On Sun, 20 Dec 2015 23:59:32 -0500, Bill Duncan wrote:
> We had 3 this year..
>
> $ for y in {1950..2050} ; do for m in {1..12};do cal $m $y|awk
> 'FNR==1{m=$0}/^ 1/{print m}';done;done| awk '{a[$2]=a[$2]" "$1}END{for (i in
> a) print i,a[i]}'| sort| awk '{t=$1;$1="";a[$0]=a[$0]" "t}END{for (i in a)
> printf "%-24s %s\n", i, a[i]}' | sort | cat -n
>
> 1 April July 1951 1962 1973 1979 1990 2001 2007 2018
> 2029 2035 2046
> 2 August 1954 1965 1971 1982 1993 1999 2010 2021
> 2027 2038 2049
> 3 February August 1976 2004 2032
> 4 February March November 1953 1959 1970 1981 1987 1998 2009 2015
> 2026 2037 2043
> 5 January April July 1956 1984 2012 2040
> 6 January October 1950 1961 1967 1978 1989 1995 2006 2017
> 2023 2034 2045
> 7 June 1952 1958 1969 1975 1980 1986 1997 2003
> 2008 2014 2025 2031 2036 2042
> 8 March November 1964 1992 2020 2048
> 9 May 1955 1960 1966 1977 1983 1988 1994 2005
> 2011 2016 2022 2033 2039 2044 2050
> 10 October 1972 2000 2028
> 11 September December 1957 1963 1968 1974 1985 1991 1996 2002
> 2013 2019 2024 2030 2041 2047
>
>
> Happy Holidays, Happy New Year in 2016 and thanks for being involved with
> such a great shell!
heh... The eyes boogle. :-)
Is the logic exhaustive ? -- in that it shows there
are no years with *no* Friday The 13Th's?
Holiday Cheer to you, as well!
Jonesy
--
Marvin L Jones | Marvin | W3DHJ.net | linux
38.238N 104.547W | @ jonz.net | Jonesy | FreeBSD
* Killfiling google & XXXXbanter.com: jonz.net/ng.htm
