Bret, This worked great, THANK YOU!!! Brett Bret, This worked great!! THANK YOU!!! Plus it's much faster vs Grepping twice (my way was slower) Brett
----- Original Message ----- From: "Bret Hughes" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Wednesday, October 01, 2003 3:05 PM Subject: Re: Viewing Text Output > On Wed, 2003-10-01 at 10:20, Brett Franck wrote: > > Hi, > > > > I am trying to view log files using GREP and variable substitution. Let's say a user wants to view a log file for "Sep 30" Here is the shell (BASH) script that I put together for it. > > > > #!/bin/sh > > cd /routerlogs > > echo > > date > > echo > > date=`date | cut -c5-7` > > echo "Which Date Do You Wish to Parse?:"; read dte; > > echo "Searching....." > > grep -e "$date $dte" *.log | grep -e WARNING > > > > grep -e "$date *$dte .*WARNING" *.log should get you close > > this says find a line that has whatever is in $date followed by zero or > more spaces followed by whatever is in $dte followed by a single space > followed by zero or more of any thing followed by WARNING > > I think :) > > Bret > > > > -- > redhat-list mailing list > unsubscribe mailto:[EMAIL PROTECTED] > https://www.redhat.com/mailman/listinfo/redhat-list > -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED] https://www.redhat.com/mailman/listinfo/redhat-list
