On Wed, May 27, 2015 at 12:59:53AM -0700, Dave Yost wrote:
> OK, I can make it to work in bash if I say
> echodo a=b\\ c
> but then zsh tries to execute c. Can’t win.
>
> The problem is: how do I write this function so that it can be invoked
> identically in zsh and bash with identical results of setting a variable to a
> value with a space in it?
dualbus@hp ~ % for sh in bash zsh; do "$sh" -c 'echodo(){ echo "$*"; eval "$@";
}; echodo a=b\\ c; echo "$a"'; done
a=b\ c
b c
a=b\ c
b c
--
Eduardo Bustamante
https://dualbus.me/
