Bill Duncan wrote:
> Remember that while there are 14 patterns of years, leap years don't
> impact Friday the 13th for January/February..
>
> This isn't an exhaustive analysis, but a quick check for 300 years
> didn't show any years without a Friday 13th..
>
> ;-)
>
> $ for y in {1900..2199} ; do for m in {1..12};do cal $m $y|awk
> 'FNR==1{m=$0}/^ 1/{print m}';done;done | awk '{y[$2]++} END {for
> (i=1900;i<2200;i++) if (!(i in y)) print i}'
> $
Aren't you making things more complex than needed, with so much pipes
and awk?
date(1) is your friend:
For instance:
$ for y in {1900..2199} ; do echo -n "$y "; for m in {1..12}; do date +%A -d
$y-$m-13; done | grep -c Friday ; done
shows there are between 1 and 3 Fridays per year.
Or a mere listing:
$ for y in {1900..2199} ; do for m in {1..12}; do date +%A -d $y-$m-13; done;
done | sort | uniq -c | sort -rn
That the most common weekday in these three centuries for the 13th is… you
guessed it, Friday.
Happy New Year to all of you, too. Although I plan to stay in 2015 for almost
10 days more! :-)
