK, I can make it to work in bash if I say
echodo a=b\\ c
but then zsh tries to execute c. Can’t win.
The problem is: how do I write this function so that it can be invoked
identically in zsh and bash with identical results of setting a variable to a
value with a space in it?
> On 2015-05-26,
On Mon, May 25, 2015 at 12:33:53PM -0700, d...@yost.com wrote:
> # Echo the arguments, then execute them as a command.
> I can't find a way to implement echodo in bash.
set -x
your code
set +x
d...@yost.com writes:
> eval$@
You are expanding a shell parameter unquoted. Never do that unless you
know what you are doing.
eval "$@"
Andreas.
--
Andreas Schwab, SUSE Labs, sch...@suse.de
GPG Key fingerprint = 0196 BAD8 1CE9 1970 F4BE 1748 E4D4 88E3 0EEA B9D7
"And now for s
Dennis Williamson wrote:
I'm trying to put a command in a variable, but the complex cases always
fail! : http://mywiki.wooledge.org/BashFAQ/050
Eval command and security issues : http://mywiki.wooledge.org/BashFAQ/048
Dunno, but I see nothing on that page about using
printf -v "%q" or
I'm trying to put a command in a variable, but the complex cases always
fail! : http://mywiki.wooledge.org/BashFAQ/050
Eval command and security issues : http://mywiki.wooledge.org/BashFAQ/048
On Mon, May 25, 2015 at 2:33 PM, wrote:
> Configuration Information [Automatically generated, do not c
d...@yost.com wrote:
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-unknown-linux-gnu'
-DCONF_VENDOR='unknown' -DLO
On 25/05/15 20:33, d...@yost.com wrote:
> if [[ -n $ZSH_VERSION ]] ; then
> echo "[ ${(q)@} ]"
> eval${(q)@}
> else
> echo "[ $@ ]"
> eval$@
> fi
I believe the bash equivalent here would be something along the lines of:
quoted=$(printf '%q ' "$@")
quoted=${quoted% }
e
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-unknown-linux-gnu'
-DCONF_VENDOR='unknown' -DLOCALEDIR='/usr/local/bash/
