Dang! I love this list.
Looks like I haven't done a "man cal" for many years. I didn't know
about "ncal".. lol.
I remember there was a note in the old Version 7 manuals about reading
the man pages periodically..
Thanks Ken!
On Tue, Dec 22, 2015 at 10:59:18AM -0900, Ken Irving wrote:
> On Tu
On Tue, Dec 22, 2015 at 04:04:16AM +0100, Ángel González wrote:
> Bill Duncan wrote:
> > Remember that while there are 14 patterns of years, leap years don't
> > impact Friday the 13th for January/February..
> >
> > This isn't an exhaustive analysis, but a quick check for 300 years
> > didn't show
Am Tue, 22 Dec 2015 08:16:28 -0500
schrieb Greg Wooledge :
> On Tue, Dec 22, 2015 at 04:04:16AM +0100, Ángel González wrote:
> > Aren't you making things more complex than needed, with so much
> > pipes and awk?
> >
> > date(1) is your friend:
> >
> > For instance:
> > $ for y in {1900..2199} ;
2015-12-22 08:16:28 -0500, Greg Wooledge:
[...]
> t=946702800 # Start at Sat Jan 1 12:00:00 EST 2000
> endyear=2036
>
> while true; do
> printf -v year '%(%Y)T' "$t"
> ((year > endyear)) && break
> printf -v day '%(%d)T' "$t"
> printf -v dow '%(%w)T' "$t"
> if [[ $day = 13 && $dow =
On Tue, Dec 22, 2015 at 04:04:16AM +0100, Ángel González wrote:
> Aren't you making things more complex than needed, with so much pipes
> and awk?
>
> date(1) is your friend:
>
> For instance:
> $ for y in {1900..2199} ; do echo -n "$y "; for m in {1..12}; do date +%A -d
> $y-$m-13; done | grep
Bill Duncan wrote:
> Remember that while there are 14 patterns of years, leap years don't
> impact Friday the 13th for January/February..
>
> This isn't an exhaustive analysis, but a quick check for 300 years
> didn't show any years without a Friday 13th..
>
> ;-)
>
> $ for y in {1900..2199} ; d
Remember that while there are 14 patterns of years, leap years don't
impact Friday the 13th for January/February..
This isn't an exhaustive analysis, but a quick check for 300 years
didn't show any years without a Friday 13th..
;-)
$ for y in {1900..2199} ; do for m in {1..12};do cal $m $y|awk '
On Mon, Dec 21, 2015 at 02:59:20PM +, Allodoxaphobia wrote:
> Is the logic exhaustive ? -- in that it shows there
> are no years with *no* Friday The 13Th's?
The Gregorian calendar has 14 different year layouts: 7 non-leap-years
beginning with Sunday through Saturday, and 7 leap-years beginni
On Sun, 20 Dec 2015 23:59:32 -0500, Bill Duncan wrote:
> We had 3 this year..
>
> $ for y in {1950..2050} ; do for m in {1..12};do cal $m $y|awk
> 'FNR==1{m=$0}/^ 1/{print m}';done;done| awk '{a[$2]=a[$2]" "$1}END{for (i in
> a) print i,a[i]}'| sort| awk '{t=$1;$1="";a[$0]=a[$0]" "t}END{for (i in
Gee bit too much free time??? But it is interesting.
On Sun, Dec 20, 2015 at 10:59 PM, Bill Duncan wrote:
> We had 3 this year..
>
> $ for y in {1950..2050} ; do for m in {1..12};do cal $m $y|awk
> 'FNR==1{m=$0}/^ 1/{print m}';done;done| awk '{a[$2]=a[$2]" "$1}END{for (i
> in a) print i,a[i]}'|
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