OK, I can make it to work in bash if I say echodo a=b\\ c but then zsh tries to execute c. Can’t win.
The problem is: how do I write this function so that it can be invoked identically in zsh and bash with identical results of setting a variable to a value with a space in it? > On 2015-05-26, at 1:04 AM, Andreas Schwab <sch...@suse.de> wrote: > > d...@yost.com writes: > >> eval $@ > > You are expanding a shell parameter unquoted. Never do that unless you > know what you are doing. > > eval "$@" > > Andreas. > > -- > Andreas Schwab, SUSE Labs, sch...@suse.de > GPG Key fingerprint = 0196 BAD8 1CE9 1970 F4BE 1748 E4D4 88E3 0EEA B9D7 > "And now for something completely different." On 2015-05-25, at 6:12 PM, Dennis Williamson <dennistwilliam...@gmail.com> wrote: > I'm trying to put a command in a variable, but the complex cases always fail! > : http://mywiki.wooledge.org/BashFAQ/050 > > Eval command and security issues : http://mywiki.wooledge.org/BashFAQ/048 > > On Mon, May 25, 2015 at 2:33 PM, <d...@yost.com> wrote: > Configuration Information [Automatically generated, do not change]: > Machine: x86_64 > OS: linux-gnu > Compiler: gcc > Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64' > -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-unknown-linux-gnu' > -DCONF_VENDOR='unknown' -DLOCALEDIR='/usr/local/bash/4.3.39/share/locale' > -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -I. -I../bash-4.3 > -I../bash-4.3/include -I../bash-4.3/lib -g -O2 > uname output: Linux s6.millcomputing.com 2.6.32-504.16.2.el6.x86_64 #1 SMP > Wed Apr 22 06:48:29 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux > Machine Type: x86_64-unknown-linux-gnu > > Bash Version: 4.3 > Patch Level: 39 > Release Status: release > > Description: > > # Echo the arguments, then execute them as a command. > function echodo() { > if [[ -n $ZSH_VERSION ]] ; then > echo "[ ${(q)@} ]" > eval ${(q)@} > else > echo "[ $@ ]" > eval $@ > fi > } > echodo echo b\ c > echodo a=b\ c > echo $a > > The result in zsh is: > $ echodo echo b\ c > [ echo b\ c ] > b c > $ echodo a=b\ c > [ a=b\ c ] > $ echo $a > b c > $ > > Bash gets an error: > $ echodo echo b\ c > [ echo b c ] > b c > $ echodo a=b\ c > [ a=b c ] > bash: c: command not found > $ echo $a > > $ > > I can't find a way to implement echodo in bash. Apparently this is because > bash is unable to expand a variable with quoting intact, as zsh can do with > its (q) expansion flag. > > Bash behaves differently in this case:: > > $ echodo export a=b\ c > [ export a=b c ] > $ echo $a > b > $ > > > Repeat-By: > > > > Fix: > > > > > -- > Visit serverfault.com to get your system administration questions answered. >
